The answer is C) energy is absorbed by the molecules.
(2) higher
(3) the same
Answer : The correct option is, (1) lower
Explanation :
Formula used for lowering in freezing point :
where,
= change in freezing point
= freezing point constant
m = molality
i = Van't Hoff factor
According to the question, we conclude that the molality of the given solutions are the same. So, the freezing point depends only on the Van't Hoff factor.
Now we have to calculate the Van't Hoff factor for the given solutions.
(a) The dissociation of will be,
So, Van't Hoff factor = Number of solute particles = 1 + 1 = 2
(b) The dissociation of will be,
So, Van't Hoff factor = Number of solute particles = 1 + 2 = 3
The freezing point depends only on the Van't Hoff factor. That means higher the Van't Hoff factor, lower will be the freezing point and vice-versa.
Thus, compared to the freezing point of 1.0 M at standard pressure, the freezing point of 1.0 M at standard pressure is lower.
(2) compound because the atoms of the elements are combined in a proportion that varies
(3) mixture because the atoms of the elements are combined in a fixed proportion
(4) mixture because the atoms of the elements are combined in a proportion that varies
(2) Pb(CrO4)2 (4) Pb2(CrO4)3
Lead chromate and lead sulfate are found in the crystal Pb(Cr, S)O₄, which is a changeable solid mixed phase. This material is the end product of a co-precipitation reaction between lead and chrome salts (see the chapter on production and usage for further information). The correct option is 1.
Water does not dissolve lead chromate, which is produced by the double decomposition process. It is also used as a pigment and is referred to as chrome yellow. In a media that has been buffered with a solution of acetic acid and lead acetate, the lead precipitates as chrome.
There may be significant amounts of water-soluble lead compounds in lead chromate pigments. The formula that represents Lead (II) Chromate is PbCrO₄.
Thus the correct option is 1.
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