Double vision can be the result of

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Answer 1
Answer: cross eyed can result in double vision

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Nicolaus Copernicus was considered: a heretic because his theory disagreed with the church a hero because his theory agreed with current beliefs the "Father of Astronomy" because he believed the earth was the center of the solar system

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Answer:

A heretic because his beliefs disagreed with the church

Nicolaus Copernicus was considered the "Father of Astronomy" because he believed the earth was the center of the solar system. The rest of the choices do not answer the question above.

A clever engineer designs a "sprong" that obeys the force law fx =−q(x−xe)3, where xe is the equilibrium position of the end of the sprong and q is the sprong constant. for simplicity, we'll let xe =0m. then fx =−qx3.

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The unit of q is N/m³.While the potential energy of the compressed spring will be \rm U(x)= -(qx^4)/(4).

What is the potential energy of spring?

When a springdeviates from its mean position, it attempts to regain equilibrium by applying a force that is equivalent to but opposite to the external force.

Spring force has been used in bicycle carriers and launchingmechanisms, where the energy generated by disrupting the spring'sbalance is used as potential energy.

The given equation for the force law is;

\rm  f_x =-q(x-x_e)

Where,

\rm x_e is equilibrium position of the end of the spring

q is a spring constant

If at equilibriumposition;

\rm x_e=0

\rm F_X= -qx^3 \n\n \rm q = (F_x)/(x^3) \n\n

So the unit derived will be;

q = N/m³

The potential energy of the spring is found by;

\rm F_x=- (du)/(dx) \n\n U(x)= -\int\limits^x_0 {F(x)} \, dx \n\n  U(x)= -\int\limits^x_0 -qx^3 \, dx  \n\n U(x)=- (qx^4)/(4)

Hence the unit of q is N/m³.While the potentialenergy of the compressed spring will be\rm U(x)= -(qx^4)/(4).

To learn more about the potential energy of spring refer to the link;

brainly.com/question/2730954

The objective of this question is to compute the units of q and calculate the expression for the P.E of the compressed spring

Answer:

q = N/m³

\mathbf{U(x) = -(qx^4)/(4)}

Explanation:

Given that:

The equation for the force law is:

F_x = -q (x -x_e)^3

where;

x_ee = equilibrium position of the end of the spring

i.e. x_e = 0

q = is the spring constant

Also;

F_x = -qx^3

From above the units of q can be calculated by making q the subject of the formula :

q = (F_x)/(x^3)

where x is in meters and F is in Netwon;

Then :

q = N/m³

The Potential energy P.E of the compressed spring can be calculated by using the integral:

F_x = -(dU)/(dx)

U(x) = - \int F_x dx

U(x) = - \int ^x_0 (-qx^3)  \ dx

\mathbf{U(x) = -(qx^4)/(4)}

Little is known about much of earth’s early history because ____. a. precambrian rocks have been deeply buried
b. precambrian rocks have been changed by heat and pressure
c. precambrian soft-bodied life-forms weren’t often preserved as fossils
d. all of the above

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Little is known about much of earth’s early history because Precambrian rocks have been deeply buried they have been changed by heat and pressure ,Precambrian soft-bodied life-forms weren’t often preserved as fossils.

What is Precambrian rocks?

The Precambrian is the earliest part of Earth's history, set before the current Phanerozoic.

Why are Precambrian rocks rare?

Fossils are rare in Precambrian rocks mostly because Precambrian life-forms lacked bones, or other hard parts that commonly form fossils.

Hence, D is correct option

To learn more about Precambrian, here

https://brainly.in/question/26340735?

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the correct answer is D

During a race, a horse's speed increases from 65 m/s to 73 m/s during the last 5.0 seconds of that race What was the rate of acceleration during this time?

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During a race, a horse's speed increases from 65 m/s to 73 m/s during the last 5.0 seconds of that race, 1.60 m/s² was the rate of acceleration during this time.

What do you mean by an acceleration ?

The rate of change of velocity is defined as acceleration. Acceleration usually indicates that the speed is changing, but this is not always the case. When an object moves in a circular path at a constant speed, it is still accelerating because its velocity direction changes.

Acceleration occurs when the speed of an object increases or decreases, or when it changes direction. Acceleration, like velocity, has two types: average and instantaneous.

a = v - v₀ / t

Then, a = 73 × 65 / 5

a = 1.60 m/s²

Thus, 1.60 m/s² was the rate of acceleration during this time.

To learn more about an acceleration, follow the link;

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Answer:

1.6m/s²

Explanation:

It was difficult to type the answer here

What can be found in every skeletal muscle?

Answers

You can find muscle fibers, nerves, connective tissue, and blood vessels in every skeletal system. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

Answer:

D.  tendons, nerves, blood vessels, and bones

Explanation:

A metal object is suspended from a spring scale. The scale reads 930 N when the object is suspended in air, and 731 N when the object is completely submerged in water. Find the volume of the object. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m3 .

Answers

Answer:

The volume of the object = 0.0203 m³

Explanation:

From Archimedes principle,

Upthrust = lost in weight = amount of water displaced.

U = W₁ - W₂

Where U = upthrust, W₁ = Weight in air, W₂ = weight in water.

U = 930- 731

U = 199 N.

but mass of water displaced,

m = U/g where g = 9.8 m/s²

m = 199/9.8

m = 20.31 kg.

Recall,

Density = mass/volume.

Density of water = mass of water displaced/ volume of water displaced

D = m/V

V = m/D......................................... Equation 1

Where V = volume of water displaced, m = 20.31 kg, D = 1000 kg/m³

Substitute into equation 1

V = 20.31/1000

V = 0.0203 m³

the volume of water displaced = 0.0203 m³

Note: That when an object is immersed in water, the volume of water it displaced is equal to it's volume.

Hence, Volume of water displaced = volume of the object.

Hence the volume of the object = 0.0203 m³