The hormone glucagon is released by number of different tissues in the body to stabilize blood glucose levels. Which of the following pathways is least ikely to be activated by glucagon in hepatocytes? cells in the pancreas when blood sugar levels are low. It acts on a gluconeogenesis O glycogenolysis O ? oxidation glycolysis

Answers

Answer 1

Answer:

Answer:

Glycolysis

Explanation:

In human body, glucose levels are regulated by hormones insulin and glucagon, secreted from pancreas. Glucagon from alpha cells and insulin from beta cells of the pancreas. Glucagon are regulated along depending upon the blood sugar levels. During fasting when blood sugar levels are decreased the glucagon levels are increased. Glucagon increases hepatic glucose through glycogenelysis.

So, Glycolysis of glucagon is least likely to be activated by glucagon in hepatocytes

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A stock person at the local grocery store has a job consisting of the following five segments:1) picking up boxes of tomatoes from the stockroom floor2)accelerating to a comfortable speed.3) Carring the boxes to the tomato display at constant speed.4)decelerating to a stop.5) lowering the boxes slowly to the floor.During which of the five segments of the job does the stock person do positive work on the boxes?A) (2) and (3)B(1) and (2)C) (1) onlyD) (1), (2), (4) and (5)E) (1) and (5)

Enter your answer in the provided box. In water conservation, chemists spread a thin film of certain inert materials over the surface of water to cut down on the rate of evaporation of water in reservoirs. This technique was pioneered by Benjamin Franklin three centuries ago. Franklin found that 0.10 mL of oil could spread over the surface of water of about 32.0 m2 in area. Assuming that oil forms a monolayer (that is, a layer that is only one molecule thick) estimate the length of each oil molecule in nanometers. Assume that oil molecules are roughly cubic. (1 nm = 1 × 10−9 m)

Answers

Answer:

≅3.2 nm

Explanation:

Using the converter units as know for this case that:

1 ml is 1 cubic centimeter ⇒ 0.1 ml is 0.1 cubic centimeters

32.0 m² so :

32.0 m² *100 *100 cm² ⇒ 0.1 / ( 32.0 * 100 *100 ) = 100,000,000 * 0.1 / (32.0 * 100 * 100 ) nm

v = 100/32.0 nm = 3.125 nm thick.

v ≅3.2 nm

As oil is one molecule thick and the molecules are cubic, length of each oil is 3.2 nm

You have a small piece of iron at 75 °C and place it into a large container of water at 25 °C. Which of these best explains what will occur over time. A:The iron will cause the water to boil and turn to steam. B:The iron will take the heat from the water and get hotter. C:The water will cool significantly due to its colder temperature. D:Some heat from the iron will move to the water causing both to change temperatures.

Answers

D. Heat energy will be transferred within the system and if left long enough, there will be enough transferred energy to make both of them the same temperature.

D:Some heat from the iron will move to the water causing both to change temperatures.

If Jim could drive a Jetson's flying car at a constant speed of 490 km/hr across oceans and space, approximately how long (in millions of years, in 106 years) would he take to drive to a nearby star that is 4.5 light-years away? Use 9.461 × 1012 km/light-year and 8766 hours per year (365.25 days). unanswered

Answers

Answer:

109.5 million years

Explanation:

The question asked us to find the time.

Remember that

Rate of velocity = distance / time, and this,

time taken = distance/rate

Due to the confusing nature of the units, we would have to be converting them to a more uniform one.

1 km is equal to 9.461*10^12 km/light-year, that's if we try to convert km to light year.

Since the speed is in km, the distance has to be in km also, and therefore, we convert ly to km:

4.5 light-years = 9.461*10^12 km/light-year) = 42.57*10^13 km

We that this value as our distance, in km.

Also,

Time = distance/speed

Time = 45.57*10^13 km / 490 km/hr = 9.3*10^11 hr

Now the next step is to convert hours to years, using the conversion factor 8766 hr/yr.

time (in years) = 9.6*10^11 hr / 8766 hr/yr) = 10.95*10^7 years

the final step is to divide the time in years by 10^6 years/million years, which gives the final answer as the trip takes 109.5 million years.

Which wave diagram BEST represents a dim red sunset on the right side to the light from an intense ultraviolet bug light on the left side?

Answers

Diagram-A satisfies. High amplitude (bright) and long wavelengths are present on the left (red). & The right side has a short wavelength and low amplitude (dim) (violet).

What are light waves?

Light comes from a source as waves. Each wave has an electric and a magnetic component. Light is hence sometimes referred to as electromagneticradiation.

A large portion of the light in the universetravels with wavelengths that are too short or too long for the human eye to detect, yet our brains interpret light waves by giving distinct colours to the various wavelengths.

The infrared, microwave, and radio spectrum bands have the longest wavelengths. The ultraviolet, x-ray, and gammaradiation have the shortest wavelengths in the electromagnetic spectrum.

Diagram A is therefore satisfactory. On the left, there are long wavelengths with high amplitude (bright) (red). & The right side is dark and has a short wavelength (violet).

For more details regarding waves, visit:

brainly.com/question/29334933

#SPJ5

The wave that best represents it is c.

A 7600 kg satellite is in a circular orbit around Earth at a height of 2300 km above Earth's surface. What is this satellite's speed

Answers

Answer:

6779.7m/s

Explanation:

Using

GMm/(Re +h)² = mv²/ (Re+h)

So making v subject we have

V= √GM/Re+h

V = √ 6.67*10^-11 x 5.97*10^24/(6371+2300)*10^3

V= 6779.7m/s

Note h = height of satellite

Re= radius of the earth

M = mass of the earth

Find T1, the magnitude of the force of teTo practice Problem-Solving Strategy 11.1 Equilibrium of a Rigid Body. A horizontal uniform bar of mass 2.6 kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to the end of the bar, and string 2 is attached a distance 0.7 m from the other end. A monkey of mass 1.3 kg walks from one end of the bar to the other. Find the tension T1 in string 1 at the moment that the monkey is halfway between the ends of the bar.nsion in string 1, at the moment that the monkey is halfway between the ends of the bar. Express your answer in newtons using three significant figures. View Available Hint(s)