Answer:
(a) 1.21 m/s
(b) 2303.33 J, 152.27 J
Explanation:
m1 = 95 kg, u1 = - 3.750 m/s, m2 = 113 kg, u2 = 5.38 m/s
(a) Let their velocity after striking is v.
By use of conservation of momentum
Momentum before collision = momentum after collision
m1 x u1 + m2 x u2 = (m1 + m2) x v
- 95 x 3.75 + 113 x 5.38 = (95 + 113) x v
v = ( - 356.25 + 607.94) / 208 = 1.21 m /s
(b) Kinetic energy before collision = 1/2 m1 x u1^2 + 1/2 m2 x u2^2
= 0.5 ( 95 x 3.750 x 3.750 + 113 x 5.38 x 5.38)
= 0.5 (1335.94 + 3270.7) = 2303.33 J
Kinetic energy after collision = 1/2 (m1 + m2) v^2
= 0.5 (95 + 113) x 1.21 x 1.21 = 152.27 J
Answer:
15 m/s
Explanation:
We know that where f = frequency & d = wavelength .
So here.
Wavelength = 5 m
Frequency = 3 s⁻¹
Hence Speed = 5 * 3 = 15 m/s
Answer:
4 kilometers
Explanation:
The length of a bus route in a small town can greatly depend on the specifics of the town and the route. It can range from a couple miles in a very small town to 20 miles or more for larger towns.
The length of a bus route across a small town can vary greatly depending on the size of the town and the specifics of the bus route. In a very small town, the bus route might only be a mile or two long. For larger towns, it could easily be 10-20 miles, or more. If you know the specifics of the route (streets it travels along, the number of stops, etc.), you could use a tool like Go_gle Maps to calculate an approximate distance.
#SPJ11
G = 6.67 x 10-11 Nm2/kg2
a. Calculate the value of the gravitational force between an electron (mass = 9.11 x 10-31 kg) and a proton (mass is 1836 times greater than the mass of an electron) if the two particles are separated by 3.602 nanometers. (1 nanometer or 1 nm = 1 x 10-9 m)
F= ______ N
b. The force created in the above question is:
1. repulsive
2. attractive
Answer:
a.
b.Attractive
Explanation:
We are given that
Mass of an electron,
Mass of proton,
Distance between electron and proton,R=
a.Substitute the values then we get
b.We know that like charges repel to each other and unlike charges attract to each other.
Proton and electron are unlike charges therefore, the force between proton and electron is attractive.
Answer:
h≅ 58 m
Explanation:
GIVEN:
mass of rocket M= 62,000 kg
fuel consumption rate = 150 kg/s
velocity of exhaust gases v= 6000 m/s
Now thrust = rate of fuel consumption×velocity of exhaust gases
=6000 × 150 = 900000 N
now to need calculate time t = amount of fuel consumed÷ rate
= 744/150= 4.96 sec
applying newton's law
M×a= thrust - Mg
62000 a=900000- 62000×9.8
acceleration a= 4.71 m/s^2
its height after 744 kg of its total fuel load has been consumed
h= 58.012 m
h≅ 58 m
Answer:
RMS voltage is 113.1370 V
frequency is 780.685 Hz
voltage is −158.66942 V
maximum current is 2.9739 A
Explanation:
Given data
∆V = 160.0 sin(495t) Volts
so Vmax = 160
and angular frequency = 495
time t = 1/106 s
resistor R = 53.8 Ω
to find out
RMS voltage and frequency of the source and voltage and maximum current
solution
we know voltage equation = Vmax sin ωt
here Vmax is 160 as given equation in question
so RMS will be Vmax / √2
RMS voltage = 160/ √2
RMS voltage is 113.1370 V
and frequency = angular frequency / 2π
so frequency = 497 / 2π
frequency is 780.685 Hz
voltage at time (1/106) s
V(t) = 160.0 sin(495/ 108)
voltage = −158.66942 V
so current from ohm law at resistor R 53.8 Ω
maximum current = voltage max / resistor
maximum current = 160 / 53.8
maximum current = 2.9739 A
The root-mean-square voltage of the AC source is 113.14 V, its frequency is 78.75 Hz, and the voltage at time t = 1/106 s is approximately 150.4 V. The current at this peak voltage, when connected to a resistor of 53.8 Ω, is approximately 2.97 A.
The output of an AC voltage source can be represented by the equation V = V₀ sin ωt, where V₀ is the peak voltage, ω is the angular frequency, and t is the time. In this case, V₀ = 160 V and ω = 495 (1/s). The root-mean-square voltage (Vrms), which is commonly used to express AC voltage, can be calculated from the peak voltage using the formula Vrms = V₀/√2 which gives approximately 113.14 V.
The frequency of the source is related to the angular frequency by the equation f = ω/2π, which gives a frequency of approximately 78.75 Hz. To find the voltage at a specific time t = 1/106 s, we substitute these values into the initial equation resulting in V = V₀ sin ωt = approximately 150.4 V.
Finally, the resistance R = 53.8 Ω allows us to calculate the maximum current in the circuit given by I = V/R. The maximum current occurs at the peak voltage, so I(max) = V₀/R = approximately 2.97 A.
#SPJ3
30 m
30 in
What is Greta's average velocity over the 240s period?
m/s
What is Greta's average speed over the 240s period?
m/s
Average velocity: 0 m/s. Average speed: 0.25 m/s. Greta returns to her starting point, so her displacement is 0m.
Greta's average velocity is 0 m/s because she ends up at the same point where she started. Her displacement is 0 meters, and since velocity is displacement divided by time, her average velocity is 0 / 240 = 0 m/s.
Her average speed, on the other hand, is calculated using the formula: Average Speed = TotalDistance / Total Time.
Initially, Greta walks 30 meters away from her truck, and then she returns 30 meters back to her starting point. So, the total distance she covers is 30 + 30 = 60 meters. Her total travel time is 240 seconds.
AverageSpeed = 60 meters / 240 seconds = 0.25 m/s.
In summary, Greta's average velocity is 0 m/s because her net displacement is 0 meters. Her average speed is 0.25 m/s because she covers a total distance of 60 meters in 240 seconds.
To learn more about Average velocity here
#SPJ3
Answer:
0 | for Velocity
.25 | for speed
Explanation: