A block of ice with mass 2.00 kg slides 0.775 m down an inclined plane that slopes downward at an angle of 31.8 ∘ below the horizontal. A) If the block of ice starts from rest, what is its final speed? You can ignore friction.

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Answer 1
Answer:

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Legacy issues $570,000 of 8.5%, four-year bonds dated January 1, 2019, that pay interest semiannually on June 30 and December 31. They are issued at $508,050 when the market rate is 12%.1. Determine the total bond interest expense to be recognized. Total bond interest expense over life of bonds: Amount repaid: 8 payments of $24,225 $193,800Par value at maturity 570,000Total repaid 763,800Less amount borrowed 645 669 Total bond interest expense $118.1312. Prepare a straight-line amortization table for the bonds' first two years. Semiannual Period End Unamortized Discount Carrying Value 01/01/201906/30/2019 12/31/2019 06/30/2020 12/31/2020 3. Record the interest payment and amortization on June 30. Note: Date General Journal Debit Credit June 30 4. Record the interest payment and amortization on December 31.Date General Journal Debit Credit December 31

A 8.00-μF capacitor that is initially uncharged is connected in series with a 3.00-Ω resistor and an emf source with E = 70.0 V and negligible internal resistance. At the instant when the resistor is dissipating electrical energy at a rate of 300 W, how much energy has been stored in the capacitor?

Answers

Answer:

The energy stored is E_s = 0.0064 \  J

Explanation:

From the question we are told that  

   The capacitance  is  C =  8 \ \mu F = 8*10^(-6) \  F

    The resistance is  R = 3.00-Ω

    The emf is  E_t = 70.0 V

      The power  is  P = 300 W

Generally the total  emf is mathematically represented as

   E_t = E_c + E_r

Here  E_c is the emf across that capacitor which is mathematically represented as

      E_c  =  (q)/(C)

and E_r is the emf across the resistor which is mathematically represented as

       E_r  = √(P R)

So  

       E_t  =  √(PR)  + (q)/(C)

=>    q = C[E_t - √(PR) ]

Generally the energy stored in a capacitor is mathematically represented as

          E_s = (q^2)/(2C)

=>      E_s = ([C [ E_t - √(PR) ]]^2)/(2C)

=>      E_s = ([8.0*10^(-6) [ 70 - √(300 * 3))/(2 *(8.0*10^(-6)))

=>      E_s = 0.0064 \  J

Final answer:

The energy stored in the capacitor is 0 J.

Explanation:

When a 8.00-μF capacitor that is initially uncharged is connected in series with a 3.00-Ω resistor and an emf source with E = 70.0 V

At the instant when the resistor is dissipating electrical energy at a rate of 300 W, we can calculate the current flowing through the circuit using Ohm's law: I = V/R = 70.0 V / 3.00 Ω = 23.33 A.

The energy stored in a capacitor can be calculated using the formula: E = 1/2 * C * V^2, where C is the capacitance and V is the voltage across the capacitor.

Since the capacitor is initially uncharged, the voltage across it is also zero. So the energy stored in the capacitor is 0.5 * 8.00 x 10^-6 F * (0 V)^2 = 0 J.

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Experts in model airplanes develop a supersonic plane to scale, it moves horizontally in the air while it is conducting a flight test. The development team defines that the space that the airplane travels as a function of time is given by the function: e (t) = 9t 2 - 6t + 3 Determine what acceleration the scale airplane has (Second derivative).

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Explanation:

e(t) = 9t² − 6t + 3

The velocity is the first derivative:

e'(t) = 18t − 6

The acceleration is the second derivative:

e"(t) = 18

What minimum distance would you have to hit a baseball from the center of the earth so that it would eventually reach the moon? Assume you can hit the ball directly along the line that connects the centers of the earth and moon. The distance between the centers of the earth and moon is ???? = 3.82 × 108 m.

Answers

Answer:

d = 3.44 x 10⁸ m

Explanation:

The minimum distance required will be the distance from the centre of the earth to a point where gravitational intensity due to both earth and moon becomes equal . Once this point is reached , moon will attract the baseball on its own .

Let this distance be d from the centre of the earth

So GM / d² = G m / ( 3.82 x 10⁸ - d )²

M is mass of the earth , m is mass of the moon

M / m =  ( d / 3.82 x 10⁸ - d )²

5.972 x 10²⁴ / 7.34 x 10²² = ( d / 3.82 x 10⁸ - d )²

81.36 = ( d / 3.82 x 10⁸ - d )²

9.02 = d / 3.82 x 10⁸ - d

34.45 x 10⁸ - 9.02 d = d

34.45 x 10⁸ = 10.02 d

d = 3.44 x 10⁸ m

A Hall-effect probe to measure magnetic field strengths needs to be calibrated in a known magnetic field. Although it is not easy to do, magnetic fields can be precisely measured by measuring the cyclotron frequency of protons. A testing laboratory adjusts a magnetic field until the proton's cyclotron frequency is 9.70 MHz . At this field strength, the Hall voltage on the probe is 0.549 mV when the current through the probe is 0.146 mA . Later, when an unknown magnetic field is measured, the Hall voltage at the same current is 1.735 mV .A) What is the strength of this magnetic field?

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Answer:

The value of the magnetic field is 2.01 T when Hall voltage is 1.735 mV

Explanation:

The frequency of the cyclotron can help us find the magnitude of the magnetic field, thus then we can compare the effect of increasing Hall voltage  on the probe.

Magnetic field magnitude at initial Hall voltage.

The cyclotron frequency can be written in terms of the magnetic field magnitude as follows

f = \cfrac{qB}{2\pi m}

Solving for the magnetic field.

B = \cfrac{2\pi mf}q

Thus we can replace the given information but in Standard units, also remembering that the mass of a proton is m_p=1.67 * 10^(-27) kg and its charge is q_p=1.6 * 10^(-19) C.

So we get

B = \cfrac{2\pi * 1.67 * 10^(-27) kg * 9.7 * 10^6 Hz}{1.6 * 10^(-19)C}

B =0.636 T

We have found the initial magnetic field magnitude of 0.636 T

Magnetic field magnitude at increased Hall voltage.

The relation given by Hall voltage with the magnetic field is:

V_H =\cfrac{R_HI}t B

Thus if we keep the same current we can write for both cases:

V_(H1) =\cfrac{R_HI}t B_1\nV_(H2) =\cfrac{R_HI}t B_2

Thus we can divide the equations by each other to get

\cfrac{V_(H1) }{V_(H2)}=\cfrac{\cfrac{R_HI}t B_1}{\cfrac{R_HI}t B_2}

Simplifying

\cfrac{V_(H1) }{V_(H2)}=\cfrac{ B_1}{ B_2}

And we can solve for B_2

B_2 =B_1 \cfrac{V_(H2)}{V_(H1)}

Replacing the given information we get

B_2= 0.636 T * \left(\cfrac{1.735 mV}{0.549 mV} \right)

We get

\boxed{B=2.01\, T}

Thus when the Hall voltage is 1.735 mV the magnetic field magnitude is 2.01 T

When running a 100 meter race Wyatt reaches his maximum speed when he is 40 meters from the starting line, and 7 seconds have elapsed since the start of the race. Wyatt continues at this max speed for the rest of the race and is 85 meters from the starting line 12 seconds after the start of the race. What is Wyatt's max speed

Answers

Answer:

9 m/s

Explanation:

Wyatt maintains the maximum speed for the rest of the race. This motion begins when his displacement is 40 m and the time is 7 s. At time 12 s, his displacement is 85 m. Because this motion is constant-velocity, the maximum speed is given by

v_\text{max} = (85-40)/(12-7) = (45)/(5) = 9 \text{ m/s}

A particle located at the position vector m has a force N acting on it. The torque about the origin is

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Final answer:

The torque about a given origin when a force N is acting on a particle at the position vector m is given by the cross product of the position and force vectors. It's represented by the SI unit Newton-meters, and for multiple particles, the total angular momentum is the vector sum of their individual angular momenta.

Explanation:

The torque about a given origin, when a force N is acting on a particle located at the position vector m, is calculated using the cross product of the position vector and the force vector. This can be written as τ = m x N. The SI unit of torque is Newton-meters (N.m).

As an example, if you apply a force perpendicularly at a distance from a pivot point, you will create a torque relative to that point. Similarly, the torque on a particle is also equal to the moment of inertia about the rotation axis times the angular acceleration.

If we consider multiple particles, the total angular momentum of these particles about the origin is the vector sum of their individual angular momenta. This is calculated by the expression for the angular momentum Ỉ = ŕ x p for each particle, where ŕ is the vector from the origin to the particle and p is the particle's linear momentum.

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Final answer:

The torque on a particle at a position vector m with force N acting on it is calculated by taking the cross-product of the position vector and the force. This principle is the same even in systems with multiple particles. The SI unit of torque is Newton-meters (N·m), which should not be confused with Joules (J).

Explanation:

The torque on a particle located at a position vector m with a force N acting on it is calculated by taking the cross-product of the position vector and the force. In terms of physics, torque (τ) is a measure of the force that can cause an object to rotate about an axis, and it is calculated as the product of the force and the distance from the axis of rotation to the point where force is applied. Hence, the formula for torque is τ = r x F where r is the position vector (or distance from the origin to the point where the force is applied) and F is the force. Remember, this equation gives a vector result with a direction perpendicular to the plane formed by r and F and a magnitude equal to the product of the magnitudes of r and F and the sine of the angle between r and F.

The same principle applies to systems where multiple particles are present. The total angular momentum of the system of particles about a particular point is the vector sum of the individual angular momenta about that point. Torque is the time derivative of angular momentum.

The SI unit for torque is Newton-meters (N·m), which should not be confused with Joules (J), as both have the same base units but represent different physical concepts. In this context, a net force of 40N acting at a distance of 0.800m from the origin would generate a torque of 32 N·m at the origin.

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