The specified formula y = (x-1)(4x+2)A linear function, -4x² has a constant term of -2 and a linear term of 2x.
To determine whether the function y = (x-1)(4x+2)-4x^2 is linear or quadratic, we can analyze the equation and identify its terms.
Start with the equation:
y = (x-1)(4x+2)-4x²
Expand the equation by multiplying the terms:
y = 4x² + 2x - 4x - 2 - 4x²
Simplifying further,
y = 2x - 2.
Analyzing the equation, we can see that there is no x² term. This indicates that the function is linear.
Let's identify the terms of the equation:
Quadratic term: There is no x² term in the equation.
Linear term: The linear term is 2x.
Constant term: The constant term is -2.
Therefore, the given function y = (x-1)(4x+2)-4x² is a linear function with a linear term of 2x and a constant term of -2.
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Answer:
6s
Step-by-step explanation:
Bx+Cy=D
Solve for y
3x _ 2y = 8
Answers:
x = 4, y = 2
x = 4, y = _2
x = _2, y = 4
x = 2, y = 4
Answer:
Option A is correct.
x =4 , y = 2
Explanation:
Given the system of equation:
......[1]
.....[2]
Multiply equation [2] by 3 both sides we get;
Using distributive property:
.....[3]
Add equation [1] and [3], to get eliminate y we get;
Combine like terms we have;
Divide both sides by 11 we get;
Substitute the value of x =4 in [1] we get;
2(4) + 6y = 20
8 + 6y = 20
Subtract 8 from both sides we have;
6y = 12
Divide both sides by 6 we have;
y = 2
Therefore, the values of x and y are; 4 and 2.
Part 2: Using complete sentences, explain how plotting specific points helps graph the function and note any critical points such as its intercepts.