Answer:
D. No, because some models of cell phones will have a larger market share than others. Measures from different models should be weighted according to their size in the population.
Step-by-step explanation:
For this case we have the following data values:
0.95,0.73,0.63,0.91,1.32,1.48,0.63,1.23,0.91,1.41,0.67
The first step on this case is order the datase on increasing way and we got:
0.63 0.63 0.67 0.73 0.91 0.91 0.95 1.23 1.32 1.41 1.48
The range is defined as
And if we replace we got:
The sample standard deviation is given by this formula:
And if we replace we got
And the sample variance is just the standard deviation squared so we got:
And for the last question about : If one of each model is measured for radiation and the results are used to find the measures of variation, are the results typical of the population of cell phones that are in use?
We can conclude this:
D. No, because some models of cell phones will have a larger market share than others. Measures from different models should be weighted according to their size in the population.
Answer:
Do you mean strandord or expanded form?
Step-by-step explanation:
Answer:
Pr = 15.71% ≈ 16%
Step-by-step explanation:
Let's begin by listing out the data given unto us, we have:
Length of board = 3 ft, Width of board = 5 ft,
Area of board = Length * Width = 3 * 5 = 15 ft²,
Diameter of each circle (d) = 1 ft; r = d ÷ 2
⇒ r = 1 ÷ 2 = 0.5 ft
Area of each circle = πr² = π * 0.5² = 0.785 ft²
Area of the three circles = 3πr² = 2.356 ft²
Probability = favourable outcome ÷ Total outcome
Probability of the penny falling into the hole = area of the three circles ÷ area of board
Pr = 2.356 ÷ 15 = 0.1571
Converting to percentage, we multiply by 100
Pr = 0.1571 * 100
Pr = 15.71% ≈ 16%
Therefore, the probability of the penny falling into the hole is 15.71% ≈ 16%
Answer:
11.63 - 6.7 = 4.93
Hope this helps!
Answer:
The correct answer to the following question will be "No". The further explanation is given below.
Step-by-step explanation:
Probability (Keeping the disease out of 1 contact)
=
Probability (not keeping the disease out of 1 contact)
=
=
Now,
Probability (not keeping the disease out of 2 contact)
= Keeping the disease out of 1 contact × not keeping the disease out of 1 contact
On putting the estimated values, we get
=
=
So that,
Probability (Keeping the disease out of 2 contact)
=
=
∴ Not 100%
Answer:
D is the answer to your question
Answer:
350
Step-by-step explanation: