Mike sees 3 more fish than Chris. Chris sees 6 fish. How many fish does Mike see? It says use comparison bars. Thanks

Answers

Answer 1

Answer: Chris sees 6 fish.

Mike sees 3 more fish than Chris.

6 + 3 = 9

So on your bar, you have Chris's number of fish he saw, 6, and you have 3 being added to that on Mike's bar.

Answer 2

Answer: Mike sees 9 fish. 6 + 3 = 9.

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Write a linear function that passes through (1,5) and (2,15)

The question is in my screenshot I took. :) Need help, please.

Answers

I am thinking that c is correct and i am truely sorry if u get it wrong

The answer is C bc there are 3 whole shapes and there divided into 1/3 each

Subtract. 3/8−(−5 1/4)

Enter your answer, as a mixed number in simplest form.
P.S -5 1/4 is a mixed number)

Answers

Your answer would like be 5 5/8

Multiplying numerators and denominators to get the LCD in all fraction denominators

= 38−21×24×2

Then rewriting the equation with the equivalent fractions

= 38−428

With like denominators we can operate on just the numerators

= 3−4 2/8

=−39/ 8

Simplifying the answer

= − 39/8

= − 4 7/8

First term 2 common difference 13

Answers

Answer:

With the first term is 2 and common difference is 13 then the series is 2,15,28,...

Step-by-step explanation:

Given first term is 2 and common difference is 13.

Arithmetic progression:

$a_(1)=2$ and d=2 [given]

Therefore we can find arithmetic series $a_(1),a_(2),a_(3),...$ with $a_(1)=2$ and d=2

d can be written as $d=a_(2)-a_(1)$ . Therefore we can write $a_(2)$ as below:

$a_(2)=a_(1)+d$

Now substitute the values $a_(1)=2$ and d=2

$a_(2)=2+13$

$a_(2)=15$

Similarly we can find $a_(3)$

d can be written as $d=a_(3)-a_(2)$ . Therefore we can write $a_(3)$ as below:

$a_(3)=a_(2)+d$

$a_(3)=15+13$

$a_(3)=28$

and so on.

Therefore the series is 2,15,28,...

Explain how you would find the length of one side of a square if the area is 16 square units

Answers

you divide by four because there are 4 sides of a square and they are all equal

If it is 16 sq units then divide by 4 and all the sides would be 4sq units

A bag contains 5 red marbles and 7 blue marbles. You randomly pick a marble and then pick a second without returning the marbles to the bag. Both marbles are red.