Answer:
The acceleration of the skateboarder is 2.067 m/s²
Explanation:
Given;
initial velocity of the skateboarder, u = 0.8 m/s
final velocity of the skateboarder, v = 7 m/s
time of motion, t = 3 s
The acceleration of the skateboarder is given as;
Therefore, the acceleration of the skateboarder is 2.067 m/s²
B. 8
C. 4
D. 12
C. 4 beats per second is correct
Answer:
Explanation:
4 meters east
a.0.14 kg
b.0.37 kg
c.11.9 kg
d.21.82 kg
Answer:
a)0,14 kg
Explanation:
Formula to calculate the gravitational potential energy:
U= m *g*h : equation (1)
U: It's gravitational potential energy in Joules (J)
m: body mass in kilograms (kg)
g= the acceleration of gravity ()
h= the body heigt measured from the floor (m)
Known information:
U= 116.62 J
g = 9.8
h =85m
mass calculation:
We replace the known information in equation 1 :
116.62 = m*9.8*85
m =116.62/(9.8*85)
m= 0,14 kg
The mass of the ball is 0,14 kg
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