Answer: the answer i for c is yes 0& 10
Explanation:
Answer:
Explanation:
given,
time taken to complete the each orbit = 144 minutes
t = 144 x 60 = 8640 s
mass of the earth = 5.98 x 10²⁴ Kg
radius of earth,R = 6.38 x 10⁶ m
Using Kepler's 3rd law
r = 9.1 x 10⁶ m
the altitude of the satellite
H = r - R
H = 9.1 x 10⁶ - 6.38 x 10⁶
H = 2.72 x 10⁶ m
Answer:
= 2630.6 N.m
Explanation:
(FR)x = ΣFx = -F4 = -407 N
(FR)y = ΣFy =-F1-F2 -F3 = -510 - 306 - 501 = -1317 N
(MR)B =ΣM + Σ(±Fd)
= MA + F1(d1 +d2) + F2d2 - F4d3
= 1504 + 510(0.880+1.11) +306(1.11) - 407(0.560)
= 2630.64 N.m (counterclockwise)
The Cartesian components of the resultant force and the couple moment are calculated by summing up all the forces and moments acting on the object. The resultant force is 1724 N and the couple moment is 29.764 N*m.
The resultant force and couple moment in the Cartesian coordinate system can be obtained by summing up all the forces and moments acting on the object. In this case, we have the forces F1, F2, F3, F4 and the couple moment MA acting on the object. The resultant force (FR) can be calculated as the sum of all the forces, i.e., FR = F1 + F2 + F3 + F4. Using the values given, FR = 510 N + 306 N + 501 N + 407 N = 1724 N. The resultant moment (MR) can be calculated as the sum of all the moments, i.e., MR = d1*F1 + d2*F2 + d3*F3 + d4*F4 - MA. Using the values given, MR = 0.880 m * 510 N + 1.11 m * 306 N + 0.560 m * 501 N + 2.08 m * 407 N - 1504 N*m = 29.764 N*m. Therefore, the Cartesian components of the resultant force and the couple moment are 1724 N and 29.764 N*m respectively.
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Answer: C = 1.319×10^-11 F
Explanation: The formulae that relates the capacitance of a capacitor to the area of the plates, distance between the plates and dielectric constant is given as
C = kε0A/d
Where C = capacitance of plates =?
k = dielectric constant = 2.0
Area of plates = 16.4cm² = 0.00164 m²
d = distance between plates = 2.2 mm = 0.0022m
By substituting the parameters, we have that
C = 2 × 8.85×10 ^-12 ×0.00164/ 0.0022
C = 0.029028 × 10^-12/ 0.0022
C = 13.19× 10^-12
C = 1.319×10^-11 F
Answer:
The highest of its trajectory = 0.45 m
Option C is the correct answer.
Explanation:
Considering vertical motion of cat:-
Initial velocity, u = 3.44 sin60 = 2.98 m/s
Acceleration , a = -9.81 m/s²
Final velocity, v = 0 m/s
We have equation of motion v² = u² + 2as
Substituting
v² = u² + 2as
0² = 2.98² + 2 x -9.81 x s
s = 0.45 m
The highest of its trajectory = 0.45 m
Option C is the correct answer.
(b) F/4,
(c) F,
(d) 2F,
(e) 4F,
(f) None of the above.
Answer:
F/2
Explanation:
In the first case, the two charges are Q1 and Q2 and the distance between them is r. K is the Coulomb's constant
Hence;
F= KQ1Q2/r^2 ------(1)
Where the charge on Q1 is doubled and the distance separating the charges is also doubled;
F= K2Q1 Q2/(2r)^2
F2= 2KQ1Q2/4r^2 ----(2)
F2= F/2
Comparing (1) and (2)
The magnitude of force acting on each of the two particles is;
F= F/2