When an electron moves up to higher energy levels, the atom Choose... a photon of light whereas the atom Choose... a photon of light when an electron drops to a lower energy level. The photons emitted from an atom appear as

Answers

Answer 1
Answer:

Answer:

Explanation:

When an electron moves from a lower energy level to a higher energy level, energy is absorbed by the atom. When an electron moves from a higher to a lower energy level, energy is released and photon is emitted.

this emitted photon is depicted as a small wave-packet being expelled by the atom in a well-defined direction.


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(ASAP) (FOOD SCIENCE) how does the addition of starches provide structure to a food product

Answers

Answer: In addition to building texture, starches are used to contribute stability to food products. This often takes the form of holding water. As previously mentioned, gelatinized starch molecules tend to reassociate with one another.

How many moles of Al are necessary to form 23.6 g of AlBr₃ from this reaction: 2 Al(s) + 3 Br₂(l) → 2 AlBr₃(s) ?

Answers

0.085 moles of Al are required to form 23.6 g of AlBr₃.

Let's consider the following balanced equation for the synthesis reaction of AlBr₃.

2 Al(s) + 3 Br₂(l) → 2 AlBr₃(s)

First, we will convert 23.6 g to moles using the molar mass of AlBr₃ (266.69 g/mol).

23.6 g * (1mol)/(266.69g) = 0.0885 mol

The molar ratio of Al to AlBr₃ is 2:2. The moles of Al required to form 0.0885  moles of AlBr₃ are:

0.0885molAlBr_3 * (2molAl)/(2molAlBr_3) = 0.0885molAl

0.085 moles of Al are required to form 23.6 g of AlBr₃.

You can learn more about stoichiometry here: brainly.com/question/22288091

Answer:

0.088 mole of Al.

Explanation:

First, we shall determine the number of mole in 23.6 g of AlBr₃.

This is illustrated below:

Mass of AlBr₃ = 23.6 g

Molar Mass of AlBr₃ = 27 + 3(80) = 267 g/mol

Mole of AlBr₃ =.?

Mole = mass/Molar mass

Mole of AlBr₃ = 23.6 / 267

Mole of AlBr₃ = 0.088 mol

Next, we shall writing the balanced equation for the reaction.

This is given below:

2Al(s) + 3Br₂(l) → 2AlBr₃(s)

From the balanced equation above,

2 moles of Al reacted with 3 mole of Br₂ to 2 moles AlBr₃.

Finally, we shall determine the number of mole of Al needed for the reaction as follow:

From the balanced equation above,

2 moles of Al reacted to 2 moles AlBr₃.

Therefore, 0.088 mole of Al will also react to produce 0.088 mole of AlBr₃.

A piston confines 0.200 mol Ne(g) in 1.20 at 25 degree C. Two experiments are performed. (a) The gas is allowed to expand through an additional 1.20 L against a constant of 1.00atm. (b) The gas is allowed to expand reversibly and isothermally to the same final volume. Please calculate the work done by the gas system in these two processes, respectively. Which process does more work? (revised from 6/e exercise 8.11) Please show calculation details.

Answers

Answer:

The second experiment (reversible path) does more work

Explanation:

Step 1:

A piston confines 0.200 mol Ne(g) in 1.20L at 25 degree °C

(a) The gas is allowed to expand through an additional 1.20 L against a constant of 1.00atm

Irreversible path: w =-Pex*ΔV

⇒ with Pex = 1.00 atm

⇒ with ΔV = 1.20 L

W = -(1.00 atm) * 1.20 L

W = -1.20L*atm *101.325 J /1 L*atm = -121.59 J

(b) The gas is allowed to expand reversibly and isothermally to the same final volume.

W = -nRTln(Vfinal/Vinitial)

⇒ with n = the number of moles = 0.200

⇒ with R = gas constant = 8.3145 J/K*mol

⇒ with T = 298 Kelvin

⇒ with Vfinal/Vinitial  = 2.40/1.20 = 2

W = -(0.200mol) * 8.3145 J/K*mol *298K *ln(2.4/1.2)

W = -343.5 J

The second experiment (reversible path) does more work

Blood samples for research or medical tests sometimes have heparin added. Why is this done? ​

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It is essential for accurate results that the correct volume of blood is sampled to achieve a correct concentration (and dilution, if liquid heparin is used), and that blood and anticoagulant are well mixed immediately after sampling.

Calculate the molar mass of each compound given below. c4h4

Answers

When asked to find molar mass, we first need to calculate the total number of atoms of each element in the compound.

In C_(4)  H_(4), we see that there are 4 Carbons and 4 Hydrogens.

We then need to look up the atomic mass of each of these elements, which is found on the periodic table.

For carbon, the atomic mass is 12.01g
For hydrogen, the atomic mass is 1.008g

Then we multiply the number of atoms in the element by the atomic mass of the element:

C: 4*12.01g=48.04g
H: 4*1.008g=4.032g

And then we need to add these two values together to get the molar mass of the compound:

48.04g+4.032g=52.072g

So now we know that the molar mass of C_(4)  H_(4) is 52.072g.

Which of the following describes the correct order for relative solubility of minerals in sedimentary rocks? a. Evaporate minerals, quartz, and calcite all have the same relative solubility.
b. Evaporate minerals are more soluble than calcite and quartz.
c. Evaporate minerals are more soluble than quartz and less soluble than calcite.
d. Evaporate minerals are less soluble than quartz and calcite.

Answers

Answer:

Evaporate minerals are more soluble than calcite and quartz.

Explanation:

Evaporate minerals are the water soluble minerals which at higher concentration precipitate out and crystallized forming rocks.

example of chemicals present are:

chlorides and sulphates.

Quartz is silica (very less soluble, or insoluble)

Calcite is calcium carbonate, again an insoluble salt.

Thus

Evaporate minerals are more soluble than calcite and quartz.