If a barometer reads 772 mm hg, what is the atmospheric pressure expressed in pounds per square inch?

Answers

Answer 1

Answer: 15.23.....................

Answer 2

Answer: I think it would be 15.23 not so sure but
hope this helps! (:

Related Questions

A spring-loaded gun, fired vertically, shoots a marble 9.0 m straight up in the air. What is the marble's range if it is fired horizontally from 1.8 m above the ground?
Compare and contrast, in detail, at least two types of pluralism. Do you think the United States is becoming more pluralistic? Why or why not? How do ethnic enclaves relate to pluralism in the US?
An early model of the atom, proposed by Rutherford after his discovery of the atomic nucleus, had a positive point charge +Ze (the nucleus) at the center of a sphere of radius R with uniformly distributed negative charge −Ze. Z is the atomic number, the number of protons in the nucleus and the number of electrons in the negative sphere. Show that the electric field inside this atom is : Ein=Ze4πϵ0(1r^2−rR^3). b. What is the electric field at the surface of the atom? Is this the expected value? Explain.c. A uranium atom has Z = 92 and R = 0.10 nm. What is the electric field at r = R/2?
A plane monochromatic electromagnetic wave with wavelength ? = 3 cm, propagates through a vacuum. Its magnetic field is described byB? =(Bxi^+Byj^)cos(kz+?t)where Bx = 3.3 X 10-6 T, By = 3.9 X 10-6 T, and i-hat and j-hat are the unit vectors in the +x and +y directions, respectively.1)What is f, the frequency of this wave?GHz2)What is I, the intensity of this wave?W/m23)What is Sz, the z-component of the Poynting vector at (x = 0, y = 0, z = 0) at t = 0?W/m24)What is Ex, the x-component of the electric field at (x = 0, y = 0, z = 0) at t = 0?V/m5)Compare the sign and magnitude of Sz, the z-component of the Poynting vector at (x=y=z=t=0) of the wave described above to the sign and magnitude of SIIz, the z-component of the Poynting vector at (x=y=z=t=0) of another plane monochromatic electromagnetic wave propagating through vaccum described by:B? =(BIIxi^?BIIyj^)cos(kz??t)where BIIx = 3.9 X 10-6 T, BIIy = 3.3 X 10-6 T, and i-hat and j-hat are the unit vectors in the +x and +y directions, respectively.SIIz < 0 and magnitude(SIIz) =/ (does not equal sign) magnitude(Sz)SIIz < 0 and magnitude(SIIz) = magnitude(Sz)SIIz > 0 and magnitude(SIIz) =/ (does not equal sign) magnitude(Sz)SIIz > 0 and magnitude(SIIz) = magnitude(
*Which of the following cannot be an example of projectile motionA. A football flying through the airB. An apple falling from a treeC. A pencil rolling on the groundD.A rocket dropping from its maximum height

We start with 5.00 moles of an ideal monatomic gas with an initial temperature of 129 ∘C. The gas expands and, in the process, absorbs an amount of heat equal to 1180 J and does an amount of work equal to 2160 J . What is the final temperature Tfinal of the gas? Use R = 8.3145 J/(mol⋅K) for the ideal gas constant.

Answers

The final temperature of an ideal monatomic gas with an initial temperature of 128°C. is 114.53°C.

From the first law of thermodynamics,

ΔU=Q - W

Where,

ΔU - change in internal energy

Q - energy absorbed

W - work

So,

ΔU = 1180 J - 2020 J

ΔU = -840 J

From ideal gas law

$\bold {\Delta U = \frac 32n R (T_2- T_1)}}\n\n\bold {T_ 2 = \frac {2\Delta U}{3nR} +T_1}$

Where, T2 is the final temperature,

n- moles of gas

R - gas constant

T1 - initial temperature,

Put the values in the equation

$\bold {T_ 2 = \frac {2* -840\ J )}{3* 5 * 8.314\ J/mol.K} + 128^oC}\n\n\bold {T_2 = 114.53 ^oC}$

Therefore, the final temperature of an ideal monatomic gas with an initial temperature of 128°C. is 114.53°C.

To know more about ideal gas law,

brainly.com/question/6534096

The solution is in the attachment

Optical astronomers need a clear, dark sky to collect good data. Explain why radio astronomers have no problem observing in the UK where it is often very cloudy.

Answers

Answer:

In the clarification portion elsewhere here, the definition of the concern is mentioned.

Explanation:

So like optical telescopes capture light waves, introduce it to concentrate, enhance it, as well as make it usable through different instruments via study, so radio telescopes accumulate weak signal light waves, introduce that one to focus, enhance it, as well as make this information available during research. To research naturally produced radio illumination from stars, galaxies, dark matter, as well as other natural phenomena, we utilize telescopes.

Optical telescopes detect space-borne visible light. There are some drawbacks of optical telescopes mostly on the surface:

Mostly at night would they have been seen.
Unless the weather gets cloudy, bad, or gloomy, they shouldn't be seen.

Although radio telescopes monitor space-coming radio waves. Those other telescopes, when they are already typically very massive as well as costly, have such an improvement surrounded by optical telescopes. They should be included in poor weather and, when they travel through the surrounding air, the radio waves aren't obscured by clouds. Throughout the afternoon and also some at night, radio telescopes are sometimes used.

A helicopter is hovering above the ground. Jim reaches out of the copter (with a safety harness on) at 180 m above the ground. A package is launched upward, from a point on a roof 10 m above the ground. The initial velocity of the package is 50.5 m/s. Consider all quantities as positive in the upward direction. Does Jim Bond have a chance to catch the package? (calculate how high will it go)

Answers

Answer:

The maximum height of the package is 140 m above the ground. Jim Bond will not catch the package.

Explanation:

Hi there!

The equation of height and velocity of the package are the following:

h = h0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

h = height of the package at time t.

h0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² because we consider the upward direction as positive).

v = velocity of the package at a time t.

First, let´s find the time it takes the package to reach the maximum height. For this, we will use the equation of velocity because we know that at the maximum height, the velocity of the package is zero. So, we have to find the time at which v = 0:

v = v0 + g · t

0 = 50.5 m/s - 9.8 m/s² · t

Solving for t:

-50.5 m/s / -9.81 m/s² = t

t = 5.15 s

Now, let´s find the height that the package reaches in that time using the equation of height. Let´s place the origin of the frame of reference on the ground so that the initial position of the package is 10 m above the ground:

h = h0 + v0 · t + 1/2 · g · t²

h = 10 m + 50.5 m/s · 5.15 s - 1/2 · 9.81 m/s² · (5.15 s)²

h = 140 m

The maximum height of the package is 140 m above the ground. Jim Bond will not catch the package.

A cat leaps to catch a bird. If the cat's jump was at 60.0° off the ground and its initial velocity was point of its trajectory? 0.30 m 3.44 m/s, what is the highest O 13.76 m 0.45 m 0.90 m

Answers

Answer:

The highest of its trajectory = 0.45 m

Option C is the correct answer.

Explanation:

Considering vertical motion of cat:-

Initial velocity, u = 3.44 sin60 = 2.98 m/s

Acceleration , a = -9.81 m/s²

Final velocity, v = 0 m/s

We have equation of motion v² = u² + 2as

Substituting

v² = u² + 2as

0² = 2.98² + 2 x -9.81 x s

s = 0.45 m

The highest of its trajectory = 0.45 m

Option C is the correct answer.

A relaxed biceps muscle requires a force of 25.4 N for an elongation of 3.20 cm; under maximum tension, the same muscle requires a force of 520 N for the same elongation. Find Young's modulus (Pa) for the muscle tissue under each of these conditions if the muscle can be modeled as a uniform cylinder with an initial length of 0.200 m and a cross-sectional area of 50.0 cm2.

Answers

Answer:

Y = 31750 Pa = 31.75 KPa (For 24.5 N force)

Y = 312500 Pa = 312.5 KPa (For 250 N force)

Explanation:

Since the elongation is constant. Therefore, the strain will remain the same in both cases:

$Strain = (Elongation)/(Original\ Length)\n\nStrain = (0.032\ m)/(0.2\ m)\n\nStrain = 0.16$

FOR A FORCE OF 25.4 N:

$Stress = (Force)/(Area)\n\nStress = (25.4\ N)/(0.005\ m^2)\n\nSress = 5080\ Pa = 5.08\ KPa$

Now, for Young's Modulus:

$Y = (Stress)/(Strain)\n\nY = (5080\ Pa)/(0.16)$

Y = 31750 Pa = 31.75 KPa

FOR A FORCE OF 520 N:

$Stress = (Force)/(Area)\n\nStress = (250\ N)/(0.005\ m^2)\n\nSress = 50000\ Pa = 50\ KPa$

Now, for Young's Modulus:

$Y = (Stress)/(Strain)\n\nY = (50000\ Pa)/(0.16)$

Y = 312500 Pa = 312.5 KPa

The surface tension of a liquid is to be measured using a liquid film suspended on a U-shaped wire frame with an 12-cm-long movable side. If the force needed to move the wire is 0.096 N, determine the surface tension of this liquid in air.

Answers

Answer:

σ = 0.8 N/m

Explanation:

Given that

L = 12 cm

We know that 1 m = 100 cm

L = 0.12 m

The force ,F= 0.096 N

Lets take surface tension = σ

We know that surface tension is given as

$\sigma =(F)/(L)\n\sigma =(F)/(L)\nNow\ by\ putting\ the\ values\n\sigma =(0.096)/(0.12)\ N/m\n\sigma=0.8\ N/m$

Therefore the surface tension σ will be 0.8 N/m .

σ = 0.8 N/m

Final answer:

The surface tension of the liquid in air is 0.8 N/m.

Explanation:

To determine the surface tension of the liquid, we need to use the formula F = yL, where F is the force needed to move the wire, y is the surface tension, and L is the length of the wire. In this case, F = 0.096 N and L = 12 cm. We can rearrange the formula to solve for y: y = F / L. Plugging in the values, we get y = 0.096 N / 0.12 m = 0.8 N/m. So, the surface tension of the liquid in air is 0.8 N/m.

Learn more about Surface tension here:

brainly.com/question/11348644

#SPJ12

Other Questions

As an object in motion becomes heavier, its kinetic energy _____. A. increases exponentially B. decreases exponentially C. increases proportionally D. decreases proportionally

Guitar string has an overall length of 1.22 m and a total mass of 3.5 g before being strung on a guitar. Once it is used on the guitar, there is a distance of 70 cm between fixed end points. The guitar string is tightened to a tension of 255 N.What is the frequency of the fundamental wave on the guitar string?

Give a quantitative definition of being in contact.

On a hot summer day in the state of Washington while kayaking, I saw several swimmers jump from a railroad bridge into the Snohomish River below. The swimmers stepped off the bridge, and I estimated that they hit the water 2.00 s later. A)How high was the bridge?B)How fast were the swimmers moving when they hit the water?C)What would the swimmer's drop time be if the bridge were twice as high?