The baseball curves better at a flatplain due to contacting with air.
A curveball is a breaking pitch with more movement than most other pitches. It is thrown slower and with more overall break than a slider and is used to throw hitters off balance.
On a flat plain, a baseball will curve down better. This is due to the curving being caused by the ball contacting air and being pushed in a specificdirection.
The spin, speed, and location of the ball's stitches in relation to the air will all influence how it changes direction when pushed against.
Consider throwing a baseball in a vacuum where there is no air. Because there is no air to push on the ball, it will not curve at all.
Thus, a flat plain area will be better for baseball curve.
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A baseball will curve better down on a flat plain.In view of the fact that the curving is caused by the ball contacting the air and pushing the ball in a particular direction.
Answer:
Explanation:
The force due to gravitation is equal to zero for each of the masses.
M1= 181kg
M2= 712kg
m = 72.6kg
The distance between M1 and M2 is said to be fixed , therefore no value should be given I.e it's a constant.
From the formula for gravitational force we have that
F = GMm/r^2
GmM1/(d-r)^2. = GmM2/r^2
where r is the distance between the 72.6 kg and 712kg
d is the distance between M1 and M2
Solving mathematically
r(√M1+√M2) = d√M2
r = d√M2/√M1 + √M2
d×26.68/ 13.45+26.68
d×26.68/40.13
r = 0.665d
True
False
Answer:Reducing mass i.e. water
Explanation:
Frequency For given mass in glass is given by
where k =stiffness of the glass
m=mass of water in glass
from the above expression we can see that if mass is inversely Proportional to frequency
thus reducing mass we can increase frequency
b) Calculate the flow speed in the bathroom.
c) What is algebraic expression for the pressure in the bathroom?
d) Calculate the water pressure in the bathroom. Report your answer in the (atm) unit.
Answer:
A) A₁ V₁ = A₂V₂
B) V₂ = 19 m /s
C) P₁ + (1/2)ρv₁² = P₂ + (1/2)ρv₂² + (h₂ - h₁ )ρg
D) P₂ = 1.88 atm
Explanation:
A) From the piaget's theory of conservation of volume, we can calculate the rate of flow of water from;
A₁ V₁ = A₂V₂
Where;
A₁ and A₂ are area of cross section V₁ and V₂ are velocity of flow at two places along pipe.
B) Using the formula given in A above, we obtain;
π x 1.2² x 4.75 = π x 0.6² x V₂
V₂ x 0.36 = 6.84
V₂ = 6.84/0.36
V₂ = 19 m /s
c ) To find pressure we shall apply Bernoulli's theorem in fluid dynamics;
P₁ + (1/2)ρv₁² = P₂ + (1/2)ρv₂² + (h₂ - h₁ )ρg
Where;
P₁ and P₂ are pressure at ground and second floor respectively
v₁ and v₂ are velocity at ground and second floor respectively
h₁ and h₂ are height at ground and second floor respectively ρ is density of water.
Thus, plugging in the relevant values to obtain;
4.1 x 10⁵ + (1/2 x 1000 x 4.75²) = P₂ + (1/2 x 1000 x 19²) + (5.2 x 1000 x 9.8)
(4.1 x 10⁵) + (0.11 x 10⁵) = P₂ + (1.8 X 10⁵) + (0.51 X 10
P₂ = 1.9 X 10⁵ N/m² = 1.88 atm
Answer:
Explanation:
We can use Ohm's Law to find the resistance R of a wire that carries a current I under a given potential difference:
Answer:
Ohm's law states that I=V/R (Current=volts divided by resistance). Since we're looking for resistance, we'll rewrite it as R=V/I. Then just plug in the numbers; R=84/9, R= 9 1/3 or 28/3. The resistance of the wire is 9.33... or 9 1/3 ohm's, depending on how you wanna write it.
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