Answer:
See Explanation
Step-by-step explanation:
The question is incomplete, as the required data to answer the question are missing.
However, the interpretation of the question is to determine the interquartile range (IQR) of a certain dataset.
Then get the difference between the calculated IQR & Joe's data and also the difference between the calculated IQR & Sam's data
Then, make comparison
To do this, I will use the following assumed datasets.
IQR is calculated as:
is of the upper half
is of the lower half
For Joe, we have:
The median is then calculated as:
For, the lower half:
So:
For the upper half:
So:
When the same process is applied to Sam's data,
Assume that:
Hence, the IQR is 47 points less for Joe's data than Sam's
2tanx
ii.
for 0° < x < 90°
C0Sx-sinx
-
Answer:
i. 31/25
ii. 1/5
Step-by-step explanation:
you know that tanx = 3/4, so you can also find that sinx = 3/5 and cosx = 4/5. Then you can use the double angle identities to find cos2x and sin2x: cos^2(x) - sin^2(x) + 2sinxcosx and substitute the givens to get 31/25. Then, cosx - sinx is obviously 1/5.
Answer:
yes the cost is proportional to the number of tickets
Step-by-step explanation:
for each 1 ticket added, it is $12 more
you can graph it by using the equation y=12x where x is the amount of tickets and the y-intercept is (0,0)
Suppose the population of a town is 15,200 and is growing 2% each year. Write an equation to model the population growth. Predict the population after 10 years
Answer:
The equation model is P = Po * e^rt
The population after 10 years = 18, 559 (most approximately)
Step-by-step explanation:
We use formula to find the population growth.
P = Po * e^rt
Where P is the total population after t years
Po is the initial population
r = rate of growth
t = time
e = 2.71 [Euler number]
The equation model is P = Po * e^rt
Now to find the population after 10 years, we have to plug in the given values in the formula.
Given:
Po = 15, 200, r = 2% = 2/100 = 0.02, and t = 10 years
P = 15,200*e^0.02(10)
P = 15,200*2.71^0.2
P = 15,200 *1.221
P = 18, 559
Therefore, the population after 10 years = 18, 559 (most approximately)