Answers
The chemical equation that violates the law of conservation of mass is C
Mg(ClO₃)₂ → MgCl₂ + 2O₂
Let's see why:
The number of atoms from each element should be the same on both sides of the equation.
For Mg:1 atoms Left Side=1 atoms Right Side
For Cl:2 atoms Left Side=2 atoms Right Side
For O: 6 atoms Left Side ≠ 4 atoms Right Side
So, the equation is not balanced for O. The correct balanced equation is the following:
Mg(ClO₃)₂ → MgCl₂ + 3O₂
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Answers
Answer:
The pOH is 4, 44 and the solution is basic.
Explanation:
The pOH is a measure of the concentration of OH (hydroxyl) ions in the solution.
The pOH is calculated as :
pOH = -log (OH-)= -log (3.67 x 10-5 )= 4, 44. In this case, the solution is basic.
The p0H scale ranges from values of 0 to 14 (less than 7.0 is basic and greater than 7.0 is acidic, a pH = 7.0 is neutral)
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Let me know if you need anything else.
- Dotz :)
Answers
Answer:
Explanation:
Calcium oxide is fromed by the decomopostion of CaCO3 at high temperature.
CaCO3 ------> CaO +CO2
Hope this helps you
Answers
Answer:
6
Explanation:
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Answers
Answer: 3. basic
Explanation:
pH is the measure of acidity or alkalinity of a solution.
pH is measured by taking negative logarithm of hydrogen ions concentration.
Electrolyte is a solution which contains ions dissolved in water and hence is a good conductor of electricity.
A basic solution has more concentration of as compared to
.
An neutral solution has equal concentration of as that of
.
An acidic solution has more concentration of as compared to
.
Answers
Answer:
To 318.18 mL would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN
Explanation:
Dilution is the reduction of the concentration of a chemical in a solution and consists simply of adding more solvent.
In a dilution the amount of solute does not vary. But as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.
In a solution it is fulfilled:
Ci* Vi = Cf* Vf
where:
- Ci: initial concentration
- Vi: initial volume
- Cf: final concentration
- Vf: final volume
In this case:
- Ci= 1.40 M
- Vi= 20 mL
- Cf= 0.088 M
- Vf= ?
Replacing:
1.40 M* 20 mL= 0.088 M* Vf
Solving:
Vf= 318.18 mL
To 318.18 mL would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN
Final answer:
To make a 0.0880 M solution of LiCN, you would need to dilute 20.0 mL of the 1.40 M solution to a final volume of 318.18 mL.
Explanation:
To dilute a solution, you can use the formula:
M1V1 = M2V2
where M1 and V1 are the initial molarity and volume, and M2 and V2 are the final molarity and volume. Rearranging the formula, we can solve for V2:
V2 = (M1 · V1) / M2
Plugging in the values given:
V2 = (1.40 M · 20.0 mL) / 0.0880 M = 318.18 mL
To make a 0.0880 M solution of LiCN, you would need to dilute 20.0 mL of the 1.40 M solution to a final volume of 318.18 mL.
Learn more about Dilution here:
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