You're carrying a 3.6-m-long, 21 kg pole to a construction site when you decide to stop for a rest. You place one end of the pole on a fence post and hold the other end of the pole 35 cm from its tip. For the steps and strategies involved in solving a similar problem, you may view a Video Tutor Solution. Part A Part complete How much force must you exert to keep the pole motionless in a horizontal position? Express your answer in newtons. F = 114 N Previous Answers
Answers
Final answer:
This Physics problem involves balancing the forces and torques acting on a 3.6-m-long pole. By applying the principles of equilibrium and calculations of torque, we find that 114 N of force is needed to keep the pole in a horizontal position.
Explanation:
This is a physics problem related to the concepts of equilibrium and torque. From the details provided, we know that the pole has a mass of 21 kg and it's 3.6 meters long. The center of gravity (cg) of the pole, since it's uniform, is at the middle, which is at 1.8 m from either end of the pole. We are then told that you are holding the pole 35 centimeters (or 0.35 meters) from its tip.
To keep the pole horizontal in equilibrium, the downward force due to the weight of the pole at its center of mass (which is equal to the mass of the pole times gravity, or 21*9.8 = 205.8 N) needs to be balanced by the sum of the torques produced by the forces you are applying at the end you are holding and the force exerted by the fence post at the other end.
Let the force you apply be F1 and the force the fence post exerts be F2. We have F2 at 0.35 m from one end (the pivot point), and F1 at 3.6 - 0.35 = 3.25 m from the pivot. Given that the torque (t) equals to Force (F) times the distance from the pivot (d), and that the net torque should equal zero in equilibrium, we have:
0.35*F2 = 3.25*F1 (1)
Because the net force should also be zero in equilibrium, we have:
F1 + F2 = 205.8 (2)
Solving these two equations, we'll be able to calculate that the force you must exert to keep the pole motionless in a horizontal position, F1, is approximately 114 N.
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Final answer:
To balance the 3.6m-long, 21 kg pole and keep it horizontally motionless, a force of approximately 114N is required
Explanation:
The subject question is a classic example of Torque problem specific to Physics, which involves the concepts of force, weight, and distance. To keep the pole motionless and horizontally balanced, the force you exert must counterbalance the torque due to the pole's weight. Assuming the pole is uniform, its center of gravity (cg) is at its midpoint, 1.8m from each end. The weight of the pole acts downward at this midpoint, providing a clockwise torque about the point of support, which is the fence post.
This torque is calculated as Torque = r * F = 1.8m (distance from fence post to cg) * Weight of pole = 1.8m * 21kg * 9.8m/s² (gravitational acceleration) = ~370 N.m. As the pole is motionless, the total torque about any point must be zero. Hence, the counter-clockwise torque provided by the force you exert is equal to the clockwise torque due to the weight of the pole. Using the distance from the point of your hold to the fence post (3.25m) we can calculate the force you need to exert: Force = Torque/distance = 370 N.m/3.25m = ~114N.
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Related Questions
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y axis:NandW and also f x axis:T and F T away from car.
Answers
9.5+9.7=19.2...
9.7-1.2=8.5...
19.2+8.5=27.70...
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Answer and Explanation:
The Sun is the main source of energy on the earth if there will be no availability of Sun energy then life is impossible om the earth besides this the Sun warms our planet. The heating of ocean and atmosphere is mainly sue to Sun energy .Sun has also a great impact on the weather we can say that Sun is weather deciding on the earth our climate is totally dependent on the how much energy we got in form of radiation from earth.
Answers
Answer:
T=12544 N*m
Explanation:
Given
L=4.0m
ms=500kg
mw=70kg
Torque is the force in a distance the relation is proportional so the torque of weight first is:
Ts = Fs*d
Ts = ms*g*L
Ts = 500kg*9.8m/s^2*2m
Ts = 9800 N*m
now torque of the worker
Tw = Fw*d
Tw = 70kg*9.8m/s^2*4m
Tw = 2744 N*m
Torque net is
Tnet = Tw+Ts
Tnet= 2744 + 9800 =12544 N*m
Final answer:
The total torque about the bolt due to the worker and the weight of the beam is 12544 Nm. This is found by adding the torque due to the beam and the worker which can be calculated using their weights and their distance from the pivot point (bolt).
Explanation:
The key to solving this question is understanding torque, which in physics represents the rotational effect of a force. Torque is calculated using the formula τ = r x F, where τ is the torque, r is the distance from the pivot point, and F is the force applied.
In this case, there are two forces to consider: the weight of the beam and the weight of the worker. Both of these can be calculated using the formula for weight (F = m*g), where m is mass and g is gravitational acceleration, which is approximately 9.8 m/s^2 on Earth. The weight of the beam is therefore 500 kg * 9.8 m/s^2 = 4900 N, and the weight of the worker is 70 kg * 9.8 m/s^2 = 686 N.
The distance from the pivot (bolt) for the beam's weight is considered to be the midpoint of the beam, so it is 4.0 m / 2 = 2.0 m. For the worker, r equals the full length of the beam, which is 4.0 m. The total torque can be calculated by adding the torque due to the beam and the worker. Therefore, the total torque τ = (2.0 m * 4900 N) + (4.0 m * 686 N) = 9800 Nm + 2744 Nm = 12544 Nm.
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Answers
Answer:
Halogen
0.85294
Explanation:
c = Speed of light =
b = Wien's displacement constant =
T = Temperature
From Wien's law we have
Frequency is given by
For Halogen
Frequency is given by
The maximum frequency is produced by Halogen bulbs which is closest to the value of
Ratio
The ratio of Incandescent to halogen peak frequency is 0.85294
O A. The Moon spinning on its axis
O B. The Sun spinning on its axis
C. Earth orbiting the Sun
D. A ballet dancer spinning in place
Answers
Answer:
Option C
Explanation:
Revolution: When an object moves around another object it is called revolution.
Rotation: When an object spins around its axis it's called rotation
Answer:C
Explanation:
Good luck!