The sulfur (S) element of the periodic table is represented by the electron configuration .
The arrangement of electrons within the energy levels or orbitals of an atom is represented by electronic configuration. Sulfur has 16 electrons in its structure. The numbers in the electronic configuration represent the principal energy levels—1, 2, and 3—as well as the orbital—s or p—that the electrons are in.
Detail analysis of electron arrangement:
When these electronic configurations are combined, the electron configuration of sulfur (S) is represented by .
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Count the number of electrons = 2+2+6+2+2= 14
So, it must be SILICON.
Which changes occur when O2(g) is added tothis system?
(1) The equilibrium shifts to the right and the concentration of PCl3(g) increases.
(2) The equilibrium shifts to the right and the concentration of PCl3(g) decreases.
(3) The equilibrium shifts to the left and the concentration of PCl3(g) increases.
(4) The equilibrium shifts to the left and the concentration of PCl3(g) decreases.
Given the data from the question, the correct answer to the question is:
The equilibrium shifts to the left and the concentration of PCl₃(g) decreases. (Option 4)
This is simply defined as a state in a chemical system where there is no observable change in the properties of the system with time.
A French scientist postulated a principle which helps us to understand a chemical system in equilibrium.
The principle states as follow:
Considering the question given above, we are concerned with O₂ (i.e concentration) being added to the reaction
2POCl₃(g) + energy <=> 2PCl₃(g) + O₂(g)
According to the principle given above, if more O₂ is added, then, PCl₃ and O₂ will react to produce more POCl₃. Thus, the equilibrium will shift to the left and also PCl₃ will reduce.
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b. Energy flows from the surroundings to the ice.
c. Water molecules lose energy.
d. The temperature of the ice increases as it melts
versus
2 H2 + O2 -> 2 H2O?
They are both balanced chemical equations.
The two reactions are equivalent.
The laws of thermodynamics apply to both.
Conservation of mass applies to both.
Given:
12.0 M HCl
2.0 liters of a 3.0 M HCl
Required:
volume of concentrated hydrochloric acid
Solution:
M1V1 = M2V2
(12.0 M HCl)V1 = (3.0 M HCl)( 2.0 liters)
V1 = (3.0 M HCl)( 2.0 liters)/ (12.0 M HCl)
V1 = 0.5 liters
The concentration of the resulting solution is 0.33 M. The correct option is 3. 0.33 M
From the question, we are to determine the concentration of the resulting solution
From the dilution law,
M₁V₁ = M₂V₂
Where M₁ is the initial concentration
V₁ is the initial volume
M₂ is the final concentration
V₂ is the final volume
From the given information
M₁ = 1.0 M
V₁ = 20 mL
M₂ = ?
V₂ = 60 mL
Then,
1 × 20 = M₂ × 60
20 = M₂ × 60
Therefore,
M₂ = 20 ÷ 60
M₂ = 0.33 M
Hence, the concentration of the resulting solution is 0.33 M. The correct option is 3. 0.33 M
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(2) 35.0% (4) 60.0%
Answer:
The correct option is (2) 35.0%
Explanation:
If we want to calculate the percent composition by mass of nitrogen in NH4NO3 we first need to calculate the mass of nitrogen in one mole of NH4NO3.
Because of the molecular form of NH4NO3 (it has 2 ''N'') we know that one mole of NH4NO3 contains 2 moles of N.
The molar mass of N (nitrogen) is
This means that 1 mole of N contains 14.0067 grams of N.
Because we have 2 moles of N ⇒
We know that in 1 mole of NH4NO3 we have 2 moles of N(28.0134 g of N).
To calculate the percent composition by mass of nitrogen we need to divide the mass of nitrogen in one mole of NH4NO3 by the mass of one mole of NH4NO3 and then multiply it by 100.
We know that in 1 mole of NH4NO3 there are 80.0 g of NH4NO3 (Because of the molar mass data) ⇒
% ≅ 35.0%
We find that the percent composition by mass of nitrogen in NH4NO3 is 35.0%
We conclude that the correct option is (2) 35.0%