A square coil (length of side = 24 cm) of wire consisting of two turns is placed in a uniform magnetic field that makes an angle of 60° with the plane of the coil. If the magnitude of this field increases by 6.0 mT every 10 ms, what is the magnitude of the emf induced in the coil?

Answers

Answer 1

Answer:

Explanation:

It is given that,

Length of side of a square, l = 24 cm = 0.24 m

The uniform magnetic field makes an angle of 60° with the plane of the coil.

The magnetic field increases by 6.0 mT every 10 ms. We need to find the magnitude of the emf induced in the coil. The induced emf is given by :

$\epsilon=N(d\phi)/(dt)$

$(d\phi)/(dt)$ is the rate of change if magnetic flux.

$\phi=BA\ cos\theta$

$\theta$ is the angle between the magnetic field and the normal to area vector.

$\theta=90-60=30$

$\epsilon=NA(dB)/(dt)* cos30$

$\epsilon=2* (0.24\ m)^2* (6\ mT)/(10\ mT)* cos(30)$

$\epsilon=0.0598\ T$

$\epsilon=59.8\ mT$

EMF = 60 mT

So, the magnitude of emf induced in the coil is 60 mT. Hence, this is the required solution.

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What it the Zeeman effect and what does it tell us about the Sun?

Answers

Answer:

Explanation:

Zeeman Effect -

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On the sun , there is a strong magnetic field , and hence , can show Zeeman effect .

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A train of 150 m length is going toward north direction at a speed of 10 ms–1 and a parrot is flying towards south direction parallel to the railway track with a speed of 5 ms–1. The time taken by the parrot to cross the train is equal to.?

Answers

Answer:

10ms

Explanation:

The bird must travel the length of the train (150m), with a combined speed of 15m/s this means it will take 10s to cross an accumulated 150ms.

Answer:

The time taken by the parrot to cross the train is = 10 m/s

Explanation:

given:

A train of 150 m length is going toward north direction at a speed of 10 m/s

and a parrot is flying towards south direction parallel to the railway track with a speed of 5 m/s

find;

The time taken by the parrot to cross the train

using the distance over speed relation formula t = d / v

where:

v = velocity

d = distance

t = time

v = 10 m/s + 5 m/s = 15 m/s (combine velocity)

d = 150 m

t = ?

plugin values into the formula

t = 150

t = 10 m/s

therefore,

The time taken by the parrot to cross the train is = 10 m/s

A thin flashlight beam traveling in air strikes a glass plate at an angle of 52° with the plane of the surface of the plate. If the index of refraction of the glass is 1.4, what angle will the beam make with the normal in the glass?

Answers

To solve this problem it is necessary to apply Snell's law and thus be able to calculate the angle of refraction.

From Snell's law we know that

$n_1sin\theta_1 = n_2 sin\theta_2$

Where,

n_i = Refractive indices of each material

$\theta_1$ = Angle of incidence

$\theta_2$ = Refraction angle

Our values are given as,

$\theta_1 = 38\°$

$n_1 = 1$

$n_2 = 1.4$

Replacing

$1*sin38 = 1.4*sin\theta_2$

Re-arrange to find $\theta_2$

$\theta_2 = sin^(-1) (sin38)/(1.4)$

$\theta_2 = 26.088°$

Therefore the angle will the beam make with the normal in the glass is 26°

A boat can travel in still water at 56 m/s. If the boats sails directly across a river that flows at 126 m/s. What is the boats speed relative to the ground

Answers

Answer:

The answer is below

Explanation:

The speed of the boat in still water is perpendicular to the speed of the water flow. Therefore the speed relative to the ground (V), the speed of flow and the speed of the boat in still water form a right angled triangle. Hence the speed relative to the ground is given as:

V² = 56² + 126²

V² = 19012

V = 137.9 m/s

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Answers

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A golf ball is dropped from rest from a height of 9.50 m. It hits the pavement, then bounces back up, rising just 9.70 m before falling back down again. A boy catches the ball on the way down when it is 1.20 m above the pavement. Ignoring air resistance calculate the total amount of time the ball is in the air, from drop to catch?

Answers

The ball is in the air for 27.70m because
9.5+9.7=19.2...
9.7-1.2=8.5...
19.2+8.5=27.70...

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