Answer:
please give me brainlist and follow
Explanation:
The key difference between Democritus and Dalton atomic theory is that the Democritus atomic theory is an ancient theory that scientists later refined and elaborated whereas Dalton atomic theory is a comparatively modern, scientific theory that we cannot discard due its important statements.
Final temperature of both =? C° (Copper)
Answer:
1.)100
2.)22.7
3.)24.6
Explanation:
EDGE2020
Water is 22.4
Final for both us 27.1
Explanation:
I just finished this part of the lab
B) 13 nM
C) 8.2 pM
D) 6.9 mM
Answer:
Binding affinity measures the strength of the interaction between a molecule to its ligand; it is expressed in terms of the equilibrium dissociation constant; and the higher value of this constant, the more weaker the binding between the molecule and the ligand is. On the other hand, small constans means that the interaction is tight. So "C" binds most tightly to the enzyme and "D" binds least tightly.
Answer:
Explanation:
The colligative properties of a given solution can be defined as the properties of that solution that are dependent on the concentration of the molecules or ions of the solute in the solution, and not on the type or identity of that solute. Examples include:
1. vapor pressure lowering
2. boiling point elevation
3. freezing point depression
4. Osmotic pressure
In this case, vapor pressure would be lowered because with an electrolyte introduced into a solution, the number of solute particles would be larger because the solute particles dissociate into ions, thereby competing with the solvent molecules at the surface of the solution, which in turn reduces the rate at which the solvent evaporates and condenses. Vapor pressure is lower compared to a solution with the same number of moles of nonelectrolyte solute.
The higher the number of ions in the solution, the greater the colligative properties of the solution will be impacted.
The presence of a strong electrolyte in solution affects the colligative properties differently than a non-electrolyte solute. Strong electrolytes dissociate into ions, increasing the number of particles in solution. This affects colligative properties such as vapor pressure, boiling point elevation, freezing point depression, and osmotic pressure.
The presence of a strong electrolyte in solution affects the colligative properties differently than the same number of moles of a non-electrolyte solute. This is because strong electrolytes dissociate into ions when dissolved in solution, while non-electrolytes do not. The dissociation of strong electrolytes increases the total number of particles in solution, which affects colligative properties such as vapor pressure, boiling point elevation, freezing point depression, and osmotic pressure.
For example, let's compare a solution of 1 mole of sodium chloride (NaCl) to a solution of 1 mole of sucrose (C12H22O11). The sodium chloride will dissociate into Na+ and Cl- ions, which means there are now 2 particles in solution (1 Na+ and 1 Cl-) instead of just 1 molecule of sucrose. This higher particle concentration will result in a greater depression of the freezing point and elevation of the boiling point compared to the sucrose solution.
In summary, the presence of a strong electrolyte increases the number of particles in solution, leading to greater deviations in colligative properties compared to the same number of moles of a non-electrolyte solute.
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Considering the formation of a chemical formula, the chemical formula is Li₂O.
Cations (positivelycharged ions) and anions (negatively charged ions) combine to form ionic compounds, which must be electrically neutral. Therefore, the cations and anions must combine in such a way that the net charge contributed by the total number of cations exactly cancels the net charge contributed by the total number of anions.
To form the chemical formula:
Lithium (Li) has a charge of +1, and oxygen has a charge of -2. Taking into account the above, the chemical formula is Li₂O.
Answer:
Lithium formula=Li+
Oxygen formula=O2(2-)
Explanation:
Quick note: These kinds of formula are really easy to google. Next time, google the chemical name, include the charge and include "formula" and you should get the answer.
Answer:
Draw the predominant product(s) of the following reactions including stereochemistry when it is appropriate.
CH3CH2 C C CH3 H2O/H2SO4/HgSO4
Explanation:
The given compound is: pent-2-yne.
When it reacts with water, in presence of sulphuric acid and mercuric sulphate then a ketone is formed as shown below:
This reaction is an example of nucleophilic attack of water on carbon carbon triple bond.
The general mechanism of the reaction is hsown below:
Pent-2-yne reacts with water and form 3-pentanone.
The reaction is shown below:
The reaction is the hydration of an alkene in an acidic environment, resulting in the formation of 2-butanol. This result is in accordance with Markovnikov's rule, which determines the position of the hydroxyl group in the resultant product.
The question refers to the acidity-catalyzed hydration of an alkene. In this case, you have an alkene CH3CH2 - CC - CH3 reacting in an acidic environment with water (H2O). The reactants have been exposed to H2O/H2SO4/HgSO4. In this reaction scenario, the acidic medium (H2SO4) and the water enact the role of a nucleophile and attack the alkene, thereby hydrating it.
The product of this reaction will be 2-butanol. Its formation is guided by Markovnikov's rule, which states that in the addition of a protic acid HX to an alkene, the acid hydrogen (H) becomes attached to the carbon with fewer alkyl substituents, and the halide (X) group becomes attached to the carbon with more alkyl substituents. This rule is why the hydroxyl group (-OH) attaches itself to the 2nd carbon atom in the major (predominant) product.
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