Which of these 23rd chromosomecombinations is likeliest to result in a
person with male and female traits?
ΧΟ
XXX
XXY
XY

Answers

Answer 1

Answer: Sorry if I’m wrong but I think it’s XO since o is not a sex chromosome

Related Questions

A syringe containing 12.0 mL of dry air at 25 C is placed in a sterilizer and heated to 100.0 C. The syringe is sealed, but the plunger can move and the volume can change. What is the volume of the air in the syringe at 100.0 C, assuming no change in pressure?
Which describes one feature of the image formed by a convex mirror?????
A block of ice with mass 2.00 kg slides 0.775 m down an inclined plane that slopes downward at an angle of 31.8 ∘ below the horizontal. A) If the block of ice starts from rest, what is its final speed? You can ignore friction.
A ball is thrown horizontally from the top of a 60.0-m building and lands 100.0 m from the base of the building. Ignore air resistance. (a) How long is the ball in the air? (b) What must have been the initial horizontal component of the velocity? (c) What is the vertical component of the velocity just before the ball hits the ground? (d) What is the velocity (including both the horizontal and vertical components) of the ball just before it hits the ground?
How do you define 'heat' and 'temperature'

Much of our knowledge of the interior of the Earth comes from the study of planetary vibrations, which is the science of

Answers

Answer:

Seismology.

Explanation:

Seismology is the beach of physical science that deals with the study of vibrations that comes out from the interior of the earth onto the surface and these vibrations are in the form of seismic waves that are primary, secondary, and surface waves.

The science of seismology tells about the magnitude and intensity of these waves that lead to planetary vibrations. These waves trigger earthquakes, floods, and even landslides.

A twirlers baton is 0.76 m long and spins around its center. The end of the baton has a centripetal acceleration of 47.8 m/s2?A 0.31 s
B 0.56 s
C 4.3s
D 70s

Answers

B 0.56 s is the time period of a twirlers baton.

What is Centripetal Acceleration?

Centripetal acceleration is defined as the property of the motion of an object which traversing a circular path.

Any object that is moving in a circle and has an acceleration vector pointed towards the center of that circle is known as Centripetal acceleration.

The centripetal acceleration is given by:

a = 4π²R/T²

Given values are:

a = 47.8 m/s²

D = 0.76 m so , R = 0.76/2 = 0.38m

Using this formula,

47.8*T² = 4π² x0.38

T² = $(4*3.14^2*0.38)/(47.8)$

T = 0.56 s

Therefore,

A twirlers baton is 0.76 m long and spins around its center. The end of the baton has a centripetal acceleration of 47.8 m/s2 which have time period of 0.56 s.

Learn more about Centripetal acceleration here:

brainly.com/question/14465119

#SPJ5

Answer:

C. 4.3 seconds

Explanation:

The temperature within a thin plate with thermal conductivity of 10 W/m/K depends on position as given by the following expression: TT=(100 K)????????−xx2/????????xx 2cos�yy/????????yy�+300 K Where, Lx = 1 m, and Ly = 2 m. At the point (0.4 m, 1 m), find: a. The magnitude of the heat flux b. The direction of the heat flux

Answers

Answer:

Heat flux = (598.3î + 204.3j) W/m²

a) Magnitude of the heat flux = 632.22 W/m²

b) Direction of the heat flux = 18.85°

Explanation:

- The correct question is the first image attached to this solution.

- The solution to this question is contained on the second and third images attached to this solution respectively.

Hope this Helps!!!

The distance in the x direction between two control points on a vertical aerial photograph is 4.5". If the distance between these same two points is 3.6" on another photograph having a scale of 1:24,000, determine the scale of the first vertical aerial photograph. Of the focal length of the camera is 6"and the average elevation at these points is 100 ft, determine the flying height from which each photograph was taken

Answers

Answer:

Use proportions to find the scale of the first photo, then use that scale and other given information to fill in the equation

S=f/(H-h)

Where:

S = scale of the photo

f = focal length of the camera (in feet)

H = flying height

h = average elevation

What is the magnifying power of an astronomical telescope using a reflecting mirror whose radius of curvature is 5.5 mm and an eyepiece whose focal length is 2.9 cmcm ? Follow the sign conventions.

Answers

The magnifying power of an astronomical telescope will be:

"0.095".

Telescope: Focal length and Power

According to the question,

Radius of curvature, R = 5.5 mm

Focal length of eyepiece, $F_e$ = 2.9 cm

We know that,

→ Focal length of mirror,

F₀ = $(Radius \ of \ curvature)/(2)$

By substituting the values,

= $(5.5)/(2)$

= 2.75 mm or,

= 0.278 cm

hence,

The telescope's magnification be:

= $(F_0)/(F_e)$

= $(0.275)/(2.9)$

= 0.095

Thus the above approach is correct.

Find out more information about magnification here:

brainly.com/question/1477543

Answer:

0.095

Explanation:

An astronomical telescope is a telescope used for viewing far distance object. It uses two lenses called the objective lens and the eyepiece lens.

Each lens has its own focal length

Let the focal length of the objective lens be Fo

Focal length of the eyepiece be Fe

Magnification of an astronomical telescope = Fo/Fe

Since the telescope uses a reflecting mirror having radius of curvature of 5.5mm instead of an objective lens, then we will replace Fo as the focal length of the mirror.

Focal length of a mirror Fo = Radius of curvature/2

Fo = R/2

Fo = 5.5/2

Fo = 2.75mm

Converting 2.75mm to cm gives 2.75/10 = 0.275cm

Fo = 0.275cm; Fe = 2.9cm

Magnification of the telescope = 0.275/2.9

Magnification of the astronomical telescope = 0.095

1. Hoai Nguyen, a Physics 2A student, drop a soccer ball from the roof of the new science building. The ball strikes the ground in 3.30 s later. You may ignore air resistance, so the ball is in free fall. How tall, in meters, is the building? 2. How fast was the ball moving right before hitting the floor?

3. Thu Tran, another Physics 2A student, grabs the ball and kicks it straight up to Hoai Nguyen, who is still up on the building rooftop. Assuming that the ball is kicked at 0.50 m above the ground and it goes on a vertical path, what is the minimum velocity required for the ball to make it to the building rooftop? Ignore air resistance. (Hint: the ball will pass the rooftop level with a higher speed...)

Answers

Answer:

1. 53.415 m

2. 32.373 m/s

3. 30.82 m/s

Explanation:

Let g = 9.81 m/s2. We can use the following equation of motion to calculate the distance traveled by the ball in 3.3s, and the velocity it achieved

1. $s = gt^2/2 = 9.81*3.3^2/2 = 53.415 m$

2. $v = gt = 9.81*3.3 = 32.373 m/s$

3. If the ball is kicked at 0.5 m above the ground then the net distance between the ball and the roof top is

53.415 - 0.5 = 48.415 m

For the ball to at least make it to the roof top at speed v = 0 m/s. We can use the following equation of motion to calculate the minimum initial speed

$v^2 - v_0^2 = 2g\Delta s$

where v = 0 m/s is the final velocity of the ball when it reaches the rooftop, $v_0$ is the initial velocity, $\Delta s = 48.415$ is the distance traveled, g = -9.81 is the gravitational acceleration with direction opposite with velocity