Sara is completing the square to find the maximum or minimum value of the function f(x) = (2 - x) (5 + x). What is the first step that Sara must take? Does the function have a maximum or minimum value? What is that value?A) multiply the binomials; maximum value;
49
4
B) multiply the binomials; minimum value;
49
4
C) set each factor equal to zero and solve for x; minimum value;
−2
5
D) set each factor equal to zero and solve for x; maximum value;
−7
2

Answers

Answer 1
Answer: Definitely multiply out the given factors:

f(x) = 10 + 2x - 5x - x^2, or  f(x) = -x^2 - 3x + 10
Find the derivative:  f '(x) = -2x - 3
Set the deriv. = to 0 and solve for x:  -2x = 3, and x = -3/2
This x = -3/2 is the x-coordinate of the max value.  The y-coord. is

f(-3/2) = (-3/2)^2 - 3(-3/2) + 10 = 21.25

I realize that this result does not agree with any of the four possible answers.  Please ensure that y ou have copied down this problem completely and correctly.


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Answers

The correct answer is option D.

The function has a repeated root. We can find this by factorization.

x² - 2x + 1
= x² - x - x + 1
= x (x - 1) - 1(x - 1)
= (x -1)(x - 1)

This can also be checked by finding the discriminant. The discriminant is zero which shows the function has a repeated root.


Mass and weight math​

Answers

Answer: There is 1,000 milligrams in 1 gram.

Answer:

1000mg

Step-by-step explanation:

to be honest that's the obvious answer

and in advance

1kg=1000000mg

1kg=1000g

1g=1000g

Suppose that the maximum weight that a certain type of rectangular beam can support varies inversely as it’s length and jointly as its width and the square of its height. Suppose also that a beam 5 inches wide, 2 inches high and 10 feet long can support a maximum weight of 8 tons. What is the maximum weight that could be supported by a beam that is 6 inches wide, 2 inches high, and 24 feet long

Answers

4 tons is maximum weight that could be supported by a beam that is 6 inches wide, 2 inches high, and 24 feet long

What is Weight?

Gravitational force of attraction on an object, caused by the presence of a massive second object, such as the Earth or Moon.

Given,

Maximum weight that a certain type of rectangular beam can support varies inversely as it’s length and jointly as its width and the square of its height.

beam 5 inches wide, 2 inches high and 10 feet long can support a maximum weight of 8 tons.

W = k × w × h²/ L

8 = k × 5 × 2² / 10

8 = k ×20/10

8 = 2 × k

k = 4

The maximum weight that could be supported by a beam that is 6 inches wide, 2 inches high, and 24 feet long

w =4 ×6 ×2² / 24

= 24 ×4/ 24

W=4 tons

Hence 4 tons is maximum weight that could be supported by a beam that is 6 inches wide, 2 inches high, and 24 feet long

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Way: W = k * w  * h^2/ L

A triangle has a base of 16 inches and a height of 18 1 8 inches. What is its area?

Answers

Answer:

144 in²

Step-by-step explanation:

area of a triangle = 1/2 * base * height

area = 1/2 * 16 * 18

area = 144 in²

Final answer:

The area of a triangle with a base of 16 inches and a height of 18 1/8 inches is 145 square inches.

Explanation:

The area of a triangle can be calculated using the formula: Area = 1/2 * base * height. In this case, the given base is 16 inches and the height is 18 1/8 inches.

To calculate: Area = 1/2 * 16 inches * 18 1/8 inches. Because 1/2 of 16 is 8, we can simplify this to Area = 8 inches * 18 1/8 inches.

Now, multiply 8 by 18 1/8 to find the area. The area of the triangle is 145 square inches.

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Help! Its due in a couple mins!Comment on these angles and what type of angles are they explain​

Answers

Answer:

right angle and congruent

Step-by-step explanation:

2. Acute angle. Acute angle is measured as 40 degrees, smaller than right angle.

Let a1equals[Start 3 By 1 Matrix 1st Row 1st Column 1 2nd Row 1st Column 2 3rd Row 1st Column negative 1 EndMatrix ]​, a2equals[Start 3 By 1 Matrix 1st Row 1st Column negative 7 2nd Row 1st Column negative 7 3rd Row 1st Column 2 EndMatrix ]​, and bequals[Start 3 By 1 Matrix 1st Row 1st Column 3 2nd Row 1st Column negative 22 3rd Row 1st Column h EndMatrix ]. For what​ value(s) of h is b in the plane spanned by a1 and a2​?

Answers

Answer:

For h= 25,  b in the plane spanned by a1 and a2​

Step-by-step explanation:

a1= \left[\begin{array}{c}1\n2\n-1\end{array}\right] \na2 = \left[\begin{array}{c}-7\n-7\n2\end{array}\right] \n\nb   = \left[\begin{array}{c}3\n-22\nh\end{array}\right]

we have to find value of h for which  b in the plane spanned by a1 and a2.

For this the linear systems given by the  following augmented matrix must be consistent.

\left[\begin{array}{cc|c}1&-7&3\n2&-7&-22\n-1&2&h\end{array}\right]

Reduce the augmented matrix into row echelon form:

R_(2) - 2R_(1) , R_(3) + R_(1)\n\n\left[\begin{array}{cc|c}1&-7&3\n0&7&-28\n-0&-5&h+3\end{array}\right]\n\n7R_(3)+5R_(2)\n\n\left[\begin{array}{cc|c}1&-7&3\n0&7&-28\n-0&0&7h-175\end{array}\right]

For system to be consistent:

                         7h-175 =0\n7h=175\nh=25