Answer:
x-7y=84
x-7y-84=0
Step-by-step explanation:
y=mx+c
y=ax+b
ax+by=c or ax+by-c=0
m= 1/7
y=1/7x-12
x-7y=84
x-7y-84=0
Answer: 6p
Explanation: The word "product" is a
keyword that tells us to use multiplication.
So your answer can be written as 6 · p or just 6p.
Don't write your answer as p6.
Even though it's technically correct, I would always put
the number before the variable as a matter of form.
Answer:
6p
Step-by-step explanation:
Answer:
Step-by-step explanation:
The negative coefficient of x^2 tells you the parabola opens downward. (Any even-degree polynomial with a negative leading coefficient will open downward.)
Going through the steps for completing the square, we ...
1. Factor out the leading coefficient from the x-terms
-1(x^2 +14x) +1
2. Add the square of half the x-coefficient inside parentheses, subtract the same amount outside parentheses.
-1(x^2 +14x +49) -(-1·49) +1
3. Simplify, expressing the content of parentheses as a square.
-(x +7)^2 +50
4. Compare to the vertex form to find the vertex. For vertex (h, k), the form is
a(x -h)^2 +k
so your vertex is ...
(h, k) = (-7, 50) . . . . . . . . . a = -1 < 0, so the curve opens downward. The vertex is a maximum.
The maximum value of the expression is 50.
Answer:15
Step-by-step explanation:
44 cm
154 cm
616 cm
Answer: 154 cm is the answer
Step-by-step explanation:
Answer:
154 cm
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let P(H) be the probability that he is accepted by Harvard
Let P(D) be the probability that he is accepted by Dartmouth
Let P(HnD) be the probability that he is accepted by Harvard and Dartmouth
Given data
P(H) = 0.3
P(D) = 0.5
P(DnH) = 0.2
To get the probability that he is accepted by Dartmouth if he is accepted by Harvard, can be gotten using the conditional probability formula.
P(D|H) = P(DnH)/P(H)
P(D|H) = 0.2/0.3
P(D|H) = 2/10/÷3/10
P(D|H) = 2/10×10/3
P(D|H) 2/3
b) The two events are independent if the occurrence of an event does not affect the other occurring. For the two events to be independent then;
P(DnH) = P(D)P(H)
Given P(D) = 0.5 and P(H) = 0.3
P(D)P(H) = 0.5 × 0.3
P(D)P(H) = 0.15
And since P(DnH) = 0.2, hence P(DnH) ≠ P(D)P(H)
This means that the event "accepted at Harvard" IS NOT independent of the event "accepted at Dartmouth" since the two values are not equal.