Answers
As per the balanced equation the amount of hydrogen peroxide required completely reacts with 265 g of lead sulphide is 150.6 g.
What is hydrogen peroxide ?
Hydrogen peroxide is covalent compound formed by two hydrogen and two oxygens. It is used as an oxidising agent. Hydrogen peroxide reacts with lead sulphide to give lead sulphate and water and the balanced reaction is given below:
As per the balanced equation 4 moles of hydrogen peroxide is required to react with one mole of lead sulphide. One mole of lead sulphide is 239.30 g and one mole of hydrogen peroxide is 34 g/mol
4 moles of hydrogen peroxides weighs 4 ×34 = 136 g. Thus, 136 g of hydrogen peroxide is needed for 239.3 g of PbS. Therefore, the mass of hydrogen peroxide needed to react with 265 g of PbS is calculated as follows:
mass = (136 ×265 g ) / 239.3
= 150.6 g.
Hence, amount of hydrogen peroxide required completely reacts with 265 g of lead sulphide is 150.6 g.
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Related Questions
Reaction A has a high activation energy, whereas reacton B has a low activation energy. Which of the statements about reaction A and reaction B are true? Reaction B is likely to occur at a faster rate than reaction A. Reaction A is more likely to occur at all than reaction B. Reaction B is more likely to occur at all than reaction A. Reaction A is likely to occur at a faster rate than reaction B.
Refer to the following standard reduction half-cell potentials at 25∘C: VO2+(aq)+Ni2+(aq)2H+(aq)++2e−e−→ →Ni(s)VO2+(aq) +H2O(l)E∘=−0.23V E∘=0.99V An electrochemical cell is based on these two half-reactions: Oxidation:Reduction:Ni(s)VO2+(aq,0.083M)+2H+(aq,1.1M)+e−→→Ni2+(aq,2.5M)+2e−VO2+(aq,2.5M)+H2O(l) Calculate the cell potential under these nonstandard concentrations. Express the cell potential to two decimal places and include the appropriate units.
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Answer:
If the partial pressure of N2 in a scuba divers blood at the surface is 0.79 atm, what will the pressure be if he/she descends to a depth of 30 meters (4 atm) and stays there long enough to reach equilibrium (b)
Explanation:
for every 3m that the internal pressure is lowered, it increases in an atmosphere approximately, so when the blood pressure of nitrogen decreases 30m, it will increase by approximately 10 atm, being enough there for the body to enter into equilibrium
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Answer:
Draw the predominant product(s) of the following reactions including stereochemistry when it is appropriate.
CH3CH2 C C CH3 H2O/H2SO4/HgSO4
Explanation:
The given compound is: pent-2-yne.
When it reacts with water, in presence of sulphuric acid and mercuric sulphate then a ketone is formed as shown below:
This reaction is an example of nucleophilic attack of water on carbon carbon triple bond.
The general mechanism of the reaction is hsown below:
Pent-2-yne reacts with water and form 3-pentanone.
The reaction is shown below:
Final answer:
The reaction is the hydration of an alkene in an acidic environment, resulting in the formation of 2-butanol. This result is in accordance with Markovnikov's rule, which determines the position of the hydroxyl group in the resultant product.
Explanation:
The question refers to the acidity-catalyzed hydration of an alkene. In this case, you have an alkene CH3CH2 - CC - CH3 reacting in an acidic environment with water (H2O). The reactants have been exposed to H2O/H2SO4/HgSO4. In this reaction scenario, the acidic medium (H2SO4) and the water enact the role of a nucleophile and attack the alkene, thereby hydrating it.
The product of this reaction will be 2-butanol. Its formation is guided by Markovnikov's rule, which states that in the addition of a protic acid HX to an alkene, the acid hydrogen (H) becomes attached to the carbon with fewer alkyl substituents, and the halide (X) group becomes attached to the carbon with more alkyl substituents. This rule is why the hydroxyl group (-OH) attaches itself to the 2nd carbon atom in the major (predominant) product.
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questions with regards to this reaction.
a) Write the molecular equation for this reaction by
Translating the two reactants into their chemical formulae.
Predict the products.
Label all the states.
Balance the reaction.
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Answer:
2 FeBr₃(aq) + 3 (NH₄)₂CO₃(aq) = Fe₂(CO₃)₃(s) + 6 NH₄Br(aq)
Explanation:
Aqueous solutions of iron(III) bromide and ammonium carbonate react. This is a double displacement reaction that gives place to ammonium bromide and iron (III) carbonate. Iron (III) carbonate is insoluble so it precipitates. The corresponding molecular equation is:
2 FeBr₃(aq) + 3 (NH₄)₂CO₃(aq) = Fe₂(CO₃)₃(s) + 6 NH₄Br(aq)
Answers
Answer:but-1-ene
Explanation:This is an E2 elimination reaction .
Kindly refer the attachment for complete reaction and products.
Sodium tert-butoxide is a bulky base and hence cannot approach the substrate 2-chlorobutane from the more substituted end and hence major product formed here would not be following zaitsev rule of elimination reaction.
Sodium tert-butoxide would approach from the less hindered side that is through the primary centre and hence would lead to the formation of 1-butene .The major product formed in this reaction would be 1-butene .
As the mechanism of the reaction is E-2 so it will be a concerted mechanism and as sodium tert-butoxide will start abstracting the primary hydrogen through the less hindered side simultaneously chlorine will start leaving. As the steric repulsion in this case is less hence the transition state is relatively stabilised and leads to the formation of a kinetic product 1-butene.
Kinetic product are formed when reactions are dependent upon rate and not on thermodynamical stability.
2-butene is more thermodynamically6 stable as compared to 1-butene
The major product formed does not follow the zaitsev rule of forming a more substituted alkene as sodium tert-butoxide cannot approach to abstract the secondary proton due to steric hindrance.
Answers
Answer:
8
Explanation:
Here we're dealing with the root mean square velocity of gases. We'll provide the formula in order to calculate the root mean square velocity of a gas:
Here:
is the ideal gas law constant;
is the absolute temperature in K;
is the molar mass of a compound in kg/mol.
We know that the gas from the red container is 4 times faster, as it takes 4 times as long for the yellow container to leak out, this means:
We also know that the temperature of the red container is twice as large:
Write the ratio of the velocities and substitute the variables:
Then:
From here:
Then:
Final answer:
Considering Graham's Law of Effusion, and given that the temperature in the red container is twice that in yellow, the molar mass of the gas in the yellow container is 16 times that of the gas in the red container.
Explanation:
The question is about comparing the molar masses of the gases based on the rate at which they escape or effuse from two different containers. The key to this problem lies in understanding Graham's Law of Effusion, which states that the rate at which a gas effuses is inversely proportional to the square root of its molar mass.
Firstly, note that it is given that the red container takes 1/4th the time as yellow to effuse completely, meaning the gas in the red container effuses 4 times faster than the gas in the yellow container. Hence, the ratio of rates of effusion is 4:1
It is also given that the temperature in the red container is twice that in the yellow. Given the gases are in the same volume and pressure, by Graham's law, the ratio of molar masses (Myellow / Mred) would be the square of the ratio of their effusion rates, however when different temperatures are considered, it's the square of [ratio of their effusion rates x (Tred / Tyellow)].
So the ratio of the molar mass of the yellow container to the red would be (4*22)2 = 16, implying that the molar mass of the gas in the yellow container is 16 times that of the gas in the red container.
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