Answer: a) : negative
b) : positive
c) : positive.
d) : negative
e) : positive.
f) : positive.
Explanation:
Entropy is the measure of randomness or disorder of a system. If a system moves from an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.
is positive when randomness increases and is negative when randomness decreases.
a)
As ions are moving to solid form , randomness decreases and thus sign of is negative.
b)
As solid is changing to gas, randomness increases and thus sign of is positive.
c)
As 2 moles of reactants are converted to 4 moles of products , randomness increases and thus sign of is positive.
d)
As gas is changing to solid, randomness decreases and thus sign of is negative.
e)
As 7 moles of reactants are converted to 8 moles of products , randomness increases and thus sign of is positive.
f)
As solid is changing to gas, randomness increases and thus sign of is positive.
A) less kinetic energy.
B)
more kinetic energy.
more total energy.
D) the same total energy.
Answer:
its not more kinetic energy i put that and got it wrong
B) 1.77 m
C) 6.39 m
D) 2.41 m
E) none of these
Answer: D) 2.41 m
Explanation:
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.
where,
n = moles of solute
= weight of solvent in kg
moles of solute =
volume of solution = 1L = 1000 ml (1L=1000ml)
Mass of solution=
mass of solute = 292 g
mass of solvent = mass of solution - mass of solute = (1108- 292) g = 816g = 0.816 kg
Now put all the given values in the formula of molality, we get
Therefore, the molality of solution will be 2.41 mole/kg
In this problem, we calculate molality by using the given mass of the solute, the mass of the solvent, and the molar mass of the solute. After performing the necessary calculations, we find that the molality is 2.41 m.
The subject of this student's question is molality, which is a measure of the concentration of a solute in a solution. It is defined as the number of moles of solute per kilogram of solvent. To find the molality (m), we need to know the mass of the solute and the mass of the solvent in the solution.
Given, that the solution contains 292g of Mg(NO3)2 per liter (which is the mass of the solute). The density of the solution is 1.108g/mL. We know that 1L = 1000mL, so the mass of the solution is density x volume = 1.108g/mL x 1000mL = 1108g.
We need to find the mass of the solvent (water). The mass of the solution is the mass of the solute + the mass of the solvent. So, the mass of the solvent is 1108g(mass of the solution) - 292g(mass of solute) = 816g or 0.816gkg.
The molar mass of Mg(NO3)2 is 148.31452 g/mol. So, the number of moles of Mg(NO3)2 in the solution is moles = mass / molar mass = 292g / 148.31452 g/mol = 1.97 moles.
Now we can calculate molality (m) = moles of solute/mass of solvent in kg = 1.97 moles / 0.816 kg = 2.41 m. Therefore, the answer is D) 2.41 m.
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Answer:
8.08 grams
Explanation:
Given;
Mass of the steam, m = 100 g
Change in temperature of water = (95°C - 35°C) = 60°C
Change in temperature of steam = (110°C - 100°C) = 10°C
let the mass of water by 'M'
also,
We know
specific heat of water, c = 4.184 J/Kg.°C
And, specific heat of steam, C = 2.03 J/Kg.°C
Now,
Heat released = Mass × specific heat × change in temperature
thus, for the condition given in the question
M × 4.184 × 60 = 100 × 2.03 × 10
or
M = 8.08 grams
The mass of water that will provide the same amount of heat when cooled from 95.0 to 35.0 C as a 100 g of steam cooling from 110C to 100C is 125 grams. To solve this question, we used the specific heat of water, calculated the heat produced in the latter scenario, and deduced the mass needed from that.
To determine the mass of water that will provide the same amount of heat when cooled from 95.0 to 35.0 C as a 100 g of steam cooling from 110 to 100C, we need to first calculate the amount of heat produced in the latter situation. Using the specific heat of water which is 4.184 J/g °C, the heat produced when cooling 100g of steam from 110C to 100C is Q=msΔT, where m is mass, s is specific heat, and ΔT is temperature difference. So, Q = 100g * 4.184 J/g°C * (110°C - 100°C) = 4184 J.
Now, we have to calculate the mass of water that will produce the same amount of heat when cooled from 95°C to 35°C. We rearrange the equation to solve for mass. Hence, m = Q/sΔT = 4184 J / 4.184 J/g°C / (95.0 °C - 35.0 °C) = 125g. Therefore, 125g of water will provide the same amount of heat when cooled from 95.0 to 35.0 C.
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Answer:
The energy produced equals 140.760 kJ
Explanation:
The relation between power, current and voltage is
Applying the given values in the relation above we get
Now Since
Again applying the calculated values we get
Answer:
Explanation:
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