7(m-12)=5m
a) -7
b) 6
c) 42
d) -42

Answers

Answer 1

Answer: $7(m-12)=5m \n \n 7m - 84 = 5m \n \n -84 = 5m - 7m \n \n -84 = -2m \n \n (-84)/(-2) = m \n \n (84)/(2) = m \n \n 42 = m \n \n m = 42 \n \n Answer: \fbox {m = 42}$

Answer 2

Answer: 7(m-12) = 5m

7m - 84 = 5m

2m - 84 = 0

2m = 84

m = 42

The answer is C) 42

Answer:

Option: c is the correct answer.

c) 70

Step-by-step explanation:

There are two choices in the quality of the item i.e. Cotton or wool.

There are 5 choice of color.

Also there are seven sizes.

Hence, in order to find the total number of items that are needed for a complete assortment we need to use to method of permutation.

i.e. the calculation is:

$2_P_1* 5_P_1* 7_P_1\n\n\n=(2!)/((2-1)!)* (5!)/((5-1)!)* (7!)/((7-1)!)\n\n\n=(2!)/(1!)* (5!)/(4!)* (7!)/(6!)\n\n\n=2* 5* 7\n\n\n=70$

Hence, the answer is:

c) 70

There are two types in five colours so 2x5=10. There are then seven sizes of each so 7x10=70. Your answer is C.70. I really need brainliest answers.

PLEASE HELP ME !! PLEASE !!

Answers

i think that it is a ok

light travels about 186,000mi/s . The function gives the distance d(t), in , that travels in t seconds. How far does travel in 16s.

Answers

The function d(t) = 186000t gives the distance, in miles, that light travels in t seconds.

To find how far light travels in 16 seconds, we can plug in t = 16 and calculate d(16).

Using my pocket calculator, I get:
d(16) = 186000 * 16 d(16) = 2976000

So, light travels 2976000 miles in 16 seconds. That’s about 12 times the circumference of the Earth or 0.05% of a light-year.

The angle measure in degrees that corresponds to 7/10 of a circle is

Answers

Answer:

$252\°$

Step-by-step explanation:

we know that

The complete circle subtends a $360\°$

so by proportion

Find how many degrees corresponds to $7/10$ of a circle

$(360)/(1)(degrees)/(circle) =(x)/((7/10))(degrees)/(circle) \n \nx=(7/10)*360\n \nx= 252\°$

a circle contains 360º

180º = π radians

Why can't you make these simple calculations and conversions ??

(7/10) * (360) = 252º

252º/180º = x radians / π radians
solve for x...do something !!

[7π/5 radians ]

Ted throws an object into the air with an initial vertical velocity of 54 feet per second from a platform that is 40 feet above the ground. About how long will it take the object to hit the ground?

Answers

Answer:

The height of the object as a function of time is given by:

$h(t) = -16t^2+vt+h$ .....[1]

where,

h(t) is the height of the object t second after it is thrown.

v is the initial velocity

h is the initial height.

As per the statement:

Ted throws an object into the air with an initial vertical velocity of 54 feet per second from a platform that is 40 feet above the ground

⇒v = 54 ft/sec and h = 40 feet above the ground.

Substitute in [1] we have;

$h(t) = -16t^2+54t+40$

we have to find how long will it take the object to hit the ground.

Substitute h(t) = 0

then;

$-16t^2+54t+40 = 0$

⇒ $-8t^2+27t+20=0$

Factorize this equation:

$-8t^2+32t-5t+20=0$

⇒ $-8t(t-4)-5(t-4)=0$

⇒ $(t-4)(-8t-5)=0$

By zero product property we have;

t-4 = 0 and -8t-5 = 0

⇒t = 4 and -8t = 5

⇒ t= 4 and t = - 0.625

Since, time cannot be in negative;

⇒ t= 4 sec

therefore, 4 seconds will it take the object to hit the ground

PERFECT application of the general equation of things
that are moving up and down in gravity:

   H(t) = H₀ + v₀t + 1/2 g t²

t = time after the toss
H(t) = height at any time after the toss
H₀ = height from which it's tossed
v₀ = initial speed
g = acceleration of gravity

I'm going to call 'UP' = the positive direction .
So ...

H₀ = +40 ft
v₀ = +54 ft/sec
g = -32 ft/sec²

When the object hits the ground, H(t) = 0 .
So you have ...

   0 = 40 + 54 t - 16 t²

Let me re-write that for you, to make it a
little easier and more familiar:

      - 16 t² + 54 t + 40 = 0

Divide each side by -2 :    8 t²   - 27 t - 20 = 0

Now go to your toolbox, pull out your quadratic formula,
solve that quadratic equation, and you'll get the usual two
solutions.

The positive one is the one you want.

The negative one refers to time before the toss, and may be discarded.

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7(m-12)=5ma) -7b) 6c) 42d) -42

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7(m-12)=5m
a) -7
b) 6
c) 42
d) -42