PHYSICS HIGH SCHOOL

Which star makes up Orion's knee to your right, or the end of his tunic?A.
Polaris







B.
Sirius







C.
Betelgeuse







D.
Rigel

Answers

Answer 1
Answer:

Answer:

Betelgeuse and Rigel

Explanation:

100% correct

Related Questions

You are sitting in a chair on an elavator. The elavator accelerates downward, you and the chair land on the cround with the chair landing first and then you on the chair.Explain the Net Forces at 3 points for each objectThe points are: Before the Elevator Accelerates Downward, In Freefall, At ImpactAnalyze whether the Normal Force would need to increase, and where the direction of the net force is for each object.
An electron is released from rest at the negative plate of a parallel plate capacitor. The charge per unit area on each plate is = 2.5 x 10⁻⁷ C/m², and the plates are separated by a distance of 1.7 x 10⁻² m. How fast is the electron moving just before it reaches the positive plate?
as you are leaving a building, the door opens outward. if the hinges on the door are on your right, what is the direction of the angular velocity of the door as you open it?
Please help me solve
Imagine that a car is traveling from your left to your right at a constant velocity. Which two actions could the driver take that may be represented as (a) a velocity vector and an acceleration vector both pointing to the right and then (b) changing so the velocity vector points to the right and the acceleration vector points to the left?

A 1-kilogram coconut falls out of a tree from a height of 3 meters. Determine the coconut's kinetic energy.

Answers

You first would have to find the Gravitational Potential Energy of the coconut. This can be done by multiplying PE=mgh PE=(1)(9.81)(3) PE=29.43.
However, in order to find the KE of the coconut, you would need to specify on when in the coconuts fall you would like to know the KE.
For example, at the top of the tree, before it falls, the coconut has PE of 29.43J but KE of 0J. When the coconut is about to hit the ground, though, the coconut will have a KE of 29.43J and PE of 0J.
This is because of the Law of Conservation of Energy which states that energy is not created if destroyed.
In this system, PE is converted to KE and so at the end of the fall, the coconut has the same KE as the PE it had in the beginning.

The type of radiation that will penetrate farthest into a material isA. a beta ray.


B. a gamma ray.


C. an X-ray.


D. an alpha ray.


E. They all penetrate material the same distance

Answers

my answer is E.  If am wrong then plz tell me whats the right

An object with mass 60 kg moved in outer space. When it was at location < 13, -19, -3 > its speed was 3.5 m/s. A single constant force < 220, 320, -120 > N acted on the object while the object moved from location < 13, -19, -3 > m to location < 18, -11, -8 > m. Then a different single constant force < 150, 230, 220 > N acted on the object while the object moved from location < 18, -11, -8 > m to location < 22, -17, -3 > m. What is the speed of the object at this final location?final speed = m/s

Answers

The speed of the object at its' final location is; 38 m/s

What is work energy theorem?

For the first force, we are given;

Force; F₁ = 220i + 320j - 120k

Initial Position; r₁ = 13i - 19j - 3k

Final Position; r₂ = 18i - 11j - 8k

Thus; Displacement; Δr = r₂ - r₁

Δr = 18i - 11j - 8k - (13i - 19j - 3k)

Δr = 5i + 8j - 5k

From work energy theorem, we know that;

F₁ * Δr = ¹/₂m(v₂² - v₁²)

We are given v₁ = 2.5 m/s and m = 60 kg. Thus;

(220i + 320j - 120k) × (5i + 8j - 5k) = ¹/₂ * 60(v₂² - 3.5²)

4260/30 = v₂² - 3.5²

1420 = v₂² - 12.25

Solving gives v₂ = 37.85 m/s

For the second force, we are given;

Force; F₂ = 150i + 230j - 220k

Initial Position; r₁ = 18i - 11j - 8k

Final Position; r₂ = 22i - 17j - 3k

Thus; Displacement; Δr = r₂ - r₁

Δr = 22i - 17j - 3k - (18i - 11j - 8k)

Δr = 4i - 6j + 5k

From work energy theorem, we know that;

F₂ * Δr = ¹/₂m(v₂² - v₁²)

Now,  v₁ = 37.85 m/s and m = 60 kg. Thus;

(150i + 230j + 220k) × (4i - 6j + 5k) = ¹/₂ * 60(v₂² - 37.85²)

320/30 = v₂² - 37.85²

10.67 = v₂² - 1,432.6225

Solving gives v₂ = 38 m/s

Read more about Work Energy theorem at; brainly.com/question/14468674
Sigma F.dS = total work done = change in kinetic energy
(220, 320, -120).(18-13,-11+19,-8+3) +(150, 230, 220).(22-18,-17+11,-3+8)= 1/2 *60*(V^2- 3.5^2)

220*5+320*8+ -120*-5 + 150*4 + 230* 6 +220* -5= ..
simplify his

In 2000, NASA placed a satellite in orbit around an asteroid. Consider a spherical asteroid with a mass of 1.50×1016 kg and a radius of 9.00 km .What is the speed of a satellite orbiting 4.60 km above the surface?

Answers

Answer:

8.58 m/s.

Explanation:

Given,

Mass of the asteroid,M = 1.50 x 10¹⁶ Kg

radius = 9 Km

distance of the satellite, r = 4.60 Km

Speed of the satellite  = ?

R = 9 + 4.60 = 13.60 Km

Speed of the satellite rotating in orbit

v = \sqrt{(GM)/(R)}

G is gravitational constant

v = \sqrt{(6.67* 10^(-11)* 1.50* 10^(16))/(13.60* 10^3)}

v = 8.58 m/s

Speed of the satellite is equal to 8.58 m/s.

What are the three parts of a nucleotide

Answers

The building blocks of nucleic acids, nucleotides are composed of a nitrogenous base, a five-carbon sugar (ribose or deoxyribose), and at least one phosphate group.

Answer: an organic base, a phosphate group, and a sugar

Explanation:

An object weighs 60.0 kg on the surface of the earth. How much does it weigh 4R from the surface? (5R from the center)

Answers

"60 kg" is not a weight.  It's a mass, and it's always the same
no matter where the object goes.

The weight of the object is   

                                 (mass) x (gravity in the place where the object is) .

On the surface of the Earth,

                   Weight = (60 kg) x (9.8 m/s²)

                                =      588 Newtons.

Now, the force of gravity varies as the inverse of the square of the distance from the center of the Earth.
On the surface, the distance from the center of the Earth is 1R.
So if you move out to  5R  from the center, the gravity out there is

                    (1R/5R)²  =  (1/5)²  =  1/25  =  0.04 of its value on the surface.

The object's weight would also be 0.04 of its weight on the surface.

                 (0.04) x (588 Newtons)  =  23.52 Newtons.

Again, the object's mass is still 60 kg out there.
___________________________________________

If you have a textbook, or handout material, or a lesson DVD,
or a teacher, or an on-line unit, that says the object "weighs"
60 kilograms, then you should be raising a holy stink. 
You are being planted with sloppy, inaccurate, misleading
information, and it's going to be YOUR problem to UN-learn it later.
They owe you better material.

Answer:

23.5 N

Explanation:

Just wanted to clarify something about the verified answer: Our only given measurement—the mass of the object—has 3 significant digits, so we can only include 3 significant digits in our answer.

23.52 N is NOT the correct answer. Your answer should only have 3 significant digits.

I just did the quiz where this problem came from, so I know that 23.5 N is the correct answer.
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