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Answer:
The energy stored is
Explanation:
From the question we are told that
The capacitance is
The resistance is R = 3.00-Ω
The emf is
The power is P = 300 W
Generally the total emf is mathematically represented as
Here is the emf across that capacitor which is mathematically represented as
and is the emf across the resistor which is mathematically represented as
So
=>
Generally the energy stored in a capacitor is mathematically represented as
=>
=>
=>
The energy stored in the capacitor is 0 J.
When a 8.00-μF capacitor that is initially uncharged is connected in series with a 3.00-Ω resistor and an emf source with E = 70.0 V
At the instant when the resistor is dissipating electrical energy at a rate of 300 W, we can calculate the current flowing through the circuit using Ohm's law: I = V/R = 70.0 V / 3.00 Ω = 23.33 A.
The energy stored in a capacitor can be calculated using the formula: E = 1/2 * C * V^2, where C is the capacitance and V is the voltage across the capacitor.
Since the capacitor is initially uncharged, the voltage across it is also zero. So the energy stored in the capacitor is 0.5 * 8.00 x 10^-6 F * (0 V)^2 = 0 J.
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Explanation:
e(t) = 9t² − 6t + 3
The velocity is the first derivative:
e'(t) = 18t − 6
The acceleration is the second derivative:
e"(t) = 18
Answer:
d = 3.44 x 10⁸ m
Explanation:
The minimum distance required will be the distance from the centre of the earth to a point where gravitational intensity due to both earth and moon becomes equal . Once this point is reached , moon will attract the baseball on its own .
Let this distance be d from the centre of the earth
So GM / d² = G m / ( 3.82 x 10⁸ - d )²
M is mass of the earth , m is mass of the moon
M / m = ( d / 3.82 x 10⁸ - d )²
5.972 x 10²⁴ / 7.34 x 10²² = ( d / 3.82 x 10⁸ - d )²
81.36 = ( d / 3.82 x 10⁸ - d )²
9.02 = d / 3.82 x 10⁸ - d
34.45 x 10⁸ - 9.02 d = d
34.45 x 10⁸ = 10.02 d
d = 3.44 x 10⁸ m
Answer:
The value of the magnetic field is 2.01 T when Hall voltage is 1.735 mV
Explanation:
The frequency of the cyclotron can help us find the magnitude of the magnetic field, thus then we can compare the effect of increasing Hall voltage on the probe.
Magnetic field magnitude at initial Hall voltage.
The cyclotron frequency can be written in terms of the magnetic field magnitude as follows
Solving for the magnetic field.
Thus we can replace the given information but in Standard units, also remembering that the mass of a proton is and its charge is .
So we get
We have found the initial magnetic field magnitude of 0.636 T
Magnetic field magnitude at increased Hall voltage.
The relation given by Hall voltage with the magnetic field is:
Thus if we keep the same current we can write for both cases:
Thus we can divide the equations by each other to get
Simplifying
And we can solve for
Replacing the given information we get
We get
Thus when the Hall voltage is 1.735 mV the magnetic field magnitude is 2.01 T
Answer:
9 m/s
Explanation:
Wyatt maintains the maximum speed for the rest of the race. This motion begins when his displacement is 40 m and the time is 7 s. At time 12 s, his displacement is 85 m. Because this motion is constant-velocity, the maximum speed is given by
The torque about a given origin when a force N is acting on a particle at the position vector m is given by the cross product of the position and force vectors. It's represented by the SI unit Newton-meters, and for multiple particles, the total angular momentum is the vector sum of their individual angular momenta.
The torque about a given origin, when a force N is acting on a particle located at the position vector m, is calculated using the cross product of the position vector and the force vector. This can be written as τ = m x N. The SI unit of torque is Newton-meters (N.m).
As an example, if you apply a force perpendicularly at a distance from a pivot point, you will create a torque relative to that point. Similarly, the torque on a particle is also equal to the moment of inertia about the rotation axis times the angular acceleration.
If we consider multiple particles, the total angular momentum of these particles about the origin is the vector sum of their individual angular momenta. This is calculated by the expression for the angular momentum Ỉ = ŕ x p for each particle, where ŕ is the vector from the origin to the particle and p is the particle's linear momentum.
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The torque on a particle at a position vector m with force N acting on it is calculated by taking the cross-product of the position vector and the force. This principle is the same even in systems with multiple particles. The SI unit of torque is Newton-meters (N·m), which should not be confused with Joules (J).
The torque on a particle located at a position vector m with a force N acting on it is calculated by taking the cross-product of the position vector and the force. In terms of physics, torque (τ) is a measure of the force that can cause an object to rotate about an axis, and it is calculated as the product of the force and the distance from the axis of rotation to the point where force is applied. Hence, the formula for torque is τ = r x F where r is the position vector (or distance from the origin to the point where the force is applied) and F is the force. Remember, this equation gives a vector result with a direction perpendicular to the plane formed by r and F and a magnitude equal to the product of the magnitudes of r and F and the sine of the angle between r and F.
The same principle applies to systems where multiple particles are present. The total angular momentum of the system of particles about a particular point is the vector sum of the individual angular momenta about that point. Torque is the time derivative of angular momentum.
The SI unit for torque is Newton-meters (N·m), which should not be confused with Joules (J), as both have the same base units but represent different physical concepts. In this context, a net force of 40N acting at a distance of 0.800m from the origin would generate a torque of 32 N·m at the origin.
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