Answer:
F0 / 81
Explanation:
Let the two charges by Q and q which are separated by d.
By use of coulomb's law
F0 = k Q q / d^2 ......(1)
Now the charges are decreased by factor of 9.
Q' = Q / 9
q' = q / 9 ......(2)
Now the Force is
F' = k Q' q' / d^2
F' = k (Q /9) (q / 9) / d^2
F' = k Q q / 81d^2
F' = F0 / 81
Answer:
The maximum height of the package is 140 m above the ground. Jim Bond will not catch the package.
Explanation:
Hi there!
The equation of height and velocity of the package are the following:
h = h0 + v0 · t + 1/2 · g · t²
v = v0 + g · t
Where:
h = height of the package at time t.
h0 = initial height.
v0 = initial velocity.
t = time.
g = acceleration due to gravity (-9.81 m/s² because we consider the upward direction as positive).
v = velocity of the package at a time t.
First, let´s find the time it takes the package to reach the maximum height. For this, we will use the equation of velocity because we know that at the maximum height, the velocity of the package is zero. So, we have to find the time at which v = 0:
v = v0 + g · t
0 = 50.5 m/s - 9.8 m/s² · t
Solving for t:
-50.5 m/s / -9.81 m/s² = t
t = 5.15 s
Now, let´s find the height that the package reaches in that time using the equation of height. Let´s place the origin of the frame of reference on the ground so that the initial position of the package is 10 m above the ground:
h = h0 + v0 · t + 1/2 · g · t²
h = 10 m + 50.5 m/s · 5.15 s - 1/2 · 9.81 m/s² · (5.15 s)²
h = 140 m
The maximum height of the package is 140 m above the ground. Jim Bond will not catch the package.
We have that for the Question it can be said that the magnitude of the force exerted by the horizontal rope on her arms and the ratio of the Force to the weight is
From the question we are told
A 64.0-kg ice skater is moving at 4.04 m/s when she grabs the loose end of a rope, the opposite end of which is tied to a pole. She then moves in a circle of radius 0.890 m around the pole. (a) Determine the magnitude of the force exerted by the horizontal rope on her arms. kN (b) Compare this force with her weight. F-rope W =
Generally the equation for the force applied is mathematically given as
F=1150.561N
b)
Generally the equation for the Weight is mathematically given as
W=mg
Therefore
W=64*9.81
W=627.84N
Therefore
The Force to weight ratio is
F/W=1.8325
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The force exerted by the rope on the skater's arms as she moves in a circular path is 1.167 kN. This force is about 1.860 times her weight, which is 627.2 N.
The skater is experiencing centripetal force exerted by the rope, which causes her to move in a circular path. The magnitude F of this force can be calculated using the formula F = mv²/r, where m is the skater's mass (64.0 kg), v is her velocity (4.04 m/s), and r is the radius of her circular path (0.890 m).
By substituting the given numbers into this formula, we get: F = (64.0 kg)(4.04 m/s)² / 0.890 m = 1166.67 N. In kilonewtons, this force is 1.167 kN.
To compare this force with her weight, we can calculate the weight (W) using the formula W = mg, where g is the acceleration due to gravity (around 9.8 m/s²). Substituting the given mass into this formula gives us: W = (64.0 kg)(9.8 m/s²) = 627.2 N.
Comparing these two forces shows that the force exerted by the rope on her arms is about 1.860 times her weight.
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The compound system of the block plus the
bullet rises to a height of 0.13 m along a
circular arc with a 0.23 m radius.
Assume: The entire track is frictionless.
A bullet with a m1 = 30 g mass is fired
horizontally into a block of wood with m2 =
4.2 kg mass.
The acceleration of gravity is 9.8 m/s2 .
Calculate the total energy of the composite
system at any time after the collision.
Answer in units of J.
Taking the same parameter values as those in
Part 1, determine the initial velocity of the
bullet.
Answer in units of m/s.
To solve this problem we will start considering the total energy of the system, which is given by gravitational potential energy of the total of the masses. So after the collision the system will have an energy equivalent to,
Here,
= mass of bullet
= Mass of Block of wood
The ascended height is 0.13m, so then we will have to
PART A)
PART B) At the same time the speed can be calculated through the concept provided by the conservation of momentum.
Since the mass at the end of the impact becomes only one in the system, and the mass of the block has no initial velocity, the equation can be written as
The final velocity can be calculated through the expression of kinetic energy, so
Using this value at the first equation we have that,
Answer:
360 Nm
Explanation:
Torque: This is the force that tend to cause a body to rotate or twist. The S.I unit of torque is Newton- meter (Nm).
From the question,
The expression of torque is given as
τ = F×d......................... Equation 1
Where, τ = Torque, F = force, d = distance of the bar perpendicular to the force.
Given: F = 40 N, d = 9 m
Substitute into equation 1
τ = 40(9)
τ = 360 Nm.
Answer:
360Nm
Explanation:
Torque is defined as the rotational effect of a force. The magnitude of a torque τ, is given by;
τ = r F sin θ
Where;
r = distance from the pivot point to the point where the force is applied
F = magnitude of the force applied
θ = the angle between the force and the vector directed from the point of application to the pivot point.
From the question;
r = 9m
F = 40N
θ = 90° (since the force is applied perpendicular to the end of the bar)
Substitute these values into equation (i) as follows;
τ = 9 x 40 sin 90°
τ = 360Nm
Therefore the torque is 360Nm
Answer: true
Explanation: a force can be anything that effects an object, as long as the object moves