To plan ahead using REPS and Checks, choose the minimum space cushion needed to maintain folloying distance traveling at 25 MPH (for a cargo van)?

Answers

Answer 1
Answer:

The minimum space cushion defines the required amount of space which vehicles should maintain in other to afford them the time and space to gain control in emergency scenarios. Hence, the minimum space cushion required in the scenario is 4 seconds.

In cases of mishaps or accidents, the space cushion might just afford other cars the space to maneuver their way to safety rather than being caught up in the collison or accident.

The required space cushion in most scenario is usually between 2 - 5 seconds, with additional space afforded depending on the length and type of the vehicle.

Therefore, to ensure safety, the required minimum spacecushion to be left when driving being a cargo van traveling at a speed of 25mph is 4 seconds.

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Answer 2
Answer:

Final answer:

In order to ensure safety while driving a cargo van at 25 MPH, the driver should maintain a space cushion of about 3-4 van lengths, which accounts for speed, reaction time, and distance needed to apply brakes and avert a collision.

Explanation:

The subject of your question revolves around optimal space cushion required for safety while driving a cargo van at the speed of 25 MPH, adhering to REPS (Reference point, Eye lead time, Posting and Scanning) and Checks (Check side mirrors and Rearview mirror every 5-8 seconds). This question falls under the domain of physics, as it involves velocity (speed of the vehicle), distance (space cushion), and time.

As a general rule of thumb, for every 10 miles per hour, a driver should ideally stay approximately one car length away from the car in front of them. Therefore, at 25 MPH, the driver should maintain a distance of at least 2.5 car lengths. In the case of a cargo van, which is typically larger than a regular car, this distance should ideally be increased to 3-4 van lengths to ensure safe stopping distance and reaction time in case of any sudden stoppage by the vehicle ahead.

Learn more about Driving Safety here:

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Answers

the answer is D jessim should spin the glove quickly while walking in a circle around nancy.

Answer:

The answer is D jessim should spin the glove quickly while walking in a circle around nancy.

Explanation:

Three different samples were weighed using a different type of balance for each sample. The three were found to have masses of 0.6160959 kg, 3.225 mg, and 5480.7 g. The total mass of the samples should be reported as?

Answers

Answer:

6.1 kg

Explanation:

To obtain the total mass of the sample, we must first express each mass of the sample in the same unit of measurement.

Since the SI unit of mass is kilogram (kg), we shall express the total mass of the samples in kilogram (kg).

This is illustrated below:

Mass of the samples are:

M1 = 0.6160959 kg

M2 = 3.225 mg

M3 = 5480.7 g.

Conversion of 3.225 mg to kg

1 mg = 1×10¯⁶ kg

Therefore,

3.225 mg = 3.225 × 1×10¯⁶

3.225 mg = 3.225×10¯⁶ kg

Conversion of 5480.7 g to kg

1000 g = 1 kg

Therefore,

5480.7 g = 5480.7 /1000

5480.7 g = 5.4807 kg

Thus, we can obtain the total mass of the samples as follow:

M1 = 0.6160959 kg

M2 = 3.225×10¯⁶ kg

M3 = 5.4807 kg

Total mass =?

Total mass = M1 + M2 + M3

Total mass = 0.6160959 + 3.225×10¯⁶ + 5.4807

Total mass = 6.096799125 ≈ 6.1 kg

Therefore, the total mass of the samples is approximately 6.1 kg.

Write the full ionic equation and net ionic equation for sodium dihydrogen phosphate + calcium carbonate, sodium oxilate + calclium carbonate, and sodium hydrogen phosphate + calcium carbonate

Answers

Answer:

Sodium dihydrogen phosphate + calcium carbonate

Full ionic equation

2 Na⁺(aq) + 2 H₂PO₄⁻(aq) + CaCO₃(s) ⇄ 2 Na⁺(aq) + CO₃²⁻(aq) + Ca(H₂PO₄)₂(s)

Net ionic equation

2 H₂PO₄⁻(aq) + CaCO₃(s) ⇄ CO₃²⁻(aq) + Ca(H₂PO₄)₂(s)

Sodium oxalate + calcium carbonate

Full ionic equation

2 Na⁺(aq) + C₂O₄²⁻(aq) + CaCO₃(s) ⇄ 2 Na⁺(aq) + CO₃²⁻(aq) + CaC₂O₄(s)

Net ionic equation

C₂O₄²⁻(aq) + CaCO₃(s) ⇄ CO₃²⁻(aq) + CaC₂O₄(s)

Sodium hydrogen phosphate + calcium carbonate

Full ionic equation

2 Na⁺(aq) + HPO₄²⁻(aq) + CaCO₃(s) ⇄ CaHPO₄(s) + 2 Na⁺(aq) + CO₃²⁻(aq)

Net ionic equation

HPO₄²⁻(aq) + CaCO₃(s) ⇄ CaHPO₄(s) + CO₃²⁻(aq)

Explanation:

Let's consider two kind of equations:

  • Full ionic equation: includes all ions and species that do not dissociate in water.
  • Net ionic equation: includes only ions that participate in the reaction (not spectator ions) and species that do not dissociate in water.

A Se ion has a mass number of 79 and a charge of − 2 . Determine the number of neutrons, protons, and electrons in this ion.

Answers

Answer:

45, 34, 36

Explanation:

The atomic number of Selenium is 34 and the atomic number is 79 also the atom has gained two electron denoted by superscript -2

number of neutrons = mass number - atomic number = 79 - 34 = 45

number of proton = atomic number = 34

number of electron = 34 + 2 = 36. In an atom the number of proton is always equal to number of electron if the atom is neutral but this Se atom has gain two so the number of electron will exceed the number of proton by 2.

The Se ion has 34 protons, 45 neutrons and 36 electrons.

The mass number (A) is given by the sum of the protons and neutrons:

A = protons + neutrons = 79

From the Periodic Table, we can see that the chemical element Selenium (Se) has an atomic number (Z) of 34, which is equal to the number of protons of a chemical element:

Z = protons = 34

Thus, we calculate the number of neutrons as the difference between A and Z:

neutrons = A - Z = 79 - 34 = 45

In a neutral atom (without electric charge), the number of electrons is equal to the number of protons. Since Se ion has 34 protons and a charge of -2, it has 34 electrons to be neutral and then it gained 2 electrons, so the number of electrons is equal to:

electrons = protons + 2 = 34 + 2 = 36

You can learn more about mass number, atomic number and subatomic particles here:

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Given these reactions, X ( s ) + 1 2 O 2 ( g ) ⟶ XO ( s ) Δ H = − 668.5 k J / m o l XCO 3 ( s ) ⟶ XO ( s ) + CO 2 ( g ) Δ H = + 384.3 k J / m o l what is Δ H for this reaction? X ( s ) + 1 2 O 2 ( g ) + CO 2 ( g ) ⟶ XCO 3 ( s )

Answers

Answer: The \Delta H^o_(rxn) for the reaction is -1052.8 kJ.

Explanation:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

X(s)+(1)/(2)O_2(g)+CO_2(g)\rightarrow XCO_3(s)      \Delta H^o_(rxn)=?

The intermediate balanced chemical reaction are:

(1) X(s)+(1)/(2)O_2(g)\rightarrow XO(s)    \Delta H_1=-668.5kJ

(2) XCO_3(s)\rightarrow XO(s)+CO_2     \Delta H_2=+384.3kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_(rxn)=[1* \Delta H_1]+[1* (-\Delta H_2)]

Putting values in above equation, we get:

\Delta H^o_(rxn)=[(1* (-668.5))+(1* (-384.3))=-1052.8kJ

Hence, the \Delta H^o_(rxn) for the reaction is -1052.8 kJ.

Which description best characterization the motion of particles in a solid

Answers

Answer:

D) Vibrating in fixed position

Explanation:

just took it on edge 2020

Are there any choices? Because from what the question is it seems like we need choices to help