a local business was looking to hire a landscaper to work on their property. they narrowed their choices to two companies. flourish landscaping company charges a flat rate of $120 per hour. green thumb landscapers charge $70 per hour plus a $1600 equipment fee. write a system of equations representing how much each company chargers. determine and state the number of hours that must be worked for the cost of each company to be the same. if it is estimated to take at least 35 hours to complete the job, which company will be less expensive? justify your answer

Answers

Answer 1
Answer: Flourish- 120x
Green Thumb- (70x)=1600

Flourish- 120*35= $4200
Green Thumb- (70*35)+1600= $4050

It would be less expensive to hire Green Thumb Landscapers. There is a $150 difference between the two

It would take 32 hours of work for the cost to be the same for both companies

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Write an equation to represent the sentence.Nine times a number y subtracted from 85 is seven times the sum of four and y.

Bryan worked 32 hours last week. His regular hourly wage is $7.50 per hour. Calculate his gross earnings for the week.His employer deducts 7.65% of his gross pay for Social Security and Medicare 15% of his gross pay for income taxes

Bryan's net pay for the week, rounded to the nearest dollar, will be $ __________.

Answers

multiply the number of hours worked by the hourly wage.  Once you have that number multiply that by the percent deducted.  Subtract the percent deducted number from the gross pay and you have your answer.

Note: each deduction is taken out of the total gross pay.

Find the measures of the angles.A. m∠x
B. m∠y
A. m∠x = 50°
m∠y = 135°
B. m∠x = 125°
m∠y = 50°
C. m∠x = 50°
m∠y = 125°
D. m∠x = 135°
m∠y = 50°

Answers

C. m∠x=90-40=50° 
m∠y=180-55=125°

Five times the number of test tubes in a school’s chemistry lab exceeds three times the number of beakers it has by 660. The sum of two times the number of test tubes and five times the number of beakers is 450.If b is the number of beakers and t is the number of test tubes, the system of linear equations representing this situation is .
The number of beakers in the school’s lab is , and the number of test tubes in the school’s lab is .

Answers

\left\{\begin{array}{ccc}5t-3b=660&|multiply\ both\ sides\ by\ 2\n2t+5b=450&|multiply\ both\ sides\ by\ (-5)\end{array}\right\n\n\underline{+\left\{\begin{array}{ccc}10t-6b=1320\n-10t-25b=-2250\end{array}\right}\n.\ \ \ \ \ \ -31b=-930\ \ \ \ |divide\ both\ sides\ by\ (-31)\n.\ \ \ \ \ \ \ \ \ \ \ \boxed{b=30}\n\nsubtitute\ the\ value\ of\ b\ to\ the\ second\ equation:\n\n2t+5\cdot30=450\n2t+150=450\ \ \ \ |subtract\ 150\ from\ both\ sides\n2t=300\ \ \ \ \ |divide\ both\ sides\ by\ 2\n\boxed{t=150}

Answer:
The number of beakers in the school’s lab is 30, and the number of test tubes in the school’s lab is 150.

An automobile engineer is redesigning a conical chamber that was originally specified to be 12 inches long with a circular base of diameter 5.7 inches. In the new design, the chamber is scaled by a factor of 1.5.

Answers

Answer:

The volume of the original chamber is 102.02cubic inches. This is 242.47 cubic inches less than the volume of the new chamber.

Hope this helps! I got it right on the Plato/Edmentum mastery test ♡

You can figure out the new cone or get the volume of the original cone and use the fact that if two objects are proportional in their dimensions, then the volume is proportional to the cube of the ratio of any of their lengths. E.G., doubling a sphere diameter increases the volume by 2 cubed = 8.

Solve the following equation for t.

−2t^2+t+28=0

Answers

Hello,

-2t²+t+28=0
==>2t²-t-28)=0
==>2t²-8t+7t-28=0
==>2t(t-4)+7(t-4)=0
==>(t-4)(2t+7)=0
==>t=4 or t=-7/2

Final answer:

The solution to the equation -2t^2 + t + 28 = 0 is found by applying the quadratic formula. Upon simplification, the possible values for 't' are 4 and -3.5.

Explanation:

The subject of the question is Mathematics and it is related to the concept of Quadratic Equations. Then, we are given the quadratic equation -2t^2 + t + 28 = 0 and asked to solve for 't'. We can solve quadratic equations using quadratic formula which is given by -b ± √(b^2 - 4ac) / 2a.

  1. First, identify the coefficients. In this equation the coefficients are: a=-2, b=1, and c=28
  2. Then Substitute these coefficients into the quadratic formula: t = [ -b ± sqrt (b^2 - 4ac) ] / 2a
  3. This gives: t = [ -1 ± sqrt ((1)^2 - 4*(-2)*28) ] / 2*(-2)
  4. Simplifying further gives: t = [ -1 ± sqrt (1 + 224)] / -4
  5. So, the possible values of t are:   t = [ -1 ± sqrt ( 225 ) ] / -4
  6. Finally, we get the solutions:  t = [ -1 ± 15 ] / -4  
  7. This simplifies to t = 4 or t = -3.5

Learn more about Quadratic Equations here:

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A number is multiplied by 8 , and that product is added to 2 . the sum is equal to the product of 2 and 21 . find the number.

Answers

number—> x
8x+2=2*21
8x=40
x=5