The nuclear reactions involves the nuclei of the atoms, large amount of energy will be involved and some of the mass is converted into energy.
Explanation
Nuclear reactions are reactions which leads to change in the nuclei of the atoms.
The nuclear reaction occur between the nuclei of two atoms or between nuclei and other particles of two atoms.
The product formed will be different from the reactants.
The difference in the mass of the products and reactants are generally converted into energy.
In some nuclear reactions like nuclear fusion reaction, large amount of energy is required to collide the nuclei of two heavy elements to undergo nuclear chain reaction.
IR data: 3400 (broad), 3250 (broad), 1590, 820 cm^(-1).
Draw your proposed structure below.
Answer:
Please refer to the attachment below.
Explanation:
Please refer to the attachment below for explanation.
Answer:
an element is a atom like titanium and a compound is like a water, glucose, alcohol and salt
Explanation:
the titanium is a element and water, glucose, alcohol, and salt those are a compound
Answer:
7
Explanation:
This question is a neutralization reaction.
50 ml of 0.125 M of KOH = (50 x 0.125) = 6.25 ml
In this same way, 50 ml of 0.125M of HCl = 50x0.125
= 6.25 ml
Then KOH is going to neutralise the HCl fully suvh that the pH of the medium is going to be 7
(H+) + (OH-) = H2O
Then Kw = [H=][OH-]
= [H+]² = 10^-14
Such that [H+] = 10^-7
The pH would be = -log [H+]
= -log[10^-7]
When inputted on a calculator this gives us 7
= 7
This is our answer
Answer:
the initial temperature of the iron sample is Ti = 90,36 °C
Explanation:
Assuming the calorimeter has no heat loss to the surroundings:
Q w + Q iron = 0
Also when the T stops changing means an equilibrium has been reached and therefore, in that moment, the temperature of the water is the same that the iron ( final temperature of water= final temperature of iron = T )
Assuming Q= m*c*( T- Tir)
mc*cc*(T-Tc)+mir*cir*(T - Tir) = 0
Tir = 20.3 °C + 300 g * 4.186 J/g°C * (20.3 C - 19 °C) / ( 51.9 g * 0.449 J/g°C )
Tir = 90.36 °C
Note :
- The specific heat capacity of water is assumed 1 cal/g°C = 4.186 J/g°C
- We assume no reaction between iron and water
To calculate the initial temperature of the iron sample, use the equation q = m * c * T, where q is the heat absorbed or released, m is the mass of the substance, c is the specific heat capacity, and T is the change in temperature which is 90.36 °C
To calculate the initial temperature of the iron sample, we can use the equation:
q = m * c * T
Where q is the heat absorbed or released, m is the mass of the substance, c is the specific heat capacity, andT is the change in temperature. In this case, we know the mass of the iron sample, the specific heat capacity of iron, and the change in temperature of the water. By rearranging the equation, we can solve for the initial temperature of the iron sample.
Thus,
Tir = 20.3 °C + 300 g * 4.186 J/g°C * (20.3 C - 19 °C) / ( 51.9 g * 0.449 J/g°C )
Tir = 90.36 °C
#SPJ12
Answer:
Chloroplast, Lysosome