Answers
The speed of the combined object after collision is 0 m/s.
Total momentum before collision = total momentum after collision
m₁u₁ + m₂u₂ = (m₁ + m₂)a
m₁ = object 1 mass = m, u₁ = velocity of object 1 before collision = v, m₂ = mass of object 2 = 3m, u₂ = velocity of object 2 before collision = -v/3, a = velocity after collision
mv + 3m(-v/3) = (m + 3m)a
mv - mv = 4ma
0 = 4ma
a = 0 m/s
The speed of the combined object after collision is 0 m/s.
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Answer:
the answer is 0 m/s
Explanation:
This question is describing the law of conservation of momentum
First object has mass =m
velocity of first object = v
second object = 3m
velocity of second object = v/3
the law of conservation of momentum is expressed as
m1V1 - m2V2 = (m1+ m2) V
substituting the parameters given;
making V as the subject of formular
V =
V =
V =
= 0 m/s
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6. As distance increases, gravitational force *(10 Points)increasesdecreases
A child attaches a 0.6 kg toy to a 0.9 meter length of string and spins it around in uniform circular motion. Calculate the tension in the string if the period of rotation is 4.1 seconds.
Since the density of air decreases with an increase in temperature, but the bulk modulus B is nearly independent of temperature, how would you expect the speed of sound waves in air to vary with temperature?
Answers
Answer:
the correct option is C
Explanation:
The intensity of a lamp depends on the power of the lamp that is provided by the current flowing over it, therefore the intensity would increase if we raise the current.
Another way to increase the intensity is to decrease the area with a focusing lens, as the intensity is power over area, decreasing the area increases the power.
When we see the possibilities we see that the correct option is C
Answers
Answer:
Flow stress= 9390Psi
Average flow stress= 4173.33Psi
Explanation:
Given:
Strength Coefficient = 75000psi
Strain hardening Exponent = 0.25
Gauge length = 2inches
Stretch length = 3.3 inches
Flow stress,Yf = 75000 × ln(3.3/2) × 0.25
Yf = 75000× ln(1.65) × 0.25
Yf = 75000× 0.5008 × 0.25
Flow stress = 9390Psi
Average flow stress = 75000× 0.5008 × (0.25/2.25)
Average flow stress= 4173.33psi
Answers
Final answer:
The net magnetic force exerted by the external magnetic field on a current-carrying wire formed into a loop in a uniform magnetic field is absolutely zero since the individual forces on each section of the loop cancel each other out.
Explanation:
The force exerted by a magnetic field on a current carrying wire is given by Lorentz force law, which says that the force is equal to the cross product of the current and the magnetic field. However, in this case, where the wire is formed into a loop with current flowing in a counter-clockwise direction in presence of an external magnetic field, the individual forces on each infinitesimal section of the loop cancel each other out. Therefore, the net magnetic force exerted by the external field on the entire loop is zero.
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Final answer:
The magnetic force exerted on a current-carrying wire loop by an external magnetic field can be calculated using the equation F = I * R * B.
Explanation:
The magnetic force exerted by the external field on the current-carrying wire loop can be determined using the equation F = I * R * B. The magnetic force is equal to the product of the current, radius, and magnetic field strength. The direction of the magnetic force can be determined using the right-hand rule, where the thumb represents the direction of the current, the fingers represent the magnetic field, and the palm represents the direction of the force.
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f = ________GHz
Microwave signals are beamed between two mountaintops 52 km apart. How long does it take a signal to travel from one mountaintop to the other?
Express your answer in ms and using two significant figures.
t = ________ms
Answers
Answer:
1) f= 8.6 GHz
2) t= 0.2 ms
Explanation:
1)
- Since microwaves are electromagnetic waves, they move at the same speed as the light in vacuum, i.e. 3*10⁸ m/s.
- There exists a fixed relationship between the frequency (f) , the wavelength (λ) and the propagation speed in any wave, as follows:
- Replacing by the givens, and solving for f, we get:
⇒ f = 8.6 Ghz (with two significative figures)
2)
- Assuming that the microwaves travel at a constant speed in a straight line (behaving like rays) , we can apply the definition of average velocity, as follows:
where v= c= speed of light in vacuum = 3*10⁸ m/s
d= distance between mountaintops = 52 km = 52*10³ m
- Solving for t, we get:
⇒ t = 0.2 ms (with two significative figures)
Answers
Frequency of the pendulum oscillation = 1 / Time Period => f = 1 / T = 1 / 0.5
Frequency f = 2 Hz
Answers
The magnifying power of an astronomical telescope will be:
"0.095".
Telescope: Focal length and Power
According to the question,
Radius of curvature, R = 5.5 mm
Focal length of eyepiece, = 2.9 cm
We know that,
→ Focal length of mirror,
F₀ =
By substituting the values,
=
= 2.75 mm or,
= 0.278 cm
hence,
The telescope's magnification be:
=
=
= 0.095
Thus the above approach is correct.
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Answer:
0.095
Explanation:
An astronomical telescope is a telescope used for viewing far distance object. It uses two lenses called the objective lens and the eyepiece lens.
Each lens has its own focal length
Let the focal length of the objective lens be Fo
Focal length of the eyepiece be Fe
Magnification of an astronomical telescope = Fo/Fe
Since the telescope uses a reflecting mirror having radius of curvature of 5.5mm instead of an objective lens, then we will replace Fo as the focal length of the mirror.
Focal length of a mirror Fo = Radius of curvature/2
Fo = R/2
Fo = 5.5/2
Fo = 2.75mm
Converting 2.75mm to cm gives 2.75/10 = 0.275cm
Fo = 0.275cm; Fe = 2.9cm
Magnification of the telescope = 0.275/2.9
Magnification of the astronomical telescope = 0.095