A person invested 3,900 in an account growing at a rate allowing the money to double every 7 years. How much money would be in the account after 18 years to the nearest dollar

Answers

Answer 1

Answer:

23182 or 23181.5109105

Step-by-step explanation:

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On an exam, the mean score is 78 points, with a standard deviation of 6 points. Assuming normal distribution of the scores, approximately what percentage of students received more than 85?A.12% B.17% C.8% D.9% E.None of the above
What is the value of x in both a & b?

Suppose that two cards are randomly selected from a standard 52-card deck. (a) what is the probability that the first card is a queen and the second card is a queen if the sampling is done without replacement? (b) what is the probability that the first card is a queen and the second card is a queen if the sampling is done with replacement? g

Answers

Hey ,here is the answer to ur question....!
(a).p(that the first card is a queen)=4/52=2/26=1/13
P(the card is a queen if the sampling is done without replacement)=3/52
(B).p(the first card is a queen)=4/52=1/13
P(the second card is queen of the sampling is done with replacement)=1/13....
Hope this helps you....!

1/2(3/5x-8)+7/4(2/5x+4)

Answers

Answer:

x + 3

Step-by-step explanation:

Use the distributive property, then collect like terms

(1/2)(3/5 x) + (1/2)(-8) + (7/4)(2/5 x) + (7/4)(4)

3/10 x - 4 + 7/10 x + 7

x + 3

An investment project involves an immediate outlay of $8 million. The net cash flows received at the end of years 1, 2, and 3 will be $3 million, $4 million, and $2 million. A 10% discount rate is applicable so that the present value factors for years 1, 2, and 3 are 0.9091, 0.8264, and 0.7513. The NPV of the investment will be: (a) (b) (c) (d) $1 million $9 million $0.46 million $7.54 million

Answers

Answer:

(c) 0.46 million

Step-by-step explanation:

As provided immediate cash outlay = $8 million.

This will represent cash outflow at period 0, as it is made immediately, no time period has lapsed.

Cash inflows as provided and the respective present value factor are:

Year Cash Inflow Factor Discounted Value

1 $3 million 0.9091 $2,727,300

2 $4 million 0.8264 $3,305,600

3 $2 million 0.7513 $1,502,600

Total present value of cash inflow = $7,535,500

Therefore, net present value = $7,535,500 - $8,000,000 = - $464,500

That is - 0.46 million

Correct option is

(c) 0.46 million

What is the approximate radius of the disc if the area is 78.5 square inches?

Answers

78.5 = 3.14 * r^2

r^2 = 78.5 / 3.14 = 25

r = radius = 5 answer

You want to create an 80% confidence interval for the average age of people who attend U of O football games. You take a sample of 100 attendees and find the average age to be 43.7 years old with a standard deviation of 7 years. Find the value of t* for this confidence interval. Do not round your answer. Write your answer in decimal form, not as a fraction or percent.

Answers

Answer:

80% confidence interval for the average age of people who attend U of O football games is [42.795 , 44.604].

Step-by-step explanation:

We are given that a sample of 100 attendees and find the average age to be 43.7 years old with a standard deviation of 7 years.

So, the pivotal quantity for 80% confidence interval for the population average start up cost is given by;

P.Q. = $(\bar X - \mu)/((s)/(√(n) ) )$ ~ $t_n_-_1$

where, $\mu$ = sample average age = 43.7 years old

$\sigma$ = sample standard deviation = 7 years

n = sample of attendees = 100

$\mu$ = population average age of people

So, 80% confidence interval for the average age of people, $\mu$ is ;

P(-1.2915 < $t_9_9$ < 1.2915) = 0.80

P(-1.2915 < $(\bar X - \mu)/((s)/(√(n) ) )$ < 1.2915) = 0.80

P( $-1.2915 * {(s)/(√(n) )$ < ${\bar X - \mu}$ < $1.2915 * {(s)/(√(n) )$ ) = 0.80

P( $\bar X -1.2915 * {(s)/(√(n) )$ < $\mu$ < $\bar X +1.2915 * {(s)/(√(n) )$ ) = 0.80

80% confidence interval for $\mu$ = [ $\bar X -1.2915 * {(s)/(√(n) )$ , $\bar X +1.2915 * {(s)/(√(n) )$ ]

= [ $43.7 -1.2915 * {(7)/(√(100) )$ , $43.7 +1.2915 * {(7)/(√(100) )$ ]

= [42.795 , 44.604]

Therefore, 80% confidence interval for the population average age of people who attend U of O football games is [42.795 , 44.604].

Is 48,200 written in scientific notation? If not, write it in scientific notation.

Answers

Answer:

No. 4.82×10^4

Step-by-step explanation:

It has to be x10 to be in scientific notation so you move the decimal point 4 times and get the answer

Answer:

No, 48,200 is written in Standard Notation.

If you want to evaluate 48,200 to scientific notation, the answer is 4.82 x 10^4.

Hope this helps and have a nice day!

Step-by-step explanation:

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