Answer:
This is required answer.
Explanation:
Given that,
1,2,3,4,5,6-hexachlorocyclohexane
(a). We need to draw 1,2,3,4,5,6-hexachlorocyclohexane with all the chloro groups in axial positions
Using given data
We draw 1,2,3,4,5,6-hexachlorocyclohexane with all the chloro groups in axial positions.
When we say that all the chloro groups in axial position that means axial bonds are vertical.
(b). We need to draw 1,2,3,4,5,6-hexachlorocyclohexane with all the chloro groups in equatorial positions
Using given data
We draw 1,2,3,4,5,6-hexachlorocyclohexane with all the chloro groups in equatorial positions.
When we say that all the chloro groups in equatorial position that means axial bonds are horizontal.
Hence, This is required answer.
Due to the conjugate base of the hydrogen atom is aromatic, Hb is regarded as the most acidic. Because the conjugate base of the hydrogen atom Hc is anti-aromatic, it is the least acidic.
The correct options are:
(A) - (a)
(B) - (d)
The hydrogen connected at the heptatriene's tertiary position (at the 7-methyl) would be particularly acidic, as its removal would leave a positive charge that could be transported around the ring via resonance.
The hydrogen connected to the pentadiene (5-methyl) at the tertiary position would not be acidic, as removing it would result in an anti-aromatic structure.
Thus, the least acidic H atom is Hc and the most acidic H atom is Hb.
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Answer:
When the graduation line denotes the volume contained in the calibrated vessel, the ware is marked “TC”. When the graduation line indicates the volume delivered from the vessel, the ware is marked “TD”.
Moles of any substance is given by the molar mass and the mass. The volume of EDTA required to titrate is 3.16 mL and the volume of zinc required to titrate is 22.8 mL.
Molarity is the property of the solution that gives the concentration of the solute present in the solution.
Given,
Mass of cobalt sulfate = 1.697 gm
The molar mass of cobalt sulfate = 155 g/mol
In the first part, the volume of the aliquot is 25 mL and the molarity is 0.08640 M.
The reaction is shown as:
Co²⁺ + H₄Y → CoH₂Y + 2H⁺
Moles of cobalt: n = 0.001694 ÷ 155 = 0.0000109 moles
In 25 ml aliquot moles of cobalt are, 0.000273 moles.
The volume of EDTA solution is calculated as:
V = moles ÷ Molarity
= 0.000273 mole ÷ 0.0864 mol/ L
= 3.16 mL
Hence, 3.16 mL of EDTA is required.
For the second part, moles of EDTA are calculated as:
n = 0.008640 × 0.050 = 4.32 ×10⁻⁴
In a 25 mL, sample moles of EDTA are 2.16 × 10⁻⁴ moles.
Excess moles of EDTA in the solution:
0.000432 - 0.000216 = 0.000216 moles
The volume of EDTA is calculated as:
V = 0.000216 ÷ 0.009450
= 0.0228 L
Hence, 22.8 mL of zinc is required.
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Answer:
the answer is in the screenshot
Explanation:
hope this helps
Answer:
1. Mass of Carbon is 56.89g
2. Mass of Hydrogen is 6.33g
3. Mass of Oxygen is 75.88
Explanation:
The following were obtained from the question.
Mass of the compound = 139.1g
Mass of CO2 produced = 208.6g
Mass of H2O produced = 56.93
1. Determination of mass of Carbon (C). This is illustrated below:
Molar Mass of CO2 = 12 + (2x16) = 44g/mol
Mass of C = 12/44 x 208.6
Mass of C = 56.89g
2. Determination of the mass of Hydrogen (H). This is illustrated below:
Molar Mass of H2O = (2x1) + 16 = 18g/mol
Mass of H = 2/18 x 56.93
Mass of H = 6.33g
3. Determination of the mass of oxygen (O).
This is illustrated below:
Mass of the compound = 139.1g
Mass of C = 56.89g
Mass of H = 6.33g
Mass of O = Mass of compound - (mass of C + Mass of H)
Mass of O = 139.1 - (56.89 + 6.33)
Mass of O = 139.1 - 63.22
Mass of O = 75.88
B- NaCl
C- CaS
D- MgF2
E - SO2
Answer:
A
Explanation:
Thus is because both the elements are non metals.
Answer:
SO2
Explanation:
SO2 is covalent since it is formed by the sharing of electrons between sulphur and oxygen also both the sulphur and oxegen atoms are non metal.
and we know that non-metal non-metal always bond together via covelent bonding
Answer:
K₂O
Explanation:
Given parameters:
Mass of K = 36.7g
Mass of O = 7.51g
Unknown:
Empirical formula of the compound
Solution:
The empirical formula of a compound is it's simplest ratio by which the elements in the compound combines. It differs from the molecular formula that shows the actual atomic ratios.
To find the empirical formula, follow this process;
Elements K O
Mass 36.7 7.51
Molar
mass 39 16
Number of
moles 36.7/39 7.51/16
0.94 0.47
Divide by
the smallest 0.94/0.47 0.47/0.47
2 1
Empirical formula is K₂O
The empirical formula of the compound composed of 36.7 g of potassium and 7.51 g of oxygen is K2O.
To determine the empirical formula of a compound, we need to find the ratio of the elements present. In this case, we have 36.7 g of potassium and 7.51 g of oxygen. To find the ratio, we need to convert these masses to moles by dividing them by the molar masses of potassium and oxygen. The molar mass of potassium is 39.10 g/mol and the molar mass of oxygen is 16.00 g/mol. Dividing the masses by the molar masses gives us 0.939 mol potassium and 0.469 mol oxygen. The ratio between these two elements is approximately 2:1, so the empirical formula of the compound is K2O.
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