During a chemistry experiment, the volume of a solution increases when distilled water is added to the solution at a constant rate of 100 mL/min. Initially, there are 50 mL of solution, and water is added for 5 min.​

Answer:

1.646×10¹¹ km³.

Step-by-step explanation:

From the question given, we obtained the following information:

Radius (r) = 3400 km

Volume (V) =.?

The shape of a planet is spherical in nature. Thus, we shall apply the formula for calculating the volume of a sphere to obtain the volume of Planet Mar as illustrated below:

Radius (r) = 3400 km

Pi (π) = 3.14

Volume (V) =.?

Volume of a sphere = 4/3 πr³

V = 4/3 × 3.14 × (3400)³

V = 4/3 × 3.14 × 3.9304×10¹⁰

V = 1.646×10¹¹ km³

From the calculations made above, the volume of Planet Mar is 1.646×10¹¹ km³

Answer:

We conclude that the mean is greater than 25.  

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 25

Sample mean, = 27

Sample size, n = 100

Alpha, α = 0.05

Sample standard deviation, s = 6.5

First, we design the null and the alternate hypothesis

We use One-tailed(right) z test to perform this hypothesis.

Formula:

Putting all the values, we have

Now,

Since,  

We reject the null hypothesis and accept the alternate hypothesis.

Thus,  the mean is greater than 25.

Final answer:

The null hypothesis is the mean is equal to 25 and the alternative is that the mean is greater than 25. Using a one-sample t-test and 0.05 significance level, the calculated statistic results in rejection of the null hypothesis. Thus, there is sufficient evidence to suggest that the mean daily census in pediatrics is greater than 25.

Explanation:

1. The hypotheses for this scenario are that the null hypothesis (H0): the mean daily census in the pediatrics service is equal to 25, and the alternative hypothesis (H1): the mean daily census in the pediatrics service is greater than 25.

2. The appropriate test for this scenario would be a one-sample t-test, given that we have a sample mean, a population mean, a standard deviation, and we're examining a single group of hospitals.

3. The decision rule would be: if the p-value of our t-test is less than the significance level (α=.05), we reject H0 and accept H1.

4. The test statistic is calculated as follows: t = (Sample Mean-Population Mean)/(Sample Standard Deviation/ √number of observations), this would give us (27-25)/(6.5/√100) = 3.08.

5. Since 3.08 is greater than the critical value for a 0.05 significance level, we reject the null hypothesis. Therefore, there is sufficient evidence to conclude that the mean daily census in the pediatrics service is greater than 25.

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9514 1404 393

Answer:

  145.3 square inches

Step-by-step explanation:

The lateral area of the cylinder is given by ...

  LA = 2πrh

  LA = 2π(2.5 in)(9.25 in) = 46.25π in²

  LA ≈ 145.3 in²

About 145.3 square inches of paper is used for the label.

Answer:

0.6

Step-by-step explanation:

12/20 = 6/10 = 0.6

Answer:

We cannot calculate the probability  that a randomly selected passenger weighs more than 200 pounds

Step-by-step explanation:

We cannot calculate the probability  that a randomly selected passenger weighs more than 200 pounds because we do not know the number of possible outcomes, the events , sample space or the sample size. Probability is calculated  with frequency or occurrences or how much certainty there is.It is a number between 0 and 1. 1 indicates certainty and  0 indicates impossibility. Without a range or frequency how can we depict the possibility or impossibility of an occurrence of 200 pounds.

Final answer:

You cannot calculate the probability that a randomly selected passenger weighs more than 200 pounds without sufficient data on the weight distribution of the population. Weight can widely vary due to individual factors, making it hard to have a definitive measurement. Accurate data and appropriate statistical methods are necessary.

Explanation:

The process of calculating the probability that a randomly selected passenger weighs more than 200 pounds would be seemingly simple deductive reasoning. However, it's impossible without access to sufficient data that provides information about the population's weight distribution. Since people's weights are variable and oftentimes private information, it would not be straightforward to obtain accurate and representative data.

For instance, while we can calculate the probability of drawing a certain card from a deck because we know the total number of cards and the number of each type of card, determining the likelihood of a randomly chosen passenger weighs over 200 pounds requires knowledge of the weight distribution of all potential passengers.

Moreover, weight can vary significantly among individuals due to factors like age, gender, health status, and so on. This makes it a continuous variable, meaning it's also affected by dimensions like decimal form and scientific notation when measuring. We'd need accurate data and appropriate statistical methodologies to consider all possible weight ranges and their frequencies for a reliable calculation of such probability.

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Answer:

Step-by-step explanation:

y - 5 = -2(x - 1)

y - 5 = -2x + 2

y = -2x + 7

Option 1 is the answer