Answer;
-past temperatures
The ratio of oxygen-16 and oxygen-18 isotopes in plankton fossils in deep-sea sediments can be used to determine past temperatures.
Explanation;
-O-16 will evaporate more readily than O-18 since it is lighter, therefore; during a warm period, the relative amount of O-18 will increase in the ocean waters since more of the O-16 is evaporating.
-Hence, looking at the ratio of O16 to O18 in the past can give clues about global temperatures.
Answer:
504.57 K.
Explanation:
From the question given above, the following data were obtained:
Number of mole (n) = 6.81 moles
Pressure (P) = 2.99 atm
Volume (V) = 94.35 L
Gas constant (R) = 0.0821 atm.L/Kmol
Temperature (T) =.?
Using the ideal gas equation, the temperature of the ideal gas can be obtained as follow:
PV = nRT
2.99 × 94.35 = 6.81 × 0.0821 × T
282.1065 = 0.559101 × T
Divide both side by 0.559101
T = 282.1065 / 0.559101
T = 504.57 K.
Thus, the temperature of the ideal gas is 504.57 K.
Chromatography is a pretty accurate description of what happens to ink on wet paper, because it literally means "color writing" (from the Greek words chroma and graphe). Really, though, it's a bit of a misnomer because it often doesn't involve color, paper, ink, or writing. Chromatography is actually a way of separating out a mixture of chemicals, which are in gas or liquid form, by letting them creep slowly past another substance, which is typically a liquid or solid. So, with the ink and paper trick for example, we have a liquid (the ink) dissolved in water or another solvent creeping over the surface of a solid (the paper).
The essential thing about chromatography is that we have some mixture in one state of matter (something like a gas or liquid) moving over the surface of something else in another state of matter (a liquid or solid) that stays where it is. The moving substance is called the mobile phase and the substance that stays put is the stationary phase. As the mobile phase moves, it separates out into its components on the stationary phase. We can then identify them one by one.
Answer:
the initial temperature of the iron sample is Ti = 90,36 °C
Explanation:
Assuming the calorimeter has no heat loss to the surroundings:
Q w + Q iron = 0
Also when the T stops changing means an equilibrium has been reached and therefore, in that moment, the temperature of the water is the same that the iron ( final temperature of water= final temperature of iron = T )
Assuming Q= m*c*( T- Tir)
mc*cc*(T-Tc)+mir*cir*(T - Tir) = 0
Tir = 20.3 °C + 300 g * 4.186 J/g°C * (20.3 C - 19 °C) / ( 51.9 g * 0.449 J/g°C )
Tir = 90.36 °C
Note :
- The specific heat capacity of water is assumed 1 cal/g°C = 4.186 J/g°C
- We assume no reaction between iron and water
To calculate the initial temperature of the iron sample, use the equation q = m * c * T, where q is the heat absorbed or released, m is the mass of the substance, c is the specific heat capacity, and T is the change in temperature which is 90.36 °C
To calculate the initial temperature of the iron sample, we can use the equation:
q = m * c * T
Where q is the heat absorbed or released, m is the mass of the substance, c is the specific heat capacity, andT is the change in temperature. In this case, we know the mass of the iron sample, the specific heat capacity of iron, and the change in temperature of the water. By rearranging the equation, we can solve for the initial temperature of the iron sample.
Thus,
Tir = 20.3 °C + 300 g * 4.186 J/g°C * (20.3 C - 19 °C) / ( 51.9 g * 0.449 J/g°C )
Tir = 90.36 °C
#SPJ12
HSO3-?
Answer:
The chemical formula for the ionic compound formed by Au3+ and
HSO3-compound is Au(HSO3)3
Explanation:
The charge on Au ion is
And the charge on HSO3- is
Thus, the number of atoms required by HSO3- to complete its octate is 1. On the other hand Au has 3 excess ions and hence it is to be released to reach the stable state.
So three molecules of HSO3- will combine with one atom of Au 3+
Thus, the compound formed by these two is Au(HSO3)3
The chemical formula for the ionic compound formed by Au3+ and HSO3- is Au(HSO3)3, as ionic compounds are always neutral.
The ionic compound formed by Au3+ (Gold ion) and HSO3- (Bisulfite ion) must have a net charge of zero since ionic compounds are neutral. Hence, we need 3 bisulfite ions to balance out one gold ion, which gives us the chemical formula as Au(HSO3)3.
Indeed, the formation of ionic compounds is a fascinating process. It involves the transfer of electrons from one atom (usually a metal) to another (usually a nonmetal), resulting in the formation of ions. These ions are then attracted to each other due to their opposite charges, forming an ionic compound. In this case, the gold ion (Au3+) donates three electrons, which are accepted by three bisulfite ions (HSO3-). This results in a neutral compound, as the positive and negative charges balance each other out. The resulting compound, Au(HSO3)3, is an example of how elements can combine in specific ratios to form neutral compounds.
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Answer:
5.4347826087
Explanation:
The formula for density is Mass/Volume so you would do 250/46 to get the answer of 5.4347826087 grams per milliliter