Question 10 of 321 Point
The standard form of the equation of a parabola is
y=1x2 - 4x +21. What is the vertex form of the equation?
O A. y =(x+4)2 +13
O B. y=2(x+4)2 +21
C. y = 2(x-4)2 + 21
D. y = -(x-4)? +13

Answers

Answer 1

Answer:

i thinhk is C DONT NOW

Answer 2

Answer: The answer is c ) y=2(x-4) 2+21

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I need help with this math problem please (3x+2)(5x-7)

Answers

Answer:

Hey there!

Using the foil method: (3x+2)(5x-7)

15x^2+10x-21x-14

15x^2-11x-14

Let me know if this helps :)

Here’s your answer (3x+2)x(5x-7)

Suppose you read online that children first count to 10 successfully when they are 32 months old, on average. You perform a hypothesis test evaluating whether the average age at which gifted children first count to 10 is different than the general average of 32 months. What is the p-value of the hypothesis test? Choose the closest answer.

Answers

Answer:

$p_v =2*P(t_((35))<-1.822)=0.0885$

Step-by-step explanation:

Assuming this info from R

hist(gifted$count)

## Min. 1st Qu. Median Mean 3rd Qu. Max.

## 21.00 28.00 31.00 30.69 34.25 39.00

## Sd

## [1] 4.314887

Data given and notation

$\bar X=30.69$ represent the mean

$s=4.3149$ represent the sample standard deviation

$n=36$ sample size

$\mu_o =32$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is different than 32, the system of hypothesis would be:

Null hypothesis: $\mu = 32$

Alternative hypothesis: $\mu \neq 32$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=(\bar X-\mu_o)/((s)/(√(n)))$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=(30.69-32)/((4.3149)/(√(36)))=-1.822$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=36-1=35$

Since is a two sided test the p value would be:

$p_v =2*P(t_((35))<-1.822)=0.0885$

An aptitude test has a mean score of 80 and a standard deviation of 5. The population of scores is normally distributed. What raw score corresponds to the 70th percentile?

Answers

Answer:

82.62

Step-by-step explanation:

Mean score (μ) = 80

Standard deviation (σ) = 5

The 70th percentile of a normal distribution has an equivalent z-score of roughly 0.525.

For any given score, X, the z-score can be determined by:

$z=(X-\mu)/(\sigma)$

For z = 0.525:

$0.525=(X-80)/(5)\n X=82.62$

A raw score of approximately 82.62 corresponds to the 70th percentile.

Answer: the raw score that corresponds to the 70th percentile is 82.625

Step-by-step explanation:

Since the population of scores in the aptitude test is normally distributed., we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = aptitude test scores.

µ = mean score

σ = standard deviation

From the information given,

µ = 80

σ = 5

We want to find the raw score that corresponds to the 70th percentile.

70th percentile = 70/100 = 0.7

Looking at the normal distribution table, the z score corresponding to 0.7 is 0.525.

Therefore,

0.525 = (x - 80)/5

5 × 0.525 = x - 80

2.625 = x - 80

x = 2.625 + 80

x = 82.625

Change 11/5 from an improper fraction to a mixed number

Answers

Solution: 11/5 as a mixed number is 2 1/5.

In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is . Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?

Answers

Completed question:

In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is 0.127. Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?

Answer:

0.557

Step-by-step explanation:

For each game, the probability of not end in a draw is 1 - 0.127 = 0.873. Thus, because each game is independent of each other, the probability of all of them not end in a draw is the multiplication of the probability of each one:

0.873x0.873x0.873x...x0.873 = 0.873⁶ = 0.443

Thus, the probability that at least one of them end in a draw is the total probability (1) less the probability that none of them en in a draw:

1 - 0.443

0.557

63x^18/9x^2 simplified