MATHEMATICS COLLEGE

2. The path of a high diver is given by y = + (2x2 – 9x – 56), where y is the height of the diverabove the water and x is the horizontal distance from the diving board (in feet). How far from the
end of the diving board is the diver when he hits the water?

Answers

Answer 1
Answer:

Answer:

The diver will be 8 feet from the end of the board when he hits the water.

Step-by-step explanation:

The diver hits the water when y = 0.

To find the distance, we have to find the values of x when y = 0.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^(2) + bx + c, a\neq0.

This polynomial has roots x_(1), x_(2) such that ax^(2) + bx + c = (x - x_(1))*(x - x_(2)), given by the following formulas:

x_(1) = (-b + √(\bigtriangleup))/(2*a)

x_(2) = (-b - √(\bigtriangleup))/(2*a)

\bigtriangleup = b^(2) - 4ac

In this problem, we have that:

y = 2x^(2) - 9x - 56

2x^(2) - 9x - 56 = 0

So

a = 2, b = -9, c = -56

Then

\bigtriangleup = b^(2) - 4ac = (-9)^(2) - 4*2(-56) = 529

x_(1) = (-(-9) + √(529))/(2*2) = 8

x_(2) = (-(-9) - √(529))/(2*2) = -3.5

It is a horizontal distance, so the answer is a positive value.

The diver will be 8 feet from the end of the board when he hits the water.

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y = 8x + 12
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Answers

Step-by-step explanation:

y = 8x + 12 _____(1)

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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