Answer:
It is easier
Explanation:
when riding a bicycle on a straight path you need to do more of the control and paddling to keep the bicycle on right motion, but round a bend, the wheels and tyres are already aligned to the bending path and you need not to do much work by controlling the wheels
B. 0.004021624m3
C. 0.002021624m3
D. 0.000010812m3
As per the question the volume of mercury is given as 0.002 m^3 at 20 degree Celsius.
We are asked to calculate the volume of the mercury at 50 degree Celsius.
This problem is based on thermal expansion of matter.
Let us consider the initial and final volume of the mercury is denoted as -
Let the initial and final temperature of the mercury is denoted as -
As per question
The change in temperature is
Mercury is a fluid.So we have to apply volume expansion of liquid .
The coefficient of of volume expansion of mercury at 20 degree Celsius is 0.00018 per centigrade.
As per volume expansion of liquid,
Here is the volume at T degree Celsius.
Hence volume at 50 degree Celsius is calculated as-
[ans]
As per the options given in the question ,option A is close to the calculated value. So option A is right.
a. 3
b. 6
c. 0
d. 12
Alisha uses wire to connect a battery, a lightbulb, and a switch, but the bulb does not light up even though the switch is in the closed position. The switch is in closed position that is why her circuit would not work. It must be open so that electrons can move along the wire and enable the lightbulb to light up.
B. positron
C. neutrino
D. helium-4
Answer:
The answer is B i just took the test and got it correct:)
Explanation:
Answer:
There are 6 Hydrogen atoms present in two molecules of Hydroxylamine.
Explanation:
Hydroxylamine is an inorganic compound having formula : NH₂OH
In one molecule of Hydroxylamine, NH₂OH there are 3 atoms of Hydrogen.
NH₂OH: 2+1 = 3
So two molecules of Hydroxylamine would contain 2 × 3 = 6 atoms of Hydrogen.
2 NH₂OH : (2×2)+(2×1) = 6
b. color-detection
c. photo-chemistry
d. spectrophotometry
Answer:
A
Explanation:
I took the test :)