.......state Hess law​

Increasing distance between the objects factor will cause the gravitational force between two objects to decrease. Therefore, option B is correct.

What causes gravitational force to decrease?

The gravitational force grows in proportion to the size of the masses . The gravitational force weakens rapidly as the distance between masses grows. Unless at least one of the objects has a lot of mass, detecting gravitational force is extremely difficult.

Gravity is affected by object size and distance between objects. Mass is a unit of measurement for the amount of matter in an object.

The force of gravity is proportional to the masses of the two objects and inversely proportional to the square of the distance between them. This means that the force of gravity increases with mass but decreases as the distance between objects increases.

Thus, option B is correct.

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Answer:

B

Explanation:

Answer:

-68.4 kJ

Explanation:

The standard enthalpy of vaporization = 23.3 kJ/mol

which means the energy required to vaporize 1 mole of ammonia at its boiling point (-33 °C).

To calculate heat released when 50.0 g of ammonia is condensed at -33 °C.

This is the opposite of enthalpy of vaporization which means that same magnitude of heat is released.

Thus,  Q = -23.3 kJ/mol

Where negative sign signifies release of heat

Given: mass of 50.0 g

Molar mass of ammonia = 17.034 g/mol

Moles of ammonia = 50.0 /17.034 moles = 2.9353 moles

Also,

1 mole of ammonia when condenses at -33 °C releases 23.3 kJ

2.9412 moles of ammonia when condenses at -33 °C releases 23.3×2.9353 kJ

Thus, amount of heat released when 50 g of ammonia condensed at -33 °C= -68.4 kJ, where negative sign signifies release of heat.

Final answer:

The heat released when 50.0 g of ammonia condenses at its boiling point is -68.4 kJ. This is calculated by multiplying the moles of ammonia by the enthalpy of vaporization and recognizing that heat is released in condensation.

Explanation:

To solve this problem, we need to understand the concept of enthalpy of vaporization, which is the heat needed to convert 1 mole of a substance from a liquid to a gas at constant pressure and temperature. For ammonia (NH3), which boils at -33 °C, the enthalpy of vaporization is 23.3 kJ/mol. However, we want the heat released when 50.0 g (around 2.94 moles) of ammonia condenses, which is the reverse process of vaporization. Thus, the energy would be released rather than absorbed.

Now, let's calculate this value. We multiply the number of moles of ammonia by the enthalpy of vaporization:

2.94 moles x 23.3 kJ/mol = 68.4 kJ

Since this is the reverse of the process of vaporization, heat is released, so the enthalpy change is negative (-68.4 kJ). Therefore, the correct answer is -68.4 kJ.

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Answer:

(a)

Explanation:

Hello,

In this case, such nomenclature expresses the amount of both phosphorous and chlorine atoms via prefixes for the sub indexes of each atom into the molecule, thus, as phosphorous is prefixless one infers that there is just one phosphorous and five chlorides since the prefix for such atom is penta. Therefore, the correct formula is:

Hence, the answer is (a)

Best regards.

Answer:

The correct formula for phosphorus pentachloride is a) PCl5

Answer:

Is it Group?

Explanation:

To increase the polarity of HBr, the bromine atom can be replaced with a hydrogen atom.

A polar molecule is one in which a dipole moment exists. There is a positive end and a negative end in a polar molecule. Conventionally, the direction of the dipole is from the positive end of the molecule towards the negative end of the molecule.

If we want to increase the polarity of the molecule then we must substitute the bromine atom with a more electronegative atom. In this case, chlorine is  the best option.

Missing parts;

If you wanted to change the polarity of hydrogen bromide (HBr) by substitutingthe bromine by a different atom. Which atom would increase the polarity of the  molecule?

A. chlorine (CI)

B. iodine (1)

C. sulfur (S)

D. hydrogen (H)

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Answer:

This question is incomplete as it lacks options, the options are:

A. chlorine (CI)

B. iodine (1)

C. sulfur (S)

D. hydrogen (H)

The answer is A. Chlorine

Explanation:

Polarity of a substance in chemistry is a function of electric charges in the atoms of the molecules involved. Polarity, however, can be increased or decreased in molecules depending on the charges of the atoms that form them.

Since polarity increases when an atom in the molecule has a high ability to pull electrons toward itself i.e. electronegativity, one atom that can be substituted for Bromine in the hydrogen bromide (HBr) molecule in order to increase its polarity is CHLORINE. This is because Chlorine (Cl) is more electronegative than Bromine atom, hence, will pull more electrons from hydrogen to make the HCl molecule more polar than HBr.

Answer:

¹₀n+ ²³⁸₉₂U → ²³⁹₉₃Np + ⁰₋₁e

Explanation:

Key statement;

The first transuranium element neptunium, NpNp, was prepared by bombarding U−238U−238 with neutrons to form a neptunium atom and a beta particle.

This is the beta particle;  ⁰₋₁e

¹₀n+ ²³⁸₉₂U → Np + ⁰₋₁e

The mass number of Np;

1 + 238 = Np + 0

Np = 239

The atomic number of Np;

0 + 92 = Np + (-1)

92 + 1 = Np

Np = 93

The equation is given as;

¹₀n+ ²³⁸₉₂U → ²³⁹₉₃Np + ⁰₋₁e