A cookie recipe called for 2 4⁄6 cups of sugar for every 2⁄3 cup of flour. If you made a batch of cookies using 1 cup of flour, how many cups of sugar would you need?
Answers
16/6
To turn 2/3 into 1 cup, multiply my 3/2 for both the flour and sugar.
1 cup flour = 3/2(16/6)
1=48/12
Reduce
1 cup flour = 4 cups sugar.
Hope it helps! I can provide image if needed
Related Questions
Gloria earned a total of $810 over the summer. She earned $162 babysitting and the restfrom mowing lawns. Which bar model and solution represent x, the amount of money Gloriaearned mowing lawns?
Solve the equation 2.5y +6 =4.5y -1
Henderson opened a coffee shop. He insured his store against fire for $150,000. What’s his premium if the rate per $100 is $0.79
PLZ IM ON THE CLOCK!!!!! A sports memorabilia store makes $6 profit on each football it sells and $5.50 profit on each baseball it sells. In a typical month, it sells between 35 and 45 footballs and between 40 and 55 baseballs. The store can stock no more than 80 balls total during a single month. What is the maximum profit the store can make from selling footballs and baseballs in a typical month? $457.50 $460.00 $462.50 $572.50
Answers
Answer: he should pay $23095 for this bond.
Step-by-step explanation:
We would apply the formula for determining simple interest which is expressed as
I = PRT/100
Where
I represents interest paid on the bond purchased.
P represents the principal or amount of bond purchased.
R represents interest rate
T represents the duration of the bond in years.
From the given information,
R = 11%
T = 9 months = 9/12 = 0.75
I = 25000 - P
Therefore
25000 - P = (P × 11 × 0.75)/100
25000 - P = 8.25P/100 = 0.0825P
P + 0.0825P = 25000
1.0825P = 25000
P = 25000/1.0825
P = $23095
Answer:$2706.25
Step-by-step explanation:
Principal(t)=$2500
Time(t)=9months=9/12=0.75year
Rate(r)=11%
Simple interest(si)=?
Si=(pxrxt)/100
Si=(2500x11x0.75)/100
Si=20625/100
Si=$206.25
Total amount=p + si
Total amount=2500+206.25
Total amount=$2706.25
(b) How large must the sample be if you want to halve the standard deviation of the sample mean?
Answers
Answer:
Step-by-step explanation:
Given that:
population mean = 10
variance = 25 ;
=
= 5
sample size n = 28
The standard deviation of the sample mean:
=
= 0.95
To halve the standard deviation of the sample mean, the size of how large the sample will be can be computed as follows:
= 2
n = 4 × 28
n = 112
The standard deviation is 0.95 and if the standard deviation is halved then the sample mean is 112.
What is a standard deviation?
It is the measure of the dispersion of statistical data. Dispersion is the extent to which the value is in a variation.
A normal population has a mean of 10 and a variance of 25.
A random sample of sizes n-28 is selected.
A. The standard deviation will be
B. The sample be if you want to halve the standard deviation of the sample mean
More about the standard deviation link is given below.
Answers
Answer:
Hey there!
Using the foil method: (3x+2)(5x-7)
15x^2+10x-21x-14
15x^2-11x-14
Let me know if this helps :)
Here’s your answer (3x+2)x(5x-7)
Answers
Answer: The answer is everytime you mutiply in by 0.6
Step-by-step explanation:
Answers
if we were to use the quadratic formula, we would get that the roots are
or that the 2 seperate roots are
and
if we sum these, then the bits will cancel and we wil be left with
or
or
the sum of the solutions is
Try this option:
According to the properties of the quadratic equation the sum of its roots is '-b', in other words x₁+x₂= -b
Answer: -b
Answers
Final answer:
The number 68,979 is divisible by 3 but not by 5, 6, or 11.
Explanation:
To test a number for divisibility by 3, we sum up its individual digits. If the sum is divisible by 3, then the number itself is divisible by 3. For the number 68,979, the sum of its digits is 6 + 8 + 9 + 7 + 9 = 39. Since 39 is divisible by 3, 68,979 is also divisible by 3.
To test a number for divisibility by 5, we simply check if the last digit is either 0 or 5. In the number 68,979, the last digit is 9, which is neither 0 nor 5. Therefore, 68,979 is not divisible by 5.
To test a number for divisibility by 6, we need to check if it is divisible by both 2 and 3. From the previous tests, we already know that 68,979 is divisible by 3, so we now need to check if it is divisible by 2. Since the last digit is 9, which is an odd number, 68,979 is not divisible by 2, and therefore not divisible by 6.
To test a number for divisibility by 11, we take the alternating sum of its digits. In this case, we have 6 - 8 + 9 - 7 + 9 = 9. Since 9 is not divisible by 11, 68,979 is not divisible by 11.