A low-pressure system is generally associated with what type of weather condition?A.thick cloud cover

B.increasing altitude

C.low humidity

D.clear sky

Answers

Answer 1

Answer: i would say low humidity.

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Amusement parks are a great place to see Newton's laws of motion in action. Choose your favorite ride and describe the parts of the ride that illustrate each of Newton's laws of motion. You are only required to give a written description; however, if you would like, you may draw and label a picture in addition to the paragraph explanation. Please be sure to look at the rubric to see exactly what you are expected to include!

Answers

Since it's against good conscience, I will not directly tell you how Newtonian mechanics relates to one's favorite amusement park ride, but I can still assist. Think about the very last ride you were on. There are always Newtonian forces acting on you, but even more-so at the amusement park. Anything dealing with the 'forces' of gravity or centrifugal force will do, and these are seen throughout just about every ride fathomable in a park.

if a wave has a velocity of 24 m/s and a period of 3.0 s. what is he frequency of the wave in Hz?

Answers

The frequency doesn't depend on the wave speed.
Frequency is simply the reciprocal of the period.

Frequency= 1 / (3sec) = 1/3 per sec = 1/3 Hz.

We know that by definition Frequency is the reciprocal of period.
So
f=1/3=0.33Hz

NASA decides to put a 128 kg satellite into orbit over the planet Venus because they want to take pictures. The satellite is 37,000,000 m above the surface of venus. Calculate the gravitational field at that altitude. m/s2
how do you calculate this

Answers

1). Look up the acceleration of gravity on the surface of Venus. It's 8.87 m/s².
(That's about 10% less than on Earth.)

2). Look up the radius of Venus. It's 6051.8 km.
(That's about 5% less than Earth's.)

3). Remember that the gravitational field (acceleration, force) changes
opposite to the square of the distance from the planet ... or the distance
between any two masses that are gravitating.

Now we have enough information to do the calculating. Notice that the question
only asks for the planet's "gravitational field" (acceleration) way out there. That
has nothing to do with the satellite's mass, or whatever you decide to put out there,
or even if there's nothing out there at all. It's just a characteristic of Venus at that
distance from it.

The distances we need to compare are the distances from the center of Venus.

On the surface (distance from the center is the radius of Venus), it's 6,051,800 m.
In the orbit, it's 37,000,000 m.

The ratio is (37,000,000 / 6,051,800) = about 6.1 .

The gravity way out in the orbit is less than on the surface, and by the
same amount as the square of the distance ratio.

Surface gravity = 8.87

Gravity out at the orbit = 8.87 divided by (the distance ratio)²

Gravity = 8.87 / (6.1)²

Better way: Gravity = 8.87 x (6,051,800/37,000,000)² = 0.2373 m/sec²

intravenous infusions are usually made with the help of the gravitational force. assuming that the density of the fluid being administered is 1,020 kg/m3, at what height should the iv bag be placed above the entry point so that the fluid just enters the vein if the blood pressure in the vein is 2.7 x 103 pa above atmospheric pressure? assume that the iv bag is collapsible. (hint: atmospheric pressure is applicable in the entire situation)

Answers

The IV bag should be placed approximately 10.19 meters above the entry point to ensure that the fluid just enters the vein, considering the blood pressure in the vein and assuming atmospheric pressure is applied.

Given:

Density of the fluid being administered = 1,020 kg/m³

Blood pressure in the vein = 2.7 × 10³ Pa above atmospheric pressure

Since the fluid is administered using gravitational force, the pressure at the entry point of the vein should be higher than the pressure at the IV bag.

The pressure difference can be calculated using the formula:

Pressure difference = density × gravitational acceleration × h

The pressure difference should be equal to the sum of the blood pressure in the vein and the atmospheric pressure:

Pressure difference = (blood pressure in the vein) + (atmospheric pressure)

h = (pressure difference) / (density × gravitational acceleration)

h = [(2.7 × 10³) + (101,325)] / (1,020 × 9.8)

h ≈ 10.19 meters

Therefore, the IV bag should be placed approximately 10.19 meters above the entry point to ensure that the fluid just enters the vein, considering the blood pressure in the vein and assuming atmospheric pressure is applicable throughout the situation.

To know more about atmospheric pressure:

brainly.com/question/31634228

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A conducting coil of 1850 turns is connected to a galvanometer, and the total resistance of the circuit is 30 Ω. The area of each turn is 4.00 × 10-4 m2. This coil is moved from a region where the magnetic field is zero into a region where it is nonzero, the normal to the coil being kept parallel to the magnetic field. The amount of charge that is induced to flow around the circuit is measured to be 8.0 × 10-3 C. Find the magnitude of the magnetic field.