Answer:
MOSE
Explanation:
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A) Has a positive acceleration and is speeding up.
B) Moving with zero acceleration.
C) Moving at a constant acceleration.
D) Has a negative acceleration and is slowing down.
B) Moving with zero acceleration.
Explanation:
Acceleration is defined as the rate of change of the velocity per unit time:
In a velocity-time graph, this ratio corresponds to the slope of the curve. In fact:
(change in velocity) corresponds to the increase in the y-axis
(change in time) corresponds to the increase in the x-axis
So, acceleration corresponds to the slope of the curve in a velocity-time graph. For cart C, the slope is zero, therefore the acceleration is also zero.
Answer:
B) Moving with zero acceleration.
Explanation:
As we can see the graph for Cart C that its velocity is constant and not changing its magnitude as well as its sign
So here the magnitude and direction is constant so we can say that velocity will remain constant always.
Where we can define the acceleration as
so here if magnitude and direction both are constant so
so we can say that acceleration of cart C is ZERO
so correct answer will be
B) Moving with zero acceleration.
B) The momentum before the collision is greater than the momentum after the collision.
C) The momentum before the collision is less than the momentum after the collision.
The car A has a mass of 1200 kg.
The car B has the mass of 1900 kg.
It is given that velocity of car A is given as 22 Km/hr
The car B has the velocity of 25 Km/hr.
Let the mass of two bodies are denoted as
Let the velocity of cars A and B are denoted as
The momentum before collision is-
[Here p stand for momentum.]
We are asked to calculate the final momentum of the system after collision.
The answer of the question is based law of conservation of linear momentum.
As per law of conservation of linear momentum the sum total linear momentum for an isolated system is always constant.Hence irrespective of the type of collision[elastic and inelastic],the momentum of the system is always constant which is a universal truth.
Let after the collision the velocity of A and B are
Hence the final momentum of the system is-
As per the law of conservation of linear momentum, the initial and final momentum must be equal i.e
Hence the option A is right.
Answer:
The altitude of the plane is 379.5 m.
Explanation:
Initial horizontal velocity, u = 59.1 m/s
Horizontal distance, d = 521 m
let the time taken by the packet to cover the distance is t.
Horizontal distance = horizontal velocity x time
521 = 59.1 x t
t = 8.8 s
let the vertical height is h .
Use second equation of motion in vertical direction.
The plane must be flying at an altitude of approximately 194.89 m above the pond.
To successfully drop the care package in the small lake, the plane must be flying at a certain altitude above the pond. We can use the horizontal distance and the ground speed of the plane to calculate the time it takes for the package to reach the target location. Then, using the time and the equation for free fall, we can find the altitude above the pond.
First, we calculate the time it takes for the package to reach the target location:
Next, we use the equation for free fall to find the altitude above the pond:
Therefore, the plane must be flying at an altitude of approximately 194.89 m above the pond in order to successfully accomplish this feat.
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A body revolving in circle generally has tangential acceleration if the speed is changing. Since the speed is uniform here, the tangential acceleration is zero.
centripetal acceleration is directed towards the center and is given as
a = v²/r where a = centripetal acceleration , v = speed , r = radius
Since both speed and radius are constant here, the centripetal acceleration is constant and is always directed towards the center.
hence the correct choice is
The acceleration is directed toward the center.