Find two positive numbers such that the sum of the first and twice the second is 200 and their product is a maximum.

Answers

Answer 1
Answer:

Answer:

20 and 90

Step-by-step explanation:

20 + 2(90) = 200

20 + 180 = 200

200 = 200

20 × 2(90)

= 20× 180

= 3,600


Related Questions

Write in standard form 80010000
Roxanne wants to save up enough money so that she can buy a video game. The game costs $59. Roxanne has $22 saved from mowing the grass. In order to make more money, she plans to pressure wash her neighbors’ driveways. She plans to charge $5 for each driveway she pressure washes, and any extra money she makes beyond $59 she will save to buy another video game. How many driveways does she need to pressure wash to reach her goal?
the label on marc’s yogurt said that one serving provided 10 grams of fiber, which is 50% of the recommended daily amount. what is the total recommended daily amount of fiber?
Please helpppp!!! it’s timed!!!! thank u for helping!!!!!
Please help 30 points plus brainlyist who does firstDetermine which expressions can be simplified further, and which cannot. Sort the expressions into the correctcategory2x + 3yCan Be SimplifiedCannot Be Simplifiedx + x4r +7y + 14y + 4xy + 2y

Pls not links I am serious

Answers

-1,0,1/2,1.7
If you put 1/2 =0.5

For the following normal distribution, give the x-values of the inflection points of the curve (the points where the curve's concavity changes). x ~ N(0, 52)

Answers

Answer:

The x-values of the inflection points of the curve are x = -52 and x = 52.

Step-by-step explanation:

Suppose we have a normal curve with mean \mu and standard deviation \sigma

The x-values of the inflection points of the curve are x = \mu - \sigma and x = \mu + \sigma

x ~ N(0, 52)

This means that \mu = 0, \sigma = 52

So

x = 0 - 52 = -52

x = 0 + 52 = 52

The x-values of the inflection points of the curve are x = -52 and x = 52.

Final answer:

The inflection points in a normal distribution occur at one standard deviation above and below the mean. For the distribution x ~ N(0, 52), the inflection points are at -√52 and √52.

Explanation:

In a normal distribution, the inflection points occur at one standard deviation above and below the mean. In the given normal distribution, x ~ N(0, 52), the mean (μ) is 0 and the standard deviation (σ) is the square root of the variance, i.e., √52.

Therefore, the x-values for the inflection points would be μ - σ and μ + σ, which are -√52 and +√52, respectively.

Learn more about Inflection Points here:

brainly.com/question/31582579

#SPJ11

Find the measure of x1.
{
83°
41
{
41 = [?]

Answers

Answer:

Solution given:

< 1+ 83°= 180 [co- interior angle]

<1=180-83=97°

<1=97° is your answer

5x5x5x5= ______ to the power of _____

Answers

Answer:

5 4

Step-by-step explanation:

its fristly 5

ok then bb

Answer:

5x5x5x5=625

Step-by-step explanation:

The expression 52 - 4 of (17 - 12) + 4 × 7 is equal to
70
60
50
48

Answers

Answer:

The value of given expression 52 - 4 of (17 - 12) + 4 × 7 = 60

Step-by-step explanation:

Given expression;

52 - 4 of (17 - 12) + 4 × 7

Find:

The value of given expression 52 - 4 of (17 - 12) + 4 × 7

Computation:

52 - 4 of (17 - 12) + 4 × 7

Using BODMAS rule;

52 - 4 of (17 - 12) + 4 × 7

52 - 4(17 - 12) + 4 × 7

52 - 4(5) + 28

52 - 20 + 28

80 - 20

60

So,

The value of given expression 52 - 4 of (17 - 12) + 4 × 7 = 60

If a shoe company has $1 million in fixed costs, its average shoe sells for $50 a pair, and variable costs are $30 per unit, how many units does the company need to sell to break even? (Show work)

Answers

Answer:

s

Step-by-step explanation:

bdjdiwo9929191isjjz

Other Questions
Find the​ range, variance, and standard deviation for the given sample data. Include appropriate units in the results.Listed below are the measured radiation absorption rates​ (in W/kg) corresponding to various cell phone models. If one of each model is measured for radiation and the results are used to find the measures of​ variation, are the results typical of the population of cell phones that are in​ use?0.950.950.730.730.630.630.910.911.321.321.481.480.630.631.231.230.910.911.411.41 0.670.67The range of the sample data isnothing▼​(Round to three decimal places as​ needed.)Sample standarddeviationequals=nothing▼kg.kg.left parenthesis Upper W divided by kg right parenthesis squared .W/kg2.W.W.Upper W divided by kg.W/kg.​(Round to three decimal places as​ needed.)Samplevarianceequals=nothing▼kg.kg.left parenthesis Upper W divided by kg right parenthesis squared .W/kg2.Upper W divided by kg.W/kg.W.W.​(Round to three decimal places as​ needed.)If one of each model is measured for radiation and the results are used to find the measures of​ variation, are the results typical of the population of cell phones that are in​ use?A. ​No, because it is necessary to have at least 5 of each cell phone in order to get a meaningful result. Only including one of each cell phone model is not representative of each cell phone model.B. ​Yes, because the results from any sample of cell phones will be typical of the population.C. ​Yes, because each model is being represented in the sample. Any sample that considers all possible cell phone models will produce results typical of the population of cell phones.D. No, because some models of cell phones will have a larger market share than others. Measures from different models should be weighted according to their size in the population.