Answer:
Light travels as a wave. But unlike sound waves or water waves, it does not need any matter or material to carry its energy along. This means that light can travel through a vacuum—a completely airless space. It speeds through the vacuum of space at 186,400 miles (300,000 km) per second.
Explanation:
Hope this helps :))
Answer:
(a) θ1 = 942.5rad, (b) θ2 = 13195 rad
Explanation:
(a) Given
ωo = 0 rad/s
ω = 3600rev/min = 3600×2(pi)/60 rad/s
ω = 377rad/s
t1 = 5s
θ1 = (ω + ωo)t/2
θ1 = (377 +0)×5/2
θ1 = 942.5 rads
(b) ωo = 377rad/s
ω = 0 rad/s
t2 = 70s
θ2 = (ω + ωo)t/2
θ2 = (377 +0)×70/2
θ2 = 13195 rad
Answer:
3.95 m
Explanation:
m = 1 kg, h = 100 m, k = 125 N/m
Let the spring is compressed by y.
Use the conservation of energy
potential energy of the mass is equal to the energy stored in the spring
m x g x h = 1/2 x ky^2
1 x 9.8 x 100 = 0.5 x 125 x y^2
y^2 = 15.68
y = 3.95 m
Answer:
Ionization potential of C⁺⁵ is 489.6 eV.
Wavelength of the transition from n=3 to n=2 is 1.83 x 10⁻⁸ m.
Explanation:
The ionization potential of hydrogen like atoms is given by the relation :
.....(1)
Here E is ionization potential, Z is atomic number and n is the principal quantum number which represents the state of the atom.
In this problem, the ionization potential of Carbon atom is to determine.
So, substitute 6 for Z and 1 for n in the equation (1).
E = 489.6 eV
The wavelength (λ) of the photon due to the transition of electrons in Hydrogen like atom is given by the relation :
......(2)
R is Rydberg constant, n₁ and n₂ are the transition states of the atom.
Substitute 6 for Z, 2 for n₁, 3 for n₂ and 1.09 x 10⁷ m⁻¹ for R in equation (2).
= 5.45 x 10⁷
λ = 1.83 x 10⁻⁸ m
Answer:
E = 1.76 J
Explanation:
Given that,
Mass of an object, m = 0.4 kg
It moves by a vertical distance of 0.45 m in the Earth's gravitational field.
We need to find the change in its gravitational potential energy. It can be given by the formula as follow :
So, the change in its gravitational potential energy is 1.76 J.
Answer:
with the current: 19.1 m/s eastern
against the current: 13.7 m/s western
Explanation:
The boat speed relative to ground is the sum of the boat speed relative to water + the water speed relative to ground.
Suppose eastern is positive, water speed due east is 2.7m/s.
When the boat is heading east, its speed relative to water is 16.4m/s, its speed relative to ground is 16.4 + 2.7 = 19.1 m/s eastern
When the boat is heading west, its speed relative to water is -16.4m/s, its speed relative to ground is -16.4 + 2.7 = -13.7 m/s western