The expression for the bullet's speed vbullet is and the speed of a 9.0 g bullet is v=16.8 m/s
A bullet of mass m is fired into a block of mass m that is at rest. the block, with the bullet embedded, slides distance d across a horizontal surface. the coefficient of kinetic friction is μk.
The initial kinetic energy of the bullet is given by
where
m is the mass of the bullet
v is the initial speed of the bullet
The expression for the bullet's speed vbullet is
where
is the coefficient of kinetic friction
g is the acceleration of gravity
The work done by the force of friction is
where d is the displacement of the block+bullet.
Because the final kinetic energy is zero (the bullet with the block comes at rest), we can write:
And so
By solving for v, the solution for the bullet speed:
The speed of a 9.0 g bullet that, when fired into a 12 kg stationary wood block causes the block to slide 5.4 cm across a wood table. Assume that k=0.20.
We have:
the mass of the bullet, m = 9.0 g = 0.009 kg
the mass of the block, M = 12 kg
the distance covered by the block+bullet, d = 5.4 cm = 0.054 m
the coefficient of friction,
the acceleration of gravity,
By substituting, we got
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current 0.8 A?
Answer: 88
Explanation:
B) 14 J
C) 15 J
D) 17.5 J