If you shout on the moon,will the sound travel faster or slower than on earth?why?

Answers

Answer 1

Answer: As long as the sound is inside the helmet of your space suit, it will travel
at the same speed as it would on Earth, through the same mixture of gases
at the same pressure. Once it passes through the visor of your space helmet,
its 'speed' has no meaning, since there's nothing for sound to travel through on
the moon, and it doesn't travel at all.

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You drive your car for 2.0 h at 40.0 km/h then for 2.0 h at 60.0 km/h what is your average velocity?
Scientific notation 47,000
What type of lens is used to make objects appear smaller and clearer convex or concave?

a car with a mass of 1200 kilograms is moving around a circular curve at a uniform velocity of 20 m/s the centripetal force on the car is 6000 neutrons what is the radius of the Curve

Answers

Coupla things wrong with this question, Sam.
Let's clean those up first, and then we'll work on the answer.

-- The car is NOT moving with uniform velocity.
'Velocity' includes both speed and direction. If either of these
changes, it's a change of velocity.
On a circular track, the car's direction is CONSTANTLY changing,
so its velocity is too.
The thing that's uniform is its speed, not its velocity.

-- A 'neutron' is a subatomic particle found in the nucleus of most
atoms. It's not a unit of force. The unit of force is the 'Newton'.
_______________________

OK. A centripetal force of 6,000 newtons keeps 1,200 kg of mass
moving in a circle at 20 m/s.

The formula:

   Centripetal force = (mass) (speed)² / (radius)

Multiply each side
by 'radius': (centripetal force) x (radius) = (mass) x (speed)²

Divide each side by
'centripetal force':   Radius = (mass) x (speed)² / (centripetal force)

Write in the numbers
that we know: Radius = (1200 kg) (20 m/s)² / (6000 Newtons)

   = (1200 kg) (400 m²/s²) / (6000 Newtons)

   = (480,000 kg-m²/s²) / (6000 kg-m/s²)

   = (480,000 / 6000) meters

   = 80 meters .

Answer:

80 meters

Explanation:

Using the value of atmospheric pressure at sea level, 1 × 105 Pa, estimate the total mass of the earth's atmosphere above a 5-m2 area.

Answers

Answer:

5×10^4 kg

Explanation:

pressure= force/Area

area= 5m^2

pressure = 1×10^5 Pa

1×10^5=mg/5 (weight will be the force)

5×10^5=m×10 (gravitational field strength of the earth)

5×10^5×10^-1 =m

mass=5×10^4 kg!

hope this helps!

What color do you think an object would be if it reflected all colors of the visible spectrum? A.The object would be black.

B.The object would be yellow.

C.The object would be white.

D.The object would be blue.

Answers

c) The object would be WHITE.

We call "white light" to the sunlight, but referred to the visible part of spectrum. If the object reflects all the light, it appears as a white object.

Which of these do you prove with a geometric proof?experiments
opinions
postulates
theorems

Answers

postulates and theorems.

When describing a maritime polar air mass, you might say it formed over _____ and is _____.

Answers

The correct answer for the question that is being presented above is this one: "an air mass that formed over land. it is cold and dry." When describing a maritime polar air mass, you might say it formed over land and is cold and dry. It's temperature can range from around freezing to near 20 degrees Celsius

Answer:

water, cold and moist

Explanation:

I just did a test on it and got it wrong using land, cold and dry and got it right using this anwer

A rain gutter is to be constructed from a metal sheet of width 30 cm by bending up one-third of the sheet on each side through an angle θ . How should θ be chosen so that the gutter will carry the maximum amount of water?

Answers

Answer:

Explanation:

The volume of the water carried will be proportional to the cross-sectional area. The cross-section is a trapezoid with height 10sint, where t represents theta. The top of the trapezoid is 10+(2)(10cost), i.e. 10 + 20cost. The base of the trapezoid is 10.

Area of trapezoid = (average of bases) times (height)

= ([10 + (10 +20cost)] / 2 ) 10 sint

= (10 + 10cost)(10sint)

= 100sint + 100sintcost, call this A(t). You need to maximize. So differentiate and set equal to zero.

dA/dt = -100sin(t)^2+100cos(t)+100cos(t)^2 = 0, divide by 100:

-sin(t)^2 + cos(t) + cos(t)^2 = 0, replace sin^2 by 1-cos^2

2cos(t)^2 + cos(t) - 1 = 0, factor

(1+cos(t))(2cos(t)-1)=0, so

cos(t)=1, t=0 that give a min (zero area) not a max, or

cos(t) = 1/2, so t=60 degrees. This gives the max.

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A low-pressure system is generally associated with what type of weather condition?A.thick cloud cover B.increasing altitude C.low humidity D.clear sky