3.7500*10^4+9.7100*5

Answers

Answer 1
Answer:

Answer:

37548.55

Explanation:

3.7500*10^4+9.7100*5

3.7500*10000+9.7100*5

37500+48.55

37548.55


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Classify each type of matter as an element, a compound, a heterogeneous mixture, or a homogeneous mixture. drag each item to the appropriate bin. sugar air hot tea salt water

Answers

Answer :

Sugar : Compound

Air : Homogeneous mixture

Hot tea : Homogeneous mixture

Salt water : Homogeneous mixture

Explanation :

Element : It is a pure substance which is composed of atoms of similar elements.

Compound : It is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.

Heterogeneous mixtures : It is a mixture that has non-uniform composition throughout the solution and the particle size or shapes are also different.

There is a physical boundary between the dispersed phase and dispersion medium.

Homogeneous mixtures : It is a mixture that has uniform composition throughout the solution and the particle size or shapes are not different.

There is no physical boundary between the dispersed phase and dispersion medium.

As per question,

Sugar : It is a compound that is made from atoms of different elements combined together in a fixed ratio by mass.

Air : It is a homogeneous mixture of the gaseous substances of nitrogen, oxygen, and smaller amounts of other substances.

Hot tea : It is a homogeneous mixture because its composition is the same throughout the solution.

Salt water : It is a homogeneous mixture because its composition is the same throughout the solution.

Sugar compound

Air Homogeneous mixture

Hot tea Homogeneous mixture

Salt water Homogeneous mixture

 

Element:

An element is a simplest type of a pure substance which is composed of only one type of matter. For examples; silver, gold platinum etc.

Pure substance:

A compound is a pure substance which is composed of two or more type of matter in definite proportion. For examples; water which is composed by Hydrogen and oxygen etc.

Mixture:

A mixture is made from two or more type of matter in any proportion. Mixture are generally two types:

1. Homogeneous mixture

This is also known as solution, in which the composition of the substances is uniform.

Lemon-flavored water is an example of homogeneous mixture because in this the composition of the substances is uniform.

2. Heterogeneous mixture

In this form of mixture the composition of substance are not uniform and the component of mixture also visible.

Stuffed mushrooms is an example of Heterogeneous mixture because in this form of mixture the composition of substance are not uniform and the component of mixture also visible.


Which of the following equations violates the law of conservation of mass? A. FeCl3 + 3NaOH yields Fe(OH)3 + 3NaCl

B. CS2 + 3O2 yields CO2 + 2SO2

C. Mg(ClO3)2 yields MgCl2 + 2O2

D. Zn + H2SO4 yields H2 + ZnSO4

Answers

Hi!

The chemical equation that violates the law of conservation of mass is C

Mg(ClO₃)₂ → MgCl₂ + 2O₂

Let's see why:

The number of atoms from each element should be the same on both sides of the equation.

For Mg:
1 atoms Left Side=1 atoms Right Side
For Cl:
2 atoms Left Side=2 atoms Right Side
For O: 6 atoms Left Side ≠ 4 atoms Right Side

So, the equation is not balanced for O. 
The correct balanced equation is the following:

Mg(ClO₃)₂ → MgCl₂ + 3O₂

Have a nice day!

When a sodium chloride (NaCl) solution is given to some intravenously (as an IV directly into the blood), it is usually a 0.9% NaCl solution. The reason is that a 0.9% NaCl is isotonic to your red blood cells. Use that information to answer the following questions: In the solution above, which molecule is acting as the solute and which molecule is acting as the solvent? If you replaced the 0.9% NaCl solution with pure water instead, would the water be hypertonic, hypotonic, or isotonic to your red blood cells? If you replaced the 0.9% NaCl solution with pure water instead, would the net (overall) movement of water be into the cell, out of the cell, or would there be no net movement of water? If you replaced the 0.9% NaCl solution with pure water instead and waited, what specifically would happen to your red blood cells?

Answers

Answer:

Explanation:

(1) In the IV solution, the solute here is the NaCl salt and the solvent is the liquid (water) the salt is dissolved in.

(2) If the NaCl is replace with water, the water content will become hypotonic to the red blood cells as there would be less solute in the solution than in the cell's cytosol. This also means there is more water in the solution than in the cell's cytosol.

(3) Because the water is hypotonic to the red blood cells (as described in (2) above), the net movement of water will be into the cell.

(4) If the movement of water is allowed to continue as described in (3) above (i.e if 0.9% NaCl in the solution is replaced with pure water instead and waited), the cell will rupture which can lead to cell lysis or cytolysis.

NOTE: An isotonic solution describes when there is the same amount of solute in the cell and the solution outside the cell hence there is little or no movement of water.

Final answer:

In a 0.9% NaCl solution, NaCl is the solute and water is the solvent. If replaced with pure water, the water would be hypotonic to red blood cells and water would move into the cells. The red blood cells would undergo osmosis and potentially burst.

Explanation:

In a 0.9% NaCl solution, the sodium chloride (NaCl) is acting as the solute, while the water is acting as the solvent. If the 0.9% NaCl solution is replaced with pure water, the water would be hypotonic to the red blood cells. This means that the concentration of solute particles in the water is lower than that inside the red blood cells. If pure water is used instead, there would be a net movement of water into the red blood cells because water moves from hypotonic solutions to hypertonic solutions in order to equalize the concentration of solute particles.

As a result, if the 0.9% NaCl solution is replaced with pure water and left for some time, the red blood cells would undergo osmosis and swell up. This could potentially lead to the bursting of red blood cells, a process known as hemolysis.

Learn more about Solute, Solvent, Hypotonic Solutions here:

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how does the presence of a strong electrolyte in solution affect the colligative properties of a solution when compared to the same number of moles of a nonelectrolyte solute?

Answers

Answer:

  • lowered vapor pressure
  • higher boiling point

Explanation:

The colligative properties of a given solution can be defined as the properties of that solution that are dependent on the concentration of the molecules or ions of the solute in the solution, and not on the type or identity of that solute. Examples include:

1. vapor pressure lowering

2. boiling point elevation

3. freezing point depression

4. Osmotic pressure

In this case, vapor pressure would be lowered because with an electrolyte introduced into a solution, the number of solute particles would be larger because the solute particles dissociate into ions, thereby competing with the solvent molecules at the surface of the solution, which in turn reduces the rate at which the solvent evaporates and condenses. Vapor pressure is lower compared to a solution with the same number of moles of  nonelectrolyte solute.

The higher the number of ions in the solution, the greater the colligative properties of the solution will be impacted.

Final answer:

The presence of a strong electrolyte in solution affects the colligative properties differently than a non-electrolyte solute. Strong electrolytes dissociate into ions, increasing the number of particles in solution. This affects colligative properties such as vapor pressure, boiling point elevation, freezing point depression, and osmotic pressure.

Explanation:

The presence of a strong electrolyte in solution affects the colligative properties differently than the same number of moles of a non-electrolyte solute. This is because strong electrolytes dissociate into ions when dissolved in solution, while non-electrolytes do not. The dissociation of strong electrolytes increases the total number of particles in solution, which affects colligative properties such as vapor pressure, boiling point elevation, freezing point depression, and osmotic pressure.

For example, let's compare a solution of 1 mole of sodium chloride (NaCl) to a solution of 1 mole of sucrose (C12H22O11). The sodium chloride will dissociate into Na+ and Cl- ions, which means there are now 2 particles in solution (1 Na+ and 1 Cl-) instead of just 1 molecule of sucrose. This higher particle concentration will result in a greater depression of the freezing point and elevation of the boiling point compared to the sucrose solution.

In summary, the presence of a strong electrolyte increases the number of particles in solution, leading to greater deviations in colligative properties compared to the same number of moles of a non-electrolyte solute.

Learn more about Colligative properties here:

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How many subshells in 4s

Answers

Answer:

hhjkjggghjjjjjj

Explanation:

vbjjkkkkkkkj

You need to prepare an acetate buffer of pH 5.47 from a 0.809 M acetic acid solution and a 2.20 M KOH solution. If you have 680 mL of the acetic acid solution, how many milliliters of the KOH solution do you need to add to make a buffer of pH 5.47 ? The pa of acetic acid is 4.76. Be sure to use appropriate significant figures.

Answers

Answer:

How do u post a picture as the question