Answer: formula units
Explanation:
so lets start off by looking at what we have. we have g of LiCl
which is called Lithium Chloride. in order to convert g to moles, we divide the g by the molar mass of Lithium Chloride.
whip out that HANDY DANDY PERIODIC TABLE man the PERIODIC TABLE WILL SAVE YOUR LIFE SOME DAY! someone will walk up to you all mean, and youll be like, "what, you tryna MUG me?" and then you whack 'em with the periodic table like BAM! GOTTEM!
okay so lets look at the periodic table and we notice that the atomic mass of Lithium is 6.941 and the atomic mass of Chlorine is 35.453. notice that in LiCl there is only one of each. so lets add 6.941 + 35.453 = 42.394 g/mol.
now look at what we were given: converting the given quantity to standard format instead of scientific format, we have 0.0073 grams of lithium chloride. we can convert this to moles by dividing it by its molar mass which is 42.394.
now lets use AVOCADOS NUMBER i mean AVOGADROS NUMBER!! which is
multiply and we get formula units.
if you want to be specific about the significant figures, notice that the given quantity in the question only has two significant figures. so we can alter our final answer to only have two sig figs. lets change it: formula units
Answer:
Redox reactions involve an oxidation reaction coupled with a reduction reaction.
Explanation:
A redox reaction is called like that because it involves a substance that is reducing and a substance that is oxidating, so it is Re-dox, this means that all of the chemicals reactions that involve a substance that looses an electron, are redox reactions, they are present in almost all of chemistry, from syntetic to biological chemistry, so the only correct option would be:
Redox reactions involve an oxidation reaction coupled with a reduction reaction.
Answer: An oxidation reaction is defined as the when in a reaction the oxidation number of a species involved increased, and reduction reaction is reversed, it when the oxidation number of a species is decreased. And a redox reaction is in which both of oxidation and reduction reaction takes place simultaneosly. Because chemical reaction follows the law of conservation of mass.
Answer:
12 mol CO₂
General Formulas and Concepts:
Atomic Structure
Stoichiometry
Explanation:
Step 1: Define
Identify
[rxn] 6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂
[Given] 2 mol C₆H₁₂O₆
[Solve] mol CO₂
Step 2: Identify Conversions
[rxn] 6CO₂ → C₆H₁₂O₆
Step 3: Convert
Answer:
The statements that describe Mg are:
1. is very reactive as a metal
2. forms a basic solution in water
3. is found in nature only combined with other elements
Explanation:
Magnesium is a s-block chemical element that belongs to group 2 and period 3 of the periodic table. It is a reactive alkaline earth metal that exists in nature only in the combined state with elements such as carbon, calcium and oxygen.
Magnesium reacts with water at room temperature, to give strongly basic metal oxide of the formula, MgO, which forms a basic solution in water.
It also reacts vigorously with halogens such as chlorine and bromine, to form salts.
Magnesium is a highly reactive alkaline earth metal that forms a basic solution in water and can react vigorously with alkali metals to form salts. It consists of diatomic molecules in its elemental form.
Magnesium is one of the alkaline earth metals, which are found in Group 2 of the periodic table. It is a highly reactive metal that forms a basic solution in water and can react vigorously with alkali metals to form salts. Magnesium also consists of diatomic molecules in its elemental form. However, it is not one of the least reactive elements; rather, it is one of the more reactive elements in Group 2.
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Answer : The number of drops pf the stock solution mist be added are, 50 drops.
Explanation :
As we are given that the concentration of stock solution 1 mg/mL and pipette delivers 20 drops/mL. That means,
1 mg of epinephrine = 1 mL = 20 drops
The final volume of Locke's solution = 25 mL
and the final concentration needed =
As, 1 mL of solution contains =
So, 25 mL of solution contains =
Conversion used :
Now we have to determine the number of drops needed.
As, 1 mg of epinephrine contains 20 drops.
So, 2.5 mg of epinephrine contains 2.5 × 20 = 50 drops.
Therefore, the number of drops pf the stock solution mist be added are, 50 drops.
If you want to achieve a final concentration of 100 µg/mL of epinephrine in a 25 mL solution, when using a stock solution of 1 mg/mL and a pipette that delivers 20 drops/mL, you need to add 50 drops of your stock solution.
Since we are asked to find the number of drops of stock solution required to achieve a final concentration of 100 µg/mL in a 25 mL solution, the first step is to convert the concentration of the stock solution to the same units, µg/mL. Hence, 1 mg/mL is equal to 1000 µg/mL. Further, we know that 1 mL of the stock solution contains 1000 µg of epinephrine, and our pipette delivers 20 drops/mL, so 1 drop of stock solution contains 1000 µg / 20 drops = 50 µg. Thus, if we need a 100 µg/mL concentration in 25 mL, we need a total of 100 µg/mL * 25 mL = 2500 µg of epinephrine. Therefore, to achieve this, we must add 2500 µg / 50 µg/drop = 50 drops of our stock solution. Hence,
50 drops
of the stock solution should be added to achieve the desired concentration.
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Zn+2 (aq) + 2e− → Zn(s) Eo=−0.763V
Answer the following questions about this cell.
Write a balanced equation for the half-reaction that happens at the cathode.
Write a balanced equation for the half-reaction that happens at the anode.
Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous as written. Do you have enough information to calculate the cell voltage under standard conditions
Answer: The reaction is spontaneous and there is not enough information to calculate the cell voltage.
Explanation:
The substance having highest positive reduction potential will always get reduced and will undergo reduction reaction.
Oxidation reaction occurs at anode and reduction reaction occurs at cathode.
The half reactions for the cell occurring at cathode follows:
The half reactions for the cell occurring at anode follows:
( × 2)
The balanced equation for the overall reaction of the cell follows:
For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative.
Relationship between standard Gibbs free energy and standard electrode potential follows:
For a reaction to be spontaneous, the standard electrode potential must be positive.
To calculate the of the reaction, we use the equation:
Putting values in above equation, we get:
As, the standard electrode potential of the cell is coming out to be positive, the reaction is spontaneous in nature.
As, the concentrations and partial pressures are not given. So, there is not enough information to calculate the cell voltage.
Hence, the reaction is spontaneous and there is not enough information to calculate the cell voltage.