47,000 written as 4.7 x 104 in s scientific notation
Given:
V1 = 4m3
T1 = 290k
P1 = 475 kpa = 475000 Pa
V2 = 6.5m3
T2 = 277K
Required:
P
Solution:
n = PV/RT
n = (475000 Pa)(4m3) / (8.314 Pa-m3/mol-K)(290k)
n = 788 moles
P = nRT/V
P = (788 moles)(8.314 Pa-m3/mol-K)(277K)/(6.5m3)
P = 279,204 Pa or 279 kPa
Answer:
The length of its year.
Explanation:
When Earth completes a full rotation, a year has completed. So, the same can be the same for other orbiting planet. The moon for example takes 29.5 days to revolve around the Earth, so one moon year is 29.5 Earth days.
The height of the apple from the ground can be calculated using the formula for gravitational potential energy. Given the apple's mass and its potential energy, we find that the apple is approximately 5000 meters from the ground.
The gravitational potential energy of an object can be calculated using the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity (9.8 m/s² on Earth), and h is the height of the object from the ground. In this case, the apple's gravitational potential energy is given as 175J, its mass is 0.36g (or 0.00036 kg when converted.)
To find the apple's height from the ground, you need to rearrange the formula to solve for h: h = PE / (m * g). Substituting the given values in the formula, h = 175 J / (0.00036 kg * 9.8 m/s²), you get approximately h = 5000 meters.
#SPJ12
a. carbon
c. mercury
d. nitrogen
b. oxygen