super mario, spying a mystery block just ahead and wanting star power, takes a running leap towards the block, which is a distance of 8.2 m above mario's head. the acceleration due to gravity in the mushroom kingdom is roughly 1/5th of that on earth, gmk
Answers
The time taken by Super Mario is 2.91 seconds to reach the mystery block.
To find the time it takes for Super Mario to reach the mystery block, we can use the kinematic equation:
∆y = v0t + (1/2)at2
Where ∆y is the change in a vertical position, v0 is the initial vertical velocity, a is the acceleration due to gravity, and t is the time.
Since the mystery block is 8.2 m above Mario's head, ∆y = 8.2 m. The initial vertical velocity, v0, is 0 m/s since Mario is starting from rest. The acceleration due to gravity in the Mushroom Kingdom, gmk, is 1/5th of that on Earth, so
a = (1/5)g = (1/5)(9.8 m/s2)
a = 1.96 m/s2.
Plugging these values into the equation, we get:
8.2 m = (0 m/s)t + (1/2)(1.96 m/s2)t2
Simplifying and rearranging, we get:
t2 = (8.2 m)/(0.98 m/s2)
Taking the square root of both sides, we get:
t = √((8.2 m)/(0.98 m/s2)) = 2.91 s
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Why do objects move at constant speed
Gaya 7,5 dikerjakan pada masa sebesar 3 kg sehingga kelajuannya berubah dari 65 cm/s menjadi 15 m/s maka waktu yang dibutuhkan adalah
A student releases a block of mass m at the top of a slide of height h1. the block moves down the slide and off the end of the table of height h2, landing on the floor a horizontal distance d from the edge of the table. Friction and air resistance are negligible. The overall height H of the setup is determined by the height of the room. Therefore, if h1 is increased, h2 must decrease by the same amount so that the sum h1+h2 remains equal to H. The student wants to adjust h1 and h2 to make d as large as possible.A) 1) Without using equations, explain why making h1 very small would cause d to be small, even though h2 would be very large?2) Without using equations, explain why making h2 very small would cause d to be small, even thoughh1 would be largeB) Derive an equation for d in terms of h1, h2, m, and physical constants as appropriate.
How does wavelength relate to frequency?
B. 1.5 × 102 meters/second2
C. 78.6 meters/second2
D. 6.5 × 10-3 meters/second2
Answers
Magnitude of acceleration = (change in speed) / (time for the change) .
Change in speed = (ending speed) - (starting speed)
= zero - (43 m/s)
= -43 m/s .
Magnitude of acceleration = (-43 m/sec) / (0.28 sec)
= (-43 / 0.28) (m/sec) / sec
= 153.57... m/s²
= 1.5... x 10² m/s² .
Answer:
1.5*10^2 meters/seconds^2
Explanation:
I got 100% on my test
b. frequency.
c. speed.
d. position.
Answers
Final answer:
Moving waves can be described either as a function of time or as a function of d.position.
Explanation:
Moving waves can be described either as a function of time or as a function of position.
When described as a function of time, waves are represented by their amplitude and frequency. Amplitude is the maximum displacement of the wave from its equilibrium position, while frequency is the number of complete cycles of the wave occurring in one second.
When described as a function of position, waves are represented by their wavelength and speed. Wavelength is the distance between two consecutive points in a wave that are in phase, while speed is the rate at which the wave propagates through a medium.
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Answers
Explanation:
It is given that,
Mass of moon,
Radius of circle,
The time required for one revolution is 27.3 days, t = 27.3 days
1 day = 86400 seconds
27.3 days = 2358720 seconds
Let v is the speed of moon around the circular path. It is given by :
v = 1017.57 m/s
Let F is the centripetal force acting on the moon. It is given by :
So, the centripetal force that must act on the moon is . The gravitational force that the earth exerts on the moon at that same distance is also equal to
. Hence, this is the required solution.
312 Hz
292 Hz
412 Hz
Answers
To calculate this, we will use the following formula:
f₀ = f × v ÷ (v - v₁)
where:
f₀ - frequency heard
f - actual frequency
v - speed of sound
v₁ - speed of source
We know:
f = 312 Hz
v = 331 m/s
v₁ = 82.8 km/h = 23 m/s
We need:
f₀ = ?
f₀ = f × v ÷ (v - v₁)
⇒ f₀ = 312 Hz x 331 m/s ÷ (331 m/s - 23 m/s)
⇒ f₀ = 312 Hz × 331 m/s ÷ 308 m/s
⇒ f₀ = 335.3 Hz ≈ 335 Hz
Thus, the frequency of the horn is 335 Hz.
Answer:
335 Hz
Explanation:
100%
Answers
Answer:
KE= (1/2)mv^2
given m, the remaining components of the equation are=
1/2v^2?
Explanation:
KE= (1/2)mv^2
plug in...
=(1/2)(27 kg)(3 m/s)^2= 121.5
KE= 121.5 J
Answer:
Multiplying the mass of any student by a factor of 4.5 gives the kinetic energy of the student.
Answers
Answer:
684J
Explanation:
So basically the formula for gravitational potential energy is Mass X Gravity X height. That is G.p.e = mgh
We don't have the mass but since we have the height, we multiply directly with the height since the quantity of weight is already given.
so G.p.e = 360 X 1.9 = 684J
Note that; The answer is in joules because g.p.e is work done.
Hope that was helpful!!